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#3 
y^(')(2,-4) is the image of 
y after a translation along the rule 
(x,y)rarr(x-4,y^(2)-3). What are the coordinates of pre-image 
y ?

\#33 y(2,4) y^{\prime}(2,-4) is the image of y y after a translation along the rule (x,y)(x4,y23) (x, y) \rightarrow\left(x-4, y^{2}-3\right) . What are the coordinates of pre-image y y ?

Full solution

Q. \#33 y(2,4) y^{\prime}(2,-4) is the image of y y after a translation along the rule (x,y)(x4,y23) (x, y) \rightarrow\left(x-4, y^{2}-3\right) . What are the coordinates of pre-image y y ?
  1. Understand translation rule: First, let's understand the translation rule given: (x,y)(x4,y23)(x, y) \rightarrow (x - 4, y^2 - 3). This means that for any point (x,y)(x, y), the xx-coordinate is decreased by 44 and the yy-coordinate is squared and then decreased by 33 to get the image point.
  2. Find pre-image point: We are given the image point yy' as (2,4)(2, -4). To find the pre-image yy, we need to reverse the translation rule. This means we need to add 44 to the xx-coordinate of the image and find the square root of the yy-coordinate of the image plus 33.
  3. Reverse translation for xx-coordinate: Let's apply the reverse translation to the xx-coordinate of the image point. We add 44 to the xx-coordinate of the image point: 2+4=62 + 4 = 6.
  4. Reverse translation for y-coordinate: Now, let's apply the reverse translation to the y-coordinate of the image point. We first add 33 to the y-coordinate of the image point: 4+3=1-4 + 3 = -1. Since we cannot take the square root of a negative number in the set of real numbers, there is a math error here. We cannot proceed with finding the square root of 1-1 as it would result in an imaginary number, which is not applicable in this context.

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