Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

-81x^(2)=-11
What are the solutions to the given equation?
Choose 1 answer:
(A)
x=(sqrt11)/(81)
B
x=-(sqrt11)/(81) and
x=(sqrt11)/(81)
(C)
x=-(sqrt11)/(9) and
x=(sqrt11)/(9)
(D)
x=(sqrt11)/(9)

$-81 x^{2}=-11$ $\newline$ What are the solutions to the given equation? $\newline$ Choose $1$ answer: $\newline$ (A) $x=\frac{\sqrt{11}}{81}$ $\newline$ (B) $x=-\frac{\sqrt{11}}{81}$ and $x=\frac{\sqrt{11}}{81}$ $\newline$ (C) $x=-\frac{\sqrt{11}}{9}$ and $x=\frac{\sqrt{11}}{9}$ $\newline$ (D) $x=\frac{\sqrt{11}}{9}$

View step-by-step help

View step-by-step help

Solve a quadratic equation using the zero product property

Full solution

Q.

-81 x^{2}=-11

\newline

What are the solutions to the given equation?

\newline

Choose

1

answer:

\newline

(A)

x=\frac{\sqrt{11}}{81}

\newline

(B)

x=-\frac{\sqrt{11}}{81}

and

x=\frac{\sqrt{11}}{81}

\newline

(C)

x=-\frac{\sqrt{11}}{9}

and

x=\frac{\sqrt{11}}{9}

\newline

(D)

x=\frac{\sqrt{11}}{9}

Question Prompt: question_prompt: ＂What are the solutions to the given equation $-81x^{2}=-11$ ?＂
Step $1$ : Step $1$ : Divide both sides of the equation by $-81$ to isolate $x^2$ . So, $x^2 = -11/-81$ .
Step $2$ : Step $2$ : Simplify the right side of the equation. $x^2 = \frac{11}{81}$ .
Step $3$ : Step $3$ : Take the square root of both sides to solve for $x$ . Remember, there are two solutions: $x = \sqrt{\frac{11}{81}}$ and $x = -\sqrt{\frac{11}{81}}$ .
Step $4$ : Step $4$ : Simplify the square root. $\sqrt{\frac{11}{81}}$ is the same as $\sqrt{11}/\sqrt{81}$ .
Step $5$ : Step $5$ : Since $\sqrt{81}$ is $9$ , we get $x = \frac{\sqrt{11}}{9}$ and $x = -\frac{\sqrt{11}}{9}$ .

More problems from Solve a quadratic equation using the zero product property

Question

h

is defined over the real numbers. This table gives a few values of

h

\newline

\begin{tabular}{lllll}

\newline

x

-6

1

-6

01

-6

001

-5

9

\newline

h(x)

-0

25

-0

74

-0

98

-1

0

\newline

\newline

What is a reasonable estimate for

\lim _{x \rightarrow-6} h(x)

\newline

1

\newline

-6

\newline

-2

\newline

-1

\newline

(D) The limit doesn't exist

Posted 4 months ago

Question

What is the amplitude of

\newline

g(x)=-2 \sin \left(\frac{\pi}{2} x-3\right)+5 ?

\newline

Posted 3 months ago

Question

What is the amplitude of

y=5 \sin (4 x-2)-3

\newline

Posted 3 months ago

Question

What is the amplitude of

y=-3 \cos (\pi x+2)-6 ?

\newline

Posted 3 months ago

Question

What is the amplitude of

y=3 \sin (2 x-1)+4

\newline

Posted 3 months ago

Question

What is the period of the function

h(x)=-3 \cos (\pi x+2)-6 ?

\newline

Give an exact value.

\newline

Posted 3 months ago

Question

What is the period of the function

\newline

h(x)=5 \sin (4 x-2)-3 \text { ? }

\newline

Give an exact value.

\newline

Posted 3 months ago

Question

What is the period of the function

g(x)=2 \cos (7 x+5)+1 ?

\newline

Give an exact value.

\newline

Posted 3 months ago

Question

What is the period of the function

f(x)=3 \sin (2 x-1)+4

\newline

Give an exact value.

\newline

Posted 3 months ago

Question

What is the period of the function

f(x)=-4 \cos (5 x-9)-7

\newline

Give an exact value.

\newline

Posted 3 months ago