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Math Problems
Grade 8
Powers with negative bases
Evaluate.
\newline
(
−
1
)
3
=
(-1)^{3}=
(
−
1
)
3
=
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Evaluate.
\newline
(
−
2
5
)
2
=
\left(-\frac{2}{5}\right)^{2}=
(
−
5
2
)
2
=
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Evaluate.
\newline
(
−
10
)
2
=
(-10)^{2}=
(
−
10
)
2
=
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Evaluate.
\newline
(
−
2
)
3
=
(-2)^{3}=
(
−
2
)
3
=
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Evaluate.
\newline
(
−
1
4
)
2
=
\left(-\frac{1}{4}\right)^{2}=
(
−
4
1
)
2
=
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Evaluate.
\newline
−
1
1
2
=
-11^{2}=
−
1
1
2
=
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Evaluate.
\newline
(
−
4
5
)
2
=
\left(-\frac{4}{5}\right)^{2}=
(
−
5
4
)
2
=
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Evaluate.
\newline
(
−
4
3
)
3
=
\left(-\frac{4}{3}\right)^{3}=
(
−
3
4
)
3
=
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Evaluate.
\newline
−
9
2
=
-9^{2}=
−
9
2
=
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Evaluate.
\newline
−
3
3
=
-3^{3}=
−
3
3
=
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Evaluate.
\newline
−
2
3
=
-2^{3}=
−
2
3
=
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Evaluate.
\newline
−
2
5
=
-2^{5}=
−
2
5
=
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Evaluate.
\newline
−
7
2
=
-7^{2}=
−
7
2
=
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Evaluate.
\newline
−
1
5
=
-1^{5}=
−
1
5
=
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Evaluate.
\newline
(
−
3
)
4
=
(-3)^{4}=
(
−
3
)
4
=
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Evaluate.
\newline
(
−
3
1
2
)
2
=
\left(-3 \frac{1}{2}\right)^{2}=
(
−
3
2
1
)
2
=
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Evaluate.
\newline
(
−
2
2
5
)
2
=
\left(-2 \frac{2}{5}\right)^{2}=
(
−
2
5
2
)
2
=
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Evaluate.
\newline
(
−
2
2
3
)
2
=
\left(-2 \frac{2}{3}\right)^{2}=
(
−
2
3
2
)
2
=
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Evaluate.
\newline
(
−
1
)
5
=
(-1)^{5}=
(
−
1
)
5
=
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Evaluate.
\newline
(
−
1
)
2
=
(-1)^{2}=
(
−
1
)
2
=
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Evaluate.
\newline
(
−
5
2
)
2
=
\left(-\frac{5}{2}\right)^{2}=
(
−
2
5
)
2
=
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Evaluate.
\newline
(
−
3
2
)
4
=
\left(-\frac{3}{2}\right)^{4}=
(
−
2
3
)
4
=
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Evaluate.
\newline
(
−
3
4
)
2
=
\left(-\frac{3}{4}\right)^{2}=
(
−
4
3
)
2
=
Get tutor help
Evaluate.
\newline
(
−
5
3
)
2
=
\left(-\frac{5}{3}\right)^{2}=
(
−
3
5
)
2
=
Get tutor help
Evaluate.
\newline
(
−
1
2
)
5
=
\left(-\frac{1}{2}\right)^{5}=
(
−
2
1
)
5
=
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Evaluate.
\newline
(
−
3
4
)
3
=
\left(-\frac{3}{4}\right)^{3}=
(
−
4
3
)
3
=
Get tutor help
Evaluate.
\newline
(
−
3
1
3
)
2
=
\left(-3 \frac{1}{3}\right)^{2}=
(
−
3
3
1
)
2
=
Get tutor help
Evaluate.
\newline
(
−
1
3
)
3
=
\left(-\frac{1}{3}\right)^{3}=
(
−
3
1
)
3
=
Get tutor help
Evaluate.
\newline
(
−
4
1
2
)
2
=
\left(-4 \frac{1}{2}\right)^{2}=
(
−
4
2
1
)
2
=
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Evaluate.
\newline
−
2
2
=
-2^{2}=
−
2
2
=
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Evaluate.
\newline
−
4
3
=
-4^{3}=
−
4
3
=
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Evaluate.
\newline
(
−
2
1
2
)
2
=
\left(-2 \frac{1}{2}\right)^{2}=
(
−
2
2
1
)
2
=
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Subtract.
\newline
2
−
(
−
2
)
=
2-(-2)=
2
−
(
−
2
)
=
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Subtract.
\newline
4
−
(
−
4
)
=
4-(-4)=
4
−
(
−
4
)
=
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Subtract.
\newline
3
−
(
−
6
)
=
3-(-6)=
3
−
(
−
6
)
=
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Evaluate.
\newline
−
5
3
4
0
1
3
=
\frac{\sqrt[3]{-5}}{40^{\frac{1}{3}}}=
4
0
3
1
3
−
5
=
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Evaluate.
\newline
(
1
3
)
−
2
5
⋅
9
6
−
2
5
=
\left(\frac{1}{3}\right)^{-\frac{2}{5}} \cdot 96^{-\frac{2}{5}}=
(
3
1
)
−
5
2
⋅
9
6
−
5
2
=
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Evaluate.
\newline
12
5
−
11
12
12
5
−
1
4
=
\frac{125^{-\frac{11}{12}}}{125^{-\frac{1}{4}}}=
12
5
−
4
1
12
5
−
12
11
=
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lim
x
→
0
(
−
3
x
3
−
7
x
+
8
)
=
\lim _{x \rightarrow 0}\left(-3 x^{3}-7 x+8\right)=
lim
x
→
0
(
−
3
x
3
−
7
x
+
8
)
=
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Find the sum.
\newline
∑
k
=
1
40
(
5
k
−
87
)
=
\sum_{k=1}^{40}(5 k-87)=
k
=
1
∑
40
(
5
k
−
87
)
=
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∑
k
=
1
2
(
3
−
k
)
=
\sum_{k=1}^{2}(3-k)=
∑
k
=
1
2
(
3
−
k
)
=
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Evaluate the following expression.
\newline
8
+
8
1
4
=
8+\frac{8}{1^{4}}=
8
+
1
4
8
=
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Evaluate the following expression.
\newline
9
−
1
+
9
+
3
4
=
9-1+9+3^{4}=
9
−
1
+
9
+
3
4
=
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Evaluate the following expression.
\newline
2
⋅
1
0
4
−
7
3
=
2 \cdot 10^{4}-7^{3}=
2
⋅
1
0
4
−
7
3
=
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Evaluate the following expression.
\newline
4
⋅
6
÷
2
3
=
4 \cdot 6 \div 2^{3}=
4
⋅
6
÷
2
3
=
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Evaluate the following expression.
\newline
2
8
−
10
−
15
÷
3
=
2^{8}-10-15 \div 3=
2
8
−
10
−
15
÷
3
=
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Evaluate the following expression.
\newline
5
4
5
+
4
=
\frac{5^{4}}{5}+4=
5
5
4
+
4
=
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Evaluate the following expression.
\newline
6
⋅
2
+
6
4
=
6 \cdot 2+6^{4}=
6
⋅
2
+
6
4
=
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Evaluate the expression. Do not round your answer.
\newline
(
3
+
2
)
2
−
7
=
(3+2)^{2}-7=
(
3
+
2
)
2
−
7
=
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Evaluate the following expression.
\newline
1
0
7
+
9
+
1
3
=
10^{7}+9+1^{3}=
1
0
7
+
9
+
1
3
=
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