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(4)/(6)+(1)/(3)=

$3$ ) $\frac{4}{6}+\frac{1}{3}=$

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Powers with negative bases

Full solution

Q.

3

)

\frac{4}{6}+\frac{1}{3}=

Find Common Denominator: First, find a common denominator for the fractions $\frac{4}{6}$ and $\frac{1}{3}$ . The common denominator is $6$ .
Convert $\frac{1}{3}$ to $6$ : Convert $\frac{1}{3}$ to a fraction with a denominator of $6$ . $\newline$ $\frac{1}{3} = \frac{2}{6}$
Add Fractions: Now add the fractions $\frac{4}{6}$ and $\frac{2}{6}$ . $\frac{4}{6} + \frac{2}{6} = \frac{6}{6}$

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