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6 Accelerated
13
son 11 Practice
the specified set of integers, determine which, if any, make the equation true.

20-5w=10 w+5
255
Name
qquad
Date
qquad
Period
qquad

qquad

qquad

qquad

{-10,-4,-1,0,13,12}

3y+5=4y+15

$6$ Accelerated $\newline$ $13$ $\newline$ son $11$ Practice $\newline$ the specified set of integers, determine which, if any, make the equation true. $\newline$ $20-5 w=10 w+5$ $\newline$ $255$ $\newline$ Name $\qquad$ $\newline$ Date $\qquad$ $\newline$ Period $\qquad$ $\newline$ $\qquad$ $\newline$ $\qquad$ $\newline$ $\qquad$ $\newline$ $\{-10,-4,-1,0,13,12\}$ $\newline$ $3$ . $3 y+5=4 y+15$

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Factor sums and differences of cubes

Full solution

Q.

6

Accelerated

\newline

13

\newline

son

11

Practice

\newline

the specified set of integers, determine which, if any, make the equation true.

\newline

20-5 w=10 w+5

\newline

255

\newline

Name

\qquad

\newline

Date

\qquad

\newline

Period

\qquad

\newline

\qquad

\newline

\qquad

\newline

\qquad

\newline

\{-10,-4,-1,0,13,12\}

\newline

3

.

3 y+5=4 y+15

Simplify Equation: First, let's simplify the equation by moving all the terms involving $w$ to one side and the constant terms to the other side. $20 - 5w - 10w = 5$ Combine like terms. $20 - 15w = 5$
Combine Like Terms: Next, subtract $20$ from both sides to isolate the term with $w$ . $\newline$ $-15w = 5 - 20$ $\newline$ $-15w = -15$
Isolate Term with $w$ : Now, divide both sides by $-15$ to solve for $w$ . $w = \frac{-15}{-15}$ $w = 1$
Solve for $w$ : Check if $w = 1$ is in the set of integers given. $\newline$ The set is ${-10, -4, -1, 0, 13, 12}$ , and $1$ is not in the set.
Check Integer Set: Since $1$ is not in the set, none of the integers in the set make the equation true.

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