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|3x+4| > 6-7x.

3x+4>67x |3 x+4|>6-7 x .

Full solution

Q. 3x+4>67x |3 x+4|>6-7 x .
  1. Consider Cases: First, we need to consider the two cases for the absolute value inequality.\newlineCase 11: 3x+4>67x3x + 4 > 6 - 7x when (3x+4)(3x + 4) is positive.
  2. Addition and Isolation: Add 7x7x to both sides to get all the xx terms on one side.\newline3x+4+7x>67x+7x3x + 4 + 7x > 6 - 7x + 7x\newline10x+4>610x + 4 > 6
  3. Division and Solution: Subtract 44 from both sides to isolate the term with xx.\newline10x+44>6410x + 4 - 4 > 6 - 4\newline10x>210x > 2
  4. Consider Negative Case: Divide both sides by 1010 to solve for xx.10x10>210\frac{10x}{10} > \frac{2}{10}x>15x > \frac{1}{5}
  5. Multiplication and Inequality: Now, let's consider Case 22: (3x+4)>67x-(3x + 4) > 6 - 7x when (3x+4)(3x + 4) is negative.
  6. Subtraction and Isolation: Multiply both sides by 1-1 and remember to flip the inequality sign.\newline1×(3x+4)<1×(67x)-1 \times -(3x + 4) < -1 \times (6 - 7x)\newline3x+4<7x63x + 4 < 7x - 6
  7. Addition and Isolation: Subtract 3x3x from both sides to get all the xx terms on one side.\newline3x+43x<7x63x3x + 4 - 3x < 7x - 6 - 3x\newline4<4x64 < 4x - 6
  8. Division and Solution: Add 66 to both sides to isolate the term with xx.\newline4+6<4x6+64 + 6 < 4x - 6 + 6\newline10<4x10 < 4x
  9. Combine Solutions: Divide both sides by 44 to solve for xx.\newline104<4x4\frac{10}{4} < \frac{4x}{4}\newline2.5<x2.5 < x
  10. Combine Solutions: Divide both sides by 44 to solve for xx.\newline104<4x4\frac{10}{4} < \frac{4x}{4}\newline2.5<x2.5 < x Combine the solutions from both cases to get the final solution for the inequality.\newlinex>15x > \frac{1}{5} or x>2.5x > 2.5

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