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(x-5)^(2)+36=0

$(x-5)^{2}+36=0$

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Factor sums and differences of cubes

Full solution

Q.

(x-5)^{2}+36=0

Write Equation: First, let's write down the equation we need to solve: $\newline$ $(x-5)^2 + 36 = 0$
Subtract $36$ : Now, we subtract $36$ from both sides to isolate the squared term: $\newline$ $(x-5)^2 = -36$
Take Square Root: Next, we take the square root of both sides to solve for $x-5$ . Remember, when we take the square root of both sides, we consider both the positive and negative square roots: $\newline$ $x-5 = \pm\sqrt{-36}$
Math Error: Oops, we can't take the square root of a negative number in the set of real numbers. This means there's a math error here.

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