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Math Problems
Grade 7
Add and subtract fractions
x
+
15
=
25
x+15=25
x
+
15
=
25
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At Maya's Vacation Wear,
3
8
\frac{3}{8}
8
3
of the garments are bikinis and
3
8
\frac{3}{8}
8
3
are trunks. What fraction of the garments are either bikinis or trunks?
\newline
Write your answer as a fraction or as a whole or mixed number.
\newline
_
_
_
_
_
\_\_\_\_\_
_____
of the garments
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Santiago found two worms in the yard and measured them with a ruler. One worm was
4
5
\frac{4}{5}
5
4
of an inch long. The other worm was
3
5
\frac{3}{5}
5
3
of an inch long. How much longer was the longer worm?
\newline
Write your answer as a fraction or as a whole or mixed number.
\newline
_
_
_
\_\_\_
___
inches
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Add.
\newline
2
5
+
2
5
=
\frac{2}{5} + \frac{2}{5} =
5
2
+
5
2
=
_____
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Add.
\newline
1
5
+
1
5
=
\frac{1}{5} + \frac{1}{5} =
5
1
+
5
1
=
_____
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Add.
\newline
4
5
+
2
5
=
\frac{4}{5} + \frac{2}{5} =
5
4
+
5
2
=
_____
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Subtract.
\newline
2
5
−
1
5
=
\frac{2}{5} - \frac{1}{5} =
5
2
−
5
1
=
_____
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Subtract.
\newline
9
10
−
2
5
=
\frac{9}{10} - \frac{2}{5} =
10
9
−
5
2
=
_____
Get tutor help
Add.
\newline
1
10
+
4
5
=
\frac{1}{10} + \frac{4}{5} =
10
1
+
5
4
=
_____
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Add.
\newline
3
10
+
3
10
=
\frac{3}{10} + \frac{3}{10} =
10
3
+
10
3
=
_____
Get tutor help
Subtract.
\newline
1
10
−
4
5
=
\frac{1}{10} - \frac{4}{5} =
10
1
−
5
4
=
_____
Get tutor help
Subtract.
\newline
4
5
−
1
5
=
\frac{4}{5} - \frac{1}{5} =
5
4
−
5
1
=
_____
Get tutor help
Add.
\newline
4
5
+
4
5
=
\frac{4}{5} + \frac{4}{5} =
5
4
+
5
4
=
_____
Get tutor help
Subtract.
\newline
3
4
−
1
4
=
\frac{3}{4} - \frac{1}{4} =
4
3
−
4
1
=
_____
Get tutor help
Subtract.
\newline
3
10
−
4
5
=
\frac{3}{10} - \frac{4}{5} =
10
3
−
5
4
=
_____
Get tutor help
Subtract.
\newline
1
5
−
4
5
=
\frac{1}{5} - \frac{4}{5} =
5
1
−
5
4
=
_____
Get tutor help
Add.
\newline
1
10
+
2
5
=
\frac{1}{10} + \frac{2}{5} =
10
1
+
5
2
=
_____
Get tutor help
Add.
\newline
3
4
+
1
4
=
\frac{3}{4} + \frac{1}{4} =
4
3
+
4
1
=
_____
Get tutor help
Add.
\newline
1
4
+
3
4
=
\frac{1}{4} + \frac{3}{4} =
4
1
+
4
3
=
_____
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3
x
+
4
=
0
3x+4=0
3
x
+
4
=
0
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4
x
+
3
=
17
4 x+3=17
4
x
+
3
=
17
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8
p
−
4
=
20
8p-4=20
8
p
−
4
=
20
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Solve for
k
:
k
+
22
=
29
k: k+22=29
k
:
k
+
22
=
29
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30
÷
2
×
4
−
35
30 \div 2 \times 4 - 35
30
÷
2
×
4
−
35
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P
+
6
=
5
P+6=5
P
+
6
=
5
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What value of
x
x
x
makes the equation below true?
\newline
x
+
12
=
20
x+12=20
x
+
12
=
20
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5
X
+
−
3
=
12
5X+ -3= 12
5
X
+
−
3
=
12
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5
x
+
−
3
=
12
5x+-3=12
5
x
+
−
3
=
12
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6
=
2
7
(
2
x
+
28
)
6=\frac{2}{7}(2x+28)
6
=
7
2
(
2
x
+
28
)
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2
x
+
5
=
9
2x+5=9
2
x
+
5
=
9
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4
+
3
=
7
4+3=7
4
+
3
=
7
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a
+
b
=
21
a+b=21
a
+
b
=
21
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ext{-}
9
9
9
+
2
2
2
=
56
56
56
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b
−
8
=
9
b-8=9
b
−
8
=
9
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7
x
−
9
=
13
7 x-9=13
7
x
−
9
=
13
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2
x
7
+
2
=
12
\frac{2 x}{7}+2=12
7
2
x
+
2
=
12
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(ii) Subtraction:
5
−
2
=
3
5-2=3
5
−
2
=
3
\newline
5
5
5
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x
−
9
=
10
x-9=10
x
−
9
=
10
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2
2
2
divided
5
6
\frac{5}{6}
6
5
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rac{
5
5
5
}{
8
8
8
} -
1
1
1
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x
+
6
=
10
x+6=10
x
+
6
=
10
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25
5
+
4
2
=
?
\frac{25}{5} + \frac{4}{2}= ?
5
25
+
2
4
=
?
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Ashley spent
30
%
30 \%
30%
of her money and an additional
$
68
\$ 68
$68
on a concert ticket. She then spent
25
%
25 \%
25%
of the remaining money and an additional
$
24
\$ 24
$24
on a dress. If she had
$
282
\$ 282
$282
left, how much money did she have at first?
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7
x
+
4
=
11
7 x+4=11
7
x
+
4
=
11
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11
5
+
41
8
\frac{11}{5} +\frac{41}{8}
5
11
+
8
41
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2
x
−
5
=
10
2x-5=10
2
x
−
5
=
10
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subtract
5
7
\frac{5}{7}
7
5
from
4
4
4
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2
x
+
1
=
5
2x + 1 = 5
2
x
+
1
=
5
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6
+
5
=
?
6+5=?
6
+
5
=
?
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8
=
−
6
(
a
+
2
)
8=-6(a+2)
8
=
−
6
(
a
+
2
)
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1
2
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