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(y45)2+(x+710)2=30\left(y-\dfrac{4}{5}\right)^2+\left(x+\dfrac{7}{10}\right)^2=30

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Q. (y45)2+(x+710)2=30\left(y-\dfrac{4}{5}\right)^2+\left(x+\dfrac{7}{10}\right)^2=30
  1. Identify Circle Equation: Identify the general form of the circle equation and compare it to the given equation.\newlineThe general form is (yk)2+(xh)2=r2(y - k)^2 + (x - h)^2 = r^2, where (h,k)(h, k) is the center and rr is the radius.\newlineGiven equation: (y45)2+(x+710)2=30\left(y-\dfrac{4}{5}\right)^2+\left(x+\dfrac{7}{10}\right)^2=30
  2. Determine Center: Determine the center (h,k)(h, k) of the circle from the equation.\newlineFrom the equation, h=710h = -\dfrac{7}{10} and k=45k = \dfrac{4}{5}.\newlineSo, the center is (710,45)\left(-\dfrac{7}{10}, \dfrac{4}{5}\right).
  3. Calculate Radius: Calculate the radius rr of the circle.\newlineThe radius squared r2r^2 is given as 3030.\newlineTo find rr, calculate the square root: r=30r = \sqrt{30}.

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