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57x^(2)+(57 b+a)x+ab=0
In the given equation, 
a and 
b are positive constants. The product of the solutions to the given equation is 
kab, where 
k is a constant. What is the value of 
k ?
A. 
(1)/(57)
B. 
(1)/(19)
C. 1
D. 57

57x2+(57b+a)x+ab=0 57 x^{2}+(57 b+a) x+a b=0 \newlineIn the given equation, a a and b b are positive constants. The product of the solutions to the given equation is kab k a b , where k k is a constant. What is the value of k k ?\newlineA. 157 \frac{1}{57} \newlineB. 119 \frac{1}{19} \newlineC. 11\newlineD. 5757

Full solution

Q. 57x2+(57b+a)x+ab=0 57 x^{2}+(57 b+a) x+a b=0 \newlineIn the given equation, a a and b b are positive constants. The product of the solutions to the given equation is kab k a b , where k k is a constant. What is the value of k k ?\newlineA. 157 \frac{1}{57} \newlineB. 119 \frac{1}{19} \newlineC. 11\newlineD. 5757
  1. Identify Form: Identify the form of the quadratic equation and relate it to the standard form ax2+bx+c=0ax^2 + bx + c = 0.
  2. Use Vieta's Formulas: Use Vieta's formulas, which relate the coefficients of a polynomial to sums and products of its roots. For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the product of the roots is given by ca\frac{c}{a}.
  3. Compare Roots Product: Compare the product of the roots to the given form kabkab.
  4. Solve for kk: Solve for kk.
  5. Match Value of kk: Match the value of kk with the provided options.

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