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Поставьте вместо знака 
** такой одночлен, чтобы трёхчлен но было представить в виде квадрата двучлена:
а) 
**+56 a+49;
б) 
36-12 x+**;
в) 
25a^(2)+**+(1)/(4)b^(2);
г) 
0,01b^(2)+**+100c^(2).

852852. Поставьте вместо знака * такой одночлен, чтобы трёхчлен но было представить в виде квадрата двучлена:\newlineа) +56a+49 *+56 a+49 ;\newlineб) 3612x+ 36-12 x+* ;\newlineв) 25a2++14b2 25 a^{2}+*+\frac{1}{4} b^{2} ;\newlineг) 0,01b2++100c2 0,01 b^{2}+*+100 c^{2} .

Full solution

Q. 852852. Поставьте вместо знака * такой одночлен, чтобы трёхчлен но было представить в виде квадрата двучлена:\newlineа) +56a+49 *+56 a+49 ;\newlineб) 3612x+ 36-12 x+* ;\newlineв) 25a2++14b2 25 a^{2}+*+\frac{1}{4} b^{2} ;\newlineг) 0,01b2++100c2 0,01 b^{2}+*+100 c^{2} .
  1. Recognize Perfect Square Trinomial: To represent a trinomial as the square of a binomial, the trinomial must be a perfect square trinomial. The general form of a perfect square trinomial is (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2. We need to find the missing term that will complete the square for each case.
  2. Complete the Square: 4949: а) For the trinomial x2+56a+49x^2 + 56a + 49, we recognize that 4949 is a perfect square, 727^2. The term 56a56a suggests that the binomial form could be (x+7)2(x + 7)^2, where xx is the variable part of the first term. To complete the square, we need the first term to be (7x)2(7x)^2, so xx should be aa. Therefore, the missing term is 7a×7a=49a27a \times 7a = 49a^2.
  3. Complete the Square: 3636: б) For the trinomial 3612x+36 - 12x + **, we recognize that 3636 is a perfect square, 626^2. The term 12x-12x suggests that the binomial form could be (6x)2(6 - x)^2. To complete the square, we need the last term to be (x)2(-x)^2, so the missing term is x2x^2.
  4. Complete the Square: 25a225a^2: в) For the trinomial 25a2++(14)b225a^2 + ** + (\frac{1}{4})b^2, we recognize that 25a225a^2 is a perfect square, (5a)2(5a)^2, and (14)b2(\frac{1}{4})b^2 is also a perfect square, (12b)2(\frac{1}{2}b)^2. The middle term should be 2(5a)(12b)=5ab2\cdot(5a)\cdot(\frac{1}{2}b) = 5ab. Therefore, the missing term is 5ab5ab.
  5. Complete the Square: 0.01b20.01b^2: г) For the trinomial 0.01b2++100c20.01b^2 + ** + 100c^2, we recognize that 0.01b20.01b^2 is a perfect square, (0.1b)2(0.1b)^2, and 100c2100c^2 is also a perfect square, (10c)2(10c)^2. The middle term should be 2×(0.1b)×(10c)=2bc2\times(0.1b)\times(10c) = 2bc. Therefore, the missing term is 2bc2bc.

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