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5b. Suppose the universal set is 
xi={0,1,2,3,4,5,6,7,8}.
i. Write in enumerated form the set that is represented by the bit string 011011001 .
ii. If 
A is represented 
y the bit string 110101110 and 
B is represented by the bit string 101011000, write the sets AUB and A as bit strings.

55b. Suppose the universal set is ξ={0,1,2,3,4,5,6,7,8} \xi=\{0,1,2,3,4,5,6,7,8\} .\newlinei. Write in enumerated form the set that is represented by the bit string 011011001011011001 .\newlineii. If A A is represented y y the bit string 110101110110101110 and B B is represented by the bit string 101011000101011000, write the sets AUB and A as bit strings.

Full solution

Q. 55b. Suppose the universal set is ξ={0,1,2,3,4,5,6,7,8} \xi=\{0,1,2,3,4,5,6,7,8\} .\newlinei. Write in enumerated form the set that is represented by the bit string 011011001011011001 .\newlineii. If A A is represented y y the bit string 110101110110101110 and B B is represented by the bit string 101011000101011000, write the sets AUB and A as bit strings.
  1. Convert to Set: To solve the first part of the problem, we need to convert the bit string 011011001011011001 into a set by matching each bit to the corresponding element in the universal set xi={0,1,2,3,4,5,6,7,8}x_i=\{0,1,2,3,4,5,6,7,8\}. A '11' in the bit string means the element is included in the set, while a '00' means it is not included.
  2. Enumerate Set: Enumerate the set represented by the bit string 011011001011011001. Starting from the left, the first bit is 00, so 00 is not included. The second bit is 11, so 11 is included, and so on. The resulting set is \{1,2,4,5,71,2,4,5,7\}.
  3. Find Union: To solve the second part of the problem, we need to find the union of sets AA and BB, represented by their respective bit strings. The union of two sets includes all elements that are in either set. In terms of bit strings, we perform a logical OR\text{OR} operation on each pair of corresponding bits.
  4. Perform OR Operation: Perform the logical OR operation on the bit strings for AA (110101110110101110) and BB (101011000101011000). The result is 111111110111111110, as each pair of bits has at least one '11' except for the last pair.
  5. Resulting Set: The set ABA\cup B represented by the bit string 111111110111111110 is \{00,11,22,33,44,55,66,77\}, as all bits except the last one are '11'.
  6. Given Set: The set AA is already given by the bit string 110101110110101110, so no further calculation is needed for this part.

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