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$6=\frac{2}{7}(2x+28)$

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Add and subtract fractions

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Q.

6=\frac{2}{7}(2x+28)

Multiply by $7$ : First, let's get rid of the fraction by multiplying both sides by $7$ . $7 \times 6 = \left(\frac{2}{7}\right) \times 7 \times (2x + 28)$
Simplify both sides: Now, simplify both sides. $\newline$ $42 = 2 \times (2x + 28)$
Distribute on right side: Next, distribute the $2$ on the right side. $42 = 4x + 56$
Subtract $56$ : Then, subtract $56$ from both sides to isolate the term with $x$ . $\newline$ $42 - 56 = 4x$
Calculate left side: Now, calculate the left side. $-14 = 4x$
Divide by $4$ : Finally, divide both sides by $4$ to solve for x. $\newline$ $-\frac{14}{4} = x$
Simplify division: Simplify the division to find the value of $x$ . $x = -3.5$

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