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12=e2x\frac{1}{2} = e^{-\frac{2}{x}}

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Q. 12=e2x\frac{1}{2} = e^{-\frac{2}{x}}
  1. Identify Equation & Goal: Identify the equation and the goal.\newlineWe are given the equation 12=e2x\frac{1}{2} = e^{-\frac{2}{x}}, and we need to solve for xx.
  2. Take Natural Logarithm: Take the natural logarithm of both sides to eliminate the exponential function.\newlineln(12)=ln(e2x)\ln(\frac{1}{2}) = \ln(e^{-\frac{2}{x}})
  3. Use Logarithm Property: Use the property of logarithms that ln(ey)=y\ln(e^y) = y.ln(12)=2x\ln(\frac{1}{2}) = -\frac{2}{x}
  4. Solve for x: Solve for x by multiplying both sides by x-x and dividing by ln(12)\ln(\frac{1}{2}).\newlinex=2ln(12)x = \frac{-2}{\ln(\frac{1}{2})}
  5. Calculate ln(12)\ln(\frac{1}{2}): Calculate the value of ln(12)\ln(\frac{1}{2}).\newlineln(12)\ln(\frac{1}{2}) is the natural logarithm of 12\frac{1}{2}, which is a negative value because 12\frac{1}{2} is less than 11.\newlineln(12)0.693147\ln(\frac{1}{2}) \approx -0.693147
  6. Substitute ln(12)\ln(\frac{1}{2}) into xx: Substitute the value of ln(12)\ln(\frac{1}{2}) into the equation for xx.x=2(0.693147)x = \frac{-2}{(-0.693147)}
  7. Calculate xx: Calculate the value of xx.x2(0.693147)2.88539x \approx \frac{-2}{(-0.693147)} \approx 2.88539

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