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${:[3I_(1)-I_(2)+3I_(3)+2I_(4)=12],[I_(1)-2I_(3)+I_(4)=-1],[5I_(1)-5I_(2)+I_(3)+2I_(4)=8],[3I_(1)+I_(2)+2I_(3)+2I_(4)=10],[I_(1)=iI_(1)]:}$

$\begin{array}{r}3 I_{1}-I_{2}+3 I_{3}+2 I_{4}=12 \\ I_{1}-2 I_{3}+I_{4}=-1 \\ 5 I_{1}-5 I_{2}+I_{3}+2 I_{4}=8 \\ 3 I_{1}+I_{2}+2 I_{3}+2 I_{4}=10 \\ I_{1}=\mathbf{i} I_{1}\end{array}$

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Interpret measures of center and variability

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Q.

\begin{array}{r}3 I_{1}-I_{2}+3 I_{3}+2 I_{4}=12 \\ I_{1}-2 I_{3}+I_{4}=-1 \\ 5 I_{1}-5 I_{2}+I_{3}+2 I_{4}=8 \\ 3 I_{1}+I_{2}+2 I_{3}+2 I_{4}=10 \\ I_{1}=\mathbf{i} I_{1}\end{array}

Write Equations: Write down the system of equations. $\begin{cases} 3I_1-I_2+3I_3+2I_4=12, \ I_1-2I_3+I_4=-1, \ 5I_1-5I_2+I_3+2I_4=8, \ 3I_1+I_2+2I_3+2I_4=10, \ I_1=iI_1 \end{cases}$
Simplify Equation: Simplify the last equation. $\newline$ The last equation $I_{1}=iI_{1}$ doesn't make sense, it implies $I_{1} = 0$ or it's a typo. We can't solve for imaginary numbers in this context, so we'll ignore this equation.

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