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\egin{cases} g(11)=1414 \ g(n)=g(n1-1)4-4 \end{cases}

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Q. \egin{cases} g(11)=1414 \ g(n)=g(n1-1)4-4 \end{cases}
  1. Understand Recursive Function: First, we need to understand the recursive function given. The function g(n)g(n) is defined such that g(1)=14g(1) = 14, and for every n>1n > 1, g(n)=g(n1)4g(n) = g(n-1) - 4. We need to find the value of g(5)g(5).
  2. Base Case: g(1)=14g(1) = 14: We start with the base case given: g(1)=14g(1) = 14.
  3. Find g(2)g(2): To find g(2)g(2), we use the recursive formula g(n)=g(n1)4g(n) = g(n-1) - 4. So, g(2)=g(1)4=144g(2) = g(1) - 4 = 14 - 4.
  4. Calculate g(2)g(2): Calculating g(2)g(2), we get g(2)=144=10g(2) = 14 - 4 = 10.
  5. Find g(3)g(3): Next, we find g(3)g(3) using the same recursive formula: g(3)=g(2)4=104g(3) = g(2) - 4 = 10 - 4.
  6. Calculate g(3)g(3): Calculating g(3)g(3), we get g(3)=104=6g(3) = 10 - 4 = 6.
  7. Find g(4)g(4): Now, we find g(4)g(4): g(4)=g(3)4=64g(4) = g(3) - 4 = 6 - 4.
  8. Calculate g(4)g(4): Calculating g(4)g(4), we get g(4)=64=2g(4) = 6 - 4 = 2.
  9. Find g(5)g(5): Finally, we find g(5)g(5): g(5)=g(4)4=24g(5) = g(4) - 4 = 2 - 4.
  10. Calculate g(5)g(5): Calculating g(5)g(5), we get g(5)=24=2g(5) = 2 - 4 = -2.

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