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$\dfrac{1}{4}(2^3+4^2) =$

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Powers with negative bases

Full solution

Q.

\dfrac{1}{4}(2^3+4^2) =

Evaluate Exponents: Evaluate the exponents in the expression. $\newline$ We need to calculate $2^3$ and $4^2$ . $\newline$ $2^3 = 2 \times 2 \times 2 = 8$ $\newline$ $4^2 = 4 \times 4 = 16$
Add Exponents: Add the results of the exponents. $\newline$ Now we add the results from Step $1$ . $\newline$ $8 + 16 = 24$
Multiply by Fraction: Multiply the sum by $\dfrac{1}{4}$ . $\newline$ We multiply the result from Step $2$ by $\dfrac{1}{4}$ . $\newline$ $\dfrac{1}{4} \times 24 = \dfrac{24}{4}$
Simplify Fraction: Simplify the fraction. $\newline$ We divide $24$ by $4$ to simplify the fraction. $\newline$ $\dfrac{24}{4} = 6$

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