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(tan^(2)x-1)/(1+tan x)

tan⁡2x−11+tan⁡x \frac{\tan ^{2} x-1}{1+\tan x}

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Full solution

Q. tan⁡2x−11+tan⁡x \frac{\tan ^{2} x-1}{1+\tan x}
  1. Recognize identity: Recognize the identity used in the expression. Using the identity tan⁡2(x)−1=sec⁡2(x)−1−1=sec⁡2(x)−2\tan^2(x) - 1 = \sec^2(x) - 1 - 1 = \sec^2(x) - 2.

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