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(6)
/_1 and
/_2 aro
11+4=90
0.1=(7x+16)^(@)mdmm//2=(4x-3)^(@), then find the mesure of
/_2.
quad x=pi find the measure of
/_2.

7(7x+16)+(4x-3)
A.lialtab

(-3)

( $6$ ) $\angle 1$ and $\angle 2$ aro $11+4=90$ $0.1=(7 x+16)^{\circ} \mathrm{mdm} \mathrm{m} / 2=(4 x-3)^{\circ}$ , then find the mesure of $\angle 2$ . $\quad x=\pi$ find the measure of $\angle 2$ . $\newline$ $7(7 x+16)+(4 x-3)$ $\newline$ A.lialtab $\newline$ $(-3)$

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Transformations of functions

Full solution

Q. (

6

)

\angle 1

and

\angle 2

aro

11+4=90

0.1=(7 x+16)^{\circ} \mathrm{mdm} \mathrm{m} / 2=(4 x-3)^{\circ}

, then find the mesure of

\angle 2

.

\quad x=\pi

find the measure of

\angle 2

.

\newline

7(7 x+16)+(4 x-3)

\newline

A.lialtab

\newline

(-3)

Step $1$ : Plug in x value: question_prompt: Find the measure of $\angle 2$ when $x=\pi$ . $\newline$ Step $1$ : Plug in the given value of $x$ into the equation for $\angle 2$ . $\newline$ $\angle 2 = 11 + 4 = 90$ $\newline$ $\angle 2 = 90$ degrees
Step $2$ : Solve equation: Step $2$ : Solve the equation $0.1 = (7x + 16)^{2}$ and $(4x - 3)^{2}$ to find the measure of $\angle_2$ . This step is not needed because we already have the measure of $\angle_2$ from Step $1$ .

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