Resources
Testimonials
Plans
Sign in
Sign up
Resources
Testimonials
Plans
Home
Math Problems
Grade 8
Powers with negative bases
−
15
×
(
−
14
)
=
-15 \times(-14)=
−
15
×
(
−
14
)
=
Get tutor help
2
x
×
4
x
−
5
2
2\sqrt{x}\times 4x -\frac{5}{2}
2
x
×
4
x
−
2
5
Get tutor help
2
+
(
8
+
4
4
)
=
2+\left(8+4^{4}\right)=
2
+
(
8
+
4
4
)
=
Get tutor help
2
÷
(
8
+
4
2
)
=
2\div(8+4^{2})=
2
÷
(
8
+
4
2
)
=
Get tutor help
3
4
−
1
2
=
\frac{3}{4}-\frac{1}{2}=
4
3
−
2
1
=
Get tutor help
−
1
⋅
(
1
+
x
2
+
1
y
)
=
-1 \cdot\left(1+\frac{x^{2}+1}{y}\right)=
−
1
⋅
(
1
+
y
x
2
+
1
)
=
Get tutor help
2
π
1
⋅
1
+
e
−
1
2
=
2 \pi 1 \cdot 1+\frac{e^{-1}}{2}=
2
π
1
⋅
1
+
2
e
−
1
=
Get tutor help
x
2
+
8
x
+
15
=
x^{2}+8 x+15=
x
2
+
8
x
+
15
=
Get tutor help
(
8
+
10
)
⋅
3
2
=
(8+10) \cdot 3^{2}=
(
8
+
10
)
⋅
3
2
=
Get tutor help
Evaluate.
\newline
−
6
×
(
−
1
)
=
-6 \times(-1)=
−
6
×
(
−
1
)
=
Get tutor help
Evaluate.
\newline
−
2
×
(
−
6
)
=
-2 \times(-6)=
−
2
×
(
−
6
)
=
Get tutor help
−
1
5
6
÷
(
−
3
1
3
)
=
-1 \frac{5}{6} \div\left(-3 \frac{1}{3}\right)=
−
1
6
5
÷
(
−
3
3
1
)
=
Get tutor help
−
1
2
÷
(
−
1
3
8
)
=
-\frac{1}{2} \div\left(-1 \frac{3}{8}\right)=
−
2
1
÷
(
−
1
8
3
)
=
Get tutor help
2
−
3
÷
(
−
1
2
7
)
=
\frac{2}{-3} \div\left(-1 \frac{2}{7}\right)=
−
3
2
÷
(
−
1
7
2
)
=
Get tutor help
−
5
7
÷
(
−
1
1
8
)
=
\frac{-5}{7} \div\left(-1 \frac{1}{8}\right)=
7
−
5
÷
(
−
1
8
1
)
=
Get tutor help
−
2
1
4
÷
(
−
3
1
3
)
=
-2 \frac{1}{4} \div\left(-3 \frac{1}{3}\right)=
−
2
4
1
÷
(
−
3
3
1
)
=
Get tutor help
2
1
3
÷
(
−
3
2
3
)
=
2 \frac{1}{3} \div\left(-3 \frac{2}{3}\right)=
2
3
1
÷
(
−
3
3
2
)
=
Get tutor help
4
1
2
÷
(
−
1
3
7
)
=
4 \frac{1}{2} \div\left(-1 \frac{3}{7}\right)=
4
2
1
÷
(
−
1
7
3
)
=
Get tutor help
−
4
7
÷
1
3
4
=
\frac{-4}{7} \div 1 \frac{3}{4}=
7
−
4
÷
1
4
3
=
Get tutor help
3
−
4
÷
(
−
2
1
3
)
=
\frac{3}{-4} \div\left(-2 \frac{1}{3}\right)=
−
4
3
÷
(
−
2
3
1
)
=
Get tutor help
−
3
1
2
÷
−
5
8
=
-3 \frac{1}{2} \div \frac{-5}{8}=
−
3
2
1
÷
8
−
5
=
Get tutor help
−
1
3
5
÷
5
−
6
=
-1 \frac{3}{5} \div \frac{5}{-6}=
−
1
5
3
÷
−
6
5
=
Get tutor help
2
1
5
÷
4
−
9
=
2 \frac{1}{5} \div \frac{4}{-9}=
2
5
1
÷
−
9
4
=
Get tutor help
−
3
1
2
÷
(
−
1
2
5
)
=
-3 \frac{1}{2} \div\left(-1 \frac{2}{5}\right)=
−
3
2
1
÷
(
−
1
5
2
)
=
Get tutor help
−
2
1
5
÷
−
3
7
=
-2 \frac{1}{5} \div \frac{-3}{7}=
−
2
5
1
÷
7
−
3
=
Get tutor help
−
2
3
4
÷
5
−
9
=
-2 \frac{3}{4} \div \frac{5}{-9}=
−
2
4
3
÷
−
9
5
=
Get tutor help
1
1
8
÷
(
−
3
7
)
=
1 \frac{1}{8} \div\left(-\frac{3}{7}\right)=
1
8
1
÷
(
−
7
3
)
=
Get tutor help
6
×
(
3
+
2
)
=
6 \times(3+2)=
6
×
(
3
+
2
)
=
Get tutor help
4
2
/
4
(
4
)
+
4
4^2/4(4)+4
4
2
/4
(
4
)
+
4
Get tutor help
3
3
3
)
4
6
+
1
3
=
\frac{4}{6}+\frac{1}{3}=
6
4
+
3
1
=
Get tutor help
a
=
3
2
+
3
2
=
a=3^{2}+3^{2}=
a
=
3
2
+
3
2
=
Get tutor help
[
−
1
2
−
2
3
]
−
[
1
2
3
−
3
]
=
\left[\begin{array}{cc}-1 & 2 \\ -2 & 3\end{array}\right]-\left[\begin{array}{cc}1 & 2 \\ 3 & -3\end{array}\right]=
[
−
1
−
2
2
3
]
−
[
1
3
2
−
3
]
=
Get tutor help
6
×
(
7
−
2
)
=
6 \times(7-2)=
6
×
(
7
−
2
)
=
Get tutor help
15
−
3
2
+
4
=
15-3^{2}+4=
15
−
3
2
+
4
=
Get tutor help
(iii)
(
−
75
)
+
18
=
(-75)+18=
(
−
75
)
+
18
=
Get tutor help
Q
5
−
3
5-3
5
−
3
Get tutor help
2
x
3
2x^3
2
x
3
squared
−
1
=
- 1 =
−
1
=
Get tutor help
1
2
=
e
−
2
x
\frac{1}{2} = e^{-\frac{2}{x}}
2
1
=
e
−
x
2
Get tutor help
2
2
2
. Evaluate.
\newline
7
÷
3
4
=
7 \div \frac{3}{4}=
7
÷
4
3
=
Get tutor help
2
+
3
=
2+3=
2
+
3
=
Get tutor help
y
=
−
2
(
0
−
4
)
2
−
3
y=-2(0-4)^2-3
y
=
−
2
(
0
−
4
)
2
−
3
Get tutor help
1
4
(
2
3
+
4
2
)
=
\dfrac{1}{4}(2^3+4^2) =
4
1
(
2
3
+
4
2
)
=
Get tutor help
(
1
5
)
−
3
=
\left(\frac{1}{5}\right)^{-3}=
(
5
1
)
−
3
=
Get tutor help
6
−
3
=
6^{-3}=
6
−
3
=
Get tutor help
(
1
+
2
)
2
=
(1+2)^2=
(
1
+
2
)
2
=
Get tutor help
Evaluate. Write your answer as a whole number or as a simplified fraction.
\newline
2
9
2
5
=
\frac{2^{9}}{2^{5}}=
2
5
2
9
=
Get tutor help
Solve for all values of
x
x
x
.
\newline
x
9
=
9
x
\frac{x}{9}=\frac{9}{x}
9
x
=
x
9
\newline
Answer:
x
=
x=
x
=
Get tutor help
Factor completely:
\newline
(
x
−
9
)
(
3
x
+
5
)
+
(
4
x
+
9
)
(
3
x
+
5
)
2
(x-9)(3 x+5)+(4 x+9)(3 x+5)^{2}
(
x
−
9
)
(
3
x
+
5
)
+
(
4
x
+
9
)
(
3
x
+
5
)
2
\newline
Answer:
Get tutor help
Factor completely:
\newline
(
2
x
+
3
)
(
4
x
+
9
)
+
(
5
x
+
4
)
(
4
x
+
9
)
(2 x+3)(4 x+9)+(5 x+4)(4 x+9)
(
2
x
+
3
)
(
4
x
+
9
)
+
(
5
x
+
4
)
(
4
x
+
9
)
\newline
Answer:
Get tutor help
Factor completely:
\newline
(
x
+
9
)
(
3
x
−
1
)
−
(
x
+
9
)
2
(
2
x
+
3
)
(x+9)(3 x-1)-(x+9)^{2}(2 x+3)
(
x
+
9
)
(
3
x
−
1
)
−
(
x
+
9
)
2
(
2
x
+
3
)
\newline
Answer:
Get tutor help
1
2
3
...
4
Next