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2x(x-3)=x^(2)-9

2x(x−3)=x2−9 2 x(x-3)=x^{2}-9

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Composition of linear and quadratic functions: find a valueright chevron icon

Full solution

Q. 2x(x−3)=x2−9 2 x(x-3)=x^{2}-9
  1. Distribute 2x2x: First, let's distribute the 2x2x across the (x−3)(x-3).\newline2x×x−2x×3=x2−92x \times x - 2x \times 3 = x^2 - 9\newline2x2−6x=x2−92x^2 - 6x = x^2 - 9
  2. Move terms, set to zero: Now, let's move all terms to one side to set the equation to zero.\newline2x2−6x−x2+9=02x^2 - 6x - x^2 + 9 = 0\newlinex2−6x+9=0x^2 - 6x + 9 = 0
  3. Factor quadratic equation: We can factor the quadratic equation. \newline(x−3)(x−3)=0(x - 3)(x - 3) = 0\newlinex−3=0x - 3 = 0 or x−3=0x - 3 = 0
  4. Solve for x: Solve for x in both equations. x=3x = 3 or x=3x = 3

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