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/_MBA=20^(@)/_MAC^(@)=40^(@) of 
/_MCA=30^(@). Denonstrati ef triunghial 
ABC este inconcell.

1010. MBA=20MAC=40 \angle M B A=20^{\circ} \angle M A C^{\circ}=40^{\circ} of MCA=30 \angle M C A=30^{\circ} . Denonstrati ef triunghial ABC A B C este inconcell.

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Q. 1010. MBA=20MAC=40 \angle M B A=20^{\circ} \angle M A C^{\circ}=40^{\circ} of MCA=30 \angle M C A=30^{\circ} . Denonstrati ef triunghial ABC A B C este inconcell.
  1. Identify Isosceles Triangle: Since triangle ABCABC is isosceles, two angles must be equal. We know angle MACMAC is 4040 degrees and angle MCAMCA is 3030 degrees.
  2. Calculate Sum of Known Angles: The sum of angles in a triangle is 180180 degrees. Let's add up the angles we know: 4040 degrees (angle MAC\text{MAC}) + 3030 degrees (angle MCA\text{MCA}).
  3. Subtract Sum from 180180: 4040 degrees + 3030 degrees = 7070 degrees. This is the sum of the two angles we know.
  4. Find Measure of Angle MBA: Subtract the sum of the known angles from 180180 degrees to find the measure of the third angle, which is angle MBA.
  5. Find Measure of Angle MBA: Subtract the sum of the known angles from 180180 degrees to find the measure of the third angle, which is angle MBA.180180 degrees - 7070 degrees = 110110 degrees. So, angle MBA should be 110110 degrees.

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