Q. \#3y′(2,−4) is the image of y after a translation along the rule (x,y)→(x−4,y2−3). What are the coordinates of pre-image y ?
Understand translation rule: First, let's understand the translation rule given: (x,y)→(x−4,y2−3). This means that for any point (x,y), the x-coordinate is decreased by 4 and the y-coordinate is squared and then decreased by 3 to get the image point.
Find pre-image point: We are given the image point y′ as (2,−4). To find the pre-image y, we need to reverse the translation rule. This means we need to add 4 to the x-coordinate of the image and find the square root of the y-coordinate of the image plus 3.
Reverse translation for x-coordinate: Let's apply the reverse translation to the x-coordinate of the image point. We add 4 to the x-coordinate of the image point: 2+4=6.
Reverse translation for y-coordinate: Now, let's apply the reverse translation to the y-coordinate of the image point. We first add 3 to the y-coordinate of the image point: −4+3=−1. Since we cannot take the square root of a negative number in the set of real numbers, there is a math error here. We cannot proceed with finding the square root of −1 as it would result in an imaginary number, which is not applicable in this context.
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