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{:[" SD "=root(i)((sum fx^(2))/(n)-((kfx^(1))/(n)))],[" SD "=root(7)((261)/(90)-((-128)/(90))^(2))],[=7sqrt(2,9-(-1,422)^(2))],[=7sqrt(2,9-2,0224)],[=7]:}

SD=(∑fx2n)−(kfx1n)iSD = \sqrt[i]{\left(\frac{\sum f x^{2}}{n}\right)-\left(\frac{kfx^{1}}{n}\right)}, SD=(26190)−(−12890)27SD = \sqrt[7]{\left(\frac{261}{90}\right)-\left(\frac{-128}{90}\right)^{2}}, =72,9−(−1,422)2=7\sqrt{2,9-(-1,422)^{2}}, =72,9−2,0224=7\sqrt{2,9-2,0224}, =7=7

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Full solution

Q. SD=(∑fx2n)−(kfx1n)iSD = \sqrt[i]{\left(\frac{\sum f x^{2}}{n}\right)-\left(\frac{kfx^{1}}{n}\right)}, SD=(26190)−(−12890)27SD = \sqrt[7]{\left(\frac{261}{90}\right)-\left(\frac{-128}{90}\right)^{2}}, =72,9−(−1,422)2=7\sqrt{2,9-(-1,422)^{2}}, =72,9−2,0224=7\sqrt{2,9-2,0224}, =7=7
  1. Calculate total rolls: We need to divide the total amount of tape needed by the amount of tape on each roll. 8,000 cm÷2,000 cm/roll=4 rolls8,000 \, \text{cm} \div 2,000 \, \text{cm}/\text{roll} = 4 \, \text{rolls}
  2. Determine number of rolls: So, the electrician should order 44 rolls of tape.

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