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{:[z=-13-52 i],[Re(z)=],[Im(z)=]:}

z=1352iRe(z)=Im(z)= \begin{array}{l}z=-13-52 i \\ \operatorname{Re}(z)= \\ \operatorname{Im}(z)=\end{array}

Full solution

Q. z=1352iRe(z)=Im(z)= \begin{array}{l}z=-13-52 i \\ \operatorname{Re}(z)= \\ \operatorname{Im}(z)=\end{array}
  1. Identify real and imaginary parts: Identify the real part (Re(zz)) and the imaginary part (Im(zz)) of the complex number z=1352iz = -13 - 52i.\newlineA complex number is in the form a+bia + bi, where aa is the real part and bb is the coefficient of the imaginary part ii.\newlineFor z=1352iz = -13 - 52i, the real part is 13-13 and the imaginary part is 52-52 (without the ii).
  2. Verify correctness of identification: Verify that there are no mathematical errors in identifying the real and imaginary parts.\newlineThe real part is simply the number without the ii, and the imaginary part is the coefficient of ii.\newlineThere are no additional terms or operations to consider, so there is no room for a math error in this step.

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