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6×10^(6)=(24 kN(d//2))/(4.17d^(3)+4688d^(2)-703,125 d+3.51 ×10^(-6))

6×106=24kN(d/2)4.17d3+4688d2−703,125d+3.51×10−6 6 \times 10^{6}=\frac{24 k N(d / 2)}{4.17 d^{3}+4688 d^{2}-703,125 d+3.51 \times 10^{-6}}

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Full solution

Q. 6×106=24kN(d/2)4.17d3+4688d2−703,125d+3.51×10−6 6 \times 10^{6}=\frac{24 k N(d / 2)}{4.17 d^{3}+4688 d^{2}-703,125 d+3.51 \times 10^{-6}}
  1. Rewrite Equation: Rewrite the equation to isolate the fraction on one side.\newline6×106=24kN(d/2)4.17d3+4688d2−703,125d+3.51×10−66\times10^6 = \frac{24 \text{kN}(d/2)}{4.17d^3 + 4688d^2 - 703,125d + 3.51 \times10^{-6}}
  2. Remove Fraction: Multiply both sides by the denominator to remove the fraction.\newline(6×106)(4.17d3+4688d2−703,125d+3.51×10−6)=24kN(d/2)(6\times10^6)(4.17d^3 + 4688d^2 - 703,125d + 3.51 \times10^{-6}) = 24 \text{kN}(d/2)
  3. Simplify Equation: Divide both sides by 6×1066\times10^6 to simplify.\newline4.17d3+4688d2−703,125d+3.51×10−6=24kN(d/2)6×1064.17d^3 + 4688d^2 - 703,125d + 3.51 \times10^{-6} = \frac{24 kN(d/2)}{6\times10^6}
  4. Convert kN to N: Simplify the right side of the equation.\newline4.17d3+4688d2−703,125d+3.51×10−6=24 kN(d/2)/(6×106)4.17d^3 + 4688d^2 - 703,125d + 3.51 \times 10^{-6} = 24 \text{ kN}(d/2)/(6\times10^6)\newline4.17d3+4688d2−703,125d+3.51×10−6=2 kN(d)/(106)4.17d^3 + 4688d^2 - 703,125d + 3.51 \times 10^{-6} = 2 \text{ kN}(d)/(10^6)
  5. Cancel Powers of 1010: Convert kN to N by multiplying by 10001000. 4.17d3+4688d2−703,125d+3.51×10−6=2(1000N)(d)/(106)4.17d^3 + 4688d^2 - 703,125d + 3.51 \times 10^{-6} = 2(1000N)(d)/(10^6)
  6. Final Simplified Equation: Simplify the equation by canceling out the powers of 1010.4.17d3+4688d2−703,125d+3.51×10−6=2N(d)4.17d^3 + 4688d^2 - 703,125d + 3.51 \times 10^{-6} = 2N(d)

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