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(2502)−(2302)\sqrt{(250^2)-(230^2)}

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Full solution

Q. (2502)−(2302)\sqrt{(250^2)-(230^2)}
  1. Apply formula: Apply the difference of squares formula, which is a2−b2=(a+b)(a−b)a^2 - b^2 = (a + b)(a - b).(2502)−(2302)=((250+230)(250−230))\sqrt{(250^2)-(230^2)} = \sqrt{((250 + 230)(250 - 230))}
  2. Calculate sum and difference: Calculate the sum and difference of 250250 and 230230. \newline(250+230)(250−230)=(480×20)\sqrt{(250 + 230)(250 - 230)} = \sqrt{(480 \times 20)}
  3. Multiply to find product: Multiply 480480 by 2020 to find the product.\newline480×20=9600\sqrt{480 \times 20} = \sqrt{9600}
  4. Find square root: Find the square root of 96009600.9600=98\sqrt{9600} = 98

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