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2x+37 OR 2x+9>112x+3\geq 7 \quad \maroonC{\text{ OR }} \quad 2x+9>11

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Q. 2x+37 OR 2x+9>112x+3\geq 7 \quad \maroonC{\text{ OR }} \quad 2x+9>11
  1. Solve Inequality 11: First, let's solve the inequality 2x+372x + 3 \geq 7.\newlineSubtract 33 from both sides to isolate the term with xx.\newline2x+33732x + 3 - 3 \geq 7 - 3\newline2x42x \geq 4
  2. Isolate x Term: Now, divide both sides by 22 to solve for xx.2x242\frac{2x}{2} \geq \frac{4}{2}x2x \geq 2
  3. Divide by 22: Next, let's solve the inequality 2x+9>112x + 9 > 11. Subtract 99 from both sides to isolate the term with xx. 2x+99>1192x + 9 - 9 > 11 - 9 2x>22x > 2
  4. Solve Inequality 22: Divide both sides by 22 to solve for xx.2x2>22\frac{2x}{2} > \frac{2}{2}x>1x > 1
  5. Isolate x Term: Now we have two inequalities: x2x \geq 2 or x>1x > 1. Since x>1x > 1 is less restrictive than x2x \geq 2, the solution set is determined by the inequality x2x \geq 2.

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