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453-vdots=-76=-23

4537623 \begin{array}{r}453 \\ \vdots \\ \hline-76 \\ \hline-23\end{array}

Full solution

Q. 4537623 \begin{array}{r}453 \\ \vdots \\ \hline-76 \\ \hline-23\end{array}
  1. Isolate variable vv: First, let's isolate the variable vv by adding vv to both sides of the equation.\newline453v+v=76+v453 - v + v = -76 + v\newlineThis simplifies to:\newline453=76+v453 = -76 + v
  2. Get vv by itself: Next, we need to get vv by itself on one side, so we'll subtract 453453 from both sides.\newline76+v453=76453-76 + v - 453 = -76 - 453\newlineThis gives us:\newlinev=76453v = -76 - 453
  3. Subtraction to find vv: Now, we just do the subtraction.v=529v = -529