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Решите уравнение cos2x+sin2x=0.75\cos 2x + \sin^2 x = 0.75

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Q. Решите уравнение cos2x+sin2x=0.75\cos 2x + \sin^2 x = 0.75
  1. Recognize Pythagorean identity: First, we need to recognize that cos2x\cos^2x can be expressed in terms of sin2x\sin^2x using the Pythagorean identity: cos2x=1sin2x\cos^2x = 1 - \sin^2x. We will use this identity to rewrite the equation in terms of sin2x\sin^2x only.
  2. Substitute cos2x\cos 2x: Substitute cos2x\cos 2x with 1sin2x1 - \sin^2x in the equation:\newline(1sin2x)+sin2x=0.75(1 - \sin^2x) + \sin^2x = 0.75
  3. Simplify equation: Simplify the equation by combining like terms: 1sin2x+sin2x=0.751 - \sin^2 x + \sin^2 x = 0.75
  4. Cancel sin2x\sin^2 x terms: The sin2x\sin^2 x terms cancel each other out, leaving us with: 1=0.751 = 0.75 This is a contradiction because 10.751 \neq 0.75. There seems to be a mistake in the simplification process.

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