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13 X is a point inside triangle 
PQR. It is 
3cm from 
P, and 
4cm from Q. How far is 
X from 
R ?

13X 13 X is a point inside triangle PQR P Q R . It is 3 cm 3 \mathrm{~cm} from P P , and 4 cm 4 \mathrm{~cm} from Q. How far is X \mathrm{X} from R \mathrm{R} ?

Full solution

Q. 13X 13 X is a point inside triangle PQR P Q R . It is 3 cm 3 \mathrm{~cm} from P P , and 4 cm 4 \mathrm{~cm} from Q. How far is X \mathrm{X} from R \mathrm{R} ?
  1. Identify Problem: Identify the problem as finding the distance from point XX to vertex RR in triangle PQRPQR, where distances from PP to XX and QQ to XX are known.
  2. Use Triangle Inequality Theorem: Use the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
  3. Apply Theorem: Apply the theorem: Let's denote the unknown distance from X to R as dd. According to the triangle inequality:\newline11. PX+XR>PRPX + XR > PR\newline22. QX+XR>QRQX + XR > QR\newline33. PX+QX>PQPX + QX > PQ\newlineGiven PX=3PX = 3cm and QX=4QX = 4cm, we can write:\newline11. 3+d>PR3 + d > PR\newline22. 4+d>QR4 + d > QR\newline33. 3+4>PQ3 + 4 > PQ
  4. Additional Information Needed: Since we don't have the values for PRPR, QRQR, or PQPQ, we cannot directly calculate dd using these inequalities. We need additional information about the triangle or a different approach to solve for dd.

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