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43% of the respondents stated that they talk to their pets on the A veterinarian believed this result to be too high, so she randomly 50 pet owners and discovered that 104 of them spoke to their pet phone. Does the veterinarian have a right to be skeptical? Use the lof significance.

P_(0)(1-P_(0))=◻quad grad10, the sample size is
◻
5% of tion size, and the sample the requirements for testing hesis
◻ satisfied. one decimal place as needed.)

$43 \%$ of the respondents stated that they talk to their pets on the A veterinarian believed this result to be too high, so she randomly $50$ pet owners and discovered that $104$ of them spoke to their pet phone. Does the veterinarian have a right to be skeptical? Use the lof significance. $\newline$ P_{0}\left(1-P_{0}\right)=\square \quad \(\newlineabla 10 \), the sample size is $\square$ $5 \%$ of tion size, and the sample the requirements for testing hesis $\square$ satisfied. one decimal place as needed.)

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Interpret measures of center and variability

Full solution

Q.

43 \%

of the respondents stated that they talk to their pets on the A veterinarian believed this result to be too high, so she randomly

50

pet owners and discovered that

104

of them spoke to their pet phone. Does the veterinarian have a right to be skeptical? Use the lof significance.

\newline

P_{0}\left(1-P_{0}\right)=\square \quad \(\newlineabla 10 \), the sample size is

\square

5 \%

of tion size, and the sample the requirements for testing hesis

\square

satisfied. one decimal place as needed.)

Understand the problem: Understand the problem and the data provided. $\newline$ The veterinarian questions if $43\%$ of pet owners talk to their pets on the phone. She surveyed $50$ pet owners and found that $104$ spoke to their pets on the phone, which seems incorrect because $104$ is greater than $50$ .

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