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2pi1*1+(e^(-1))/(2)=

2π1⋅1+e−12= 2 \pi 1 \cdot 1+\frac{e^{-1}}{2}=

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Full solution

Q. 2π1⋅1+e−12= 2 \pi 1 \cdot 1+\frac{e^{-1}}{2}=
  1. Identify Components: Identify the components of the expression.\newline2π1×12\pi1 \times 1 means 2×π×12 \times \pi \times 1, which is just 2π2\pi.\newlinee(−1)e^{(-1)} is the exponential function raised to the power of −1-1.\newlineThe expression also includes a division by 22.
  2. Calculate First Part: Calculate the first part of the expression: 2π1∗12\pi1*1. 2π1∗1=2×π×1=2π2\pi1*1 = 2 \times \pi \times 1 = 2\pi.
  3. Calculate Second Part: Calculate the second part of the expression: (e−1)/(2)(e^{-1})/(2). First, find e−1e^{-1}, which is approximately 0.36790.3679. Then divide by 22 to get (e−1)/(2)≈0.3679/2≈0.18395(e^{-1})/(2) \approx 0.3679/2 \approx 0.18395.
  4. Add Parts Together: Add the two parts together.\newline2π+0.18395≈2×3.14159+0.18395≈6.28318+0.18395≈6.46713.2\pi + 0.18395 \approx 2 \times 3.14159 + 0.18395 \approx 6.28318 + 0.18395 \approx 6.46713.

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