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(b) 9x+3 >= 5x-11

(b) 9x+3≥5x−11 9 x+3 \geq 5 x-11

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Full solution

Q. (b) 9x+3≥5x−11 9 x+3 \geq 5 x-11
  1. Move x terms together: First, let's move all the x terms to one side by subtracting 5x5x from both sides.9x+3−5x≥5x−11−5x9x + 3 - 5x \geq 5x - 11 - 5x4x+3≥−114x + 3 \geq -11
  2. Subtract to isolate x: Now, subtract 33 from both sides to isolate the xx term.\newline4x+3−3≥−11−34x + 3 - 3 \geq -11 - 3\newline4x≥−144x \geq -14
  3. Divide to solve for x: Finally, divide both sides by 44 to solve for xx.\newline4x4≥−144\frac{4x}{4} \geq \frac{-14}{4}\newlinex≥−3.5x \geq -3.5

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