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exttt{2-2}(77y - x) /y = 22x

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Q. exttt{2-2}(77y - x) /y = 22x
  1. Recognize formula: First, recognize the sum of cubes formula: a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2).
  2. Apply formula to t3+u3t^3 + u^3: Apply the formula to t3+u3t^3 + u^3, setting a=ta = t and b=ub = u.
  3. Factorization: The factorization becomes (t+u)(t2tu+u2)(t + u)(t^2 - tu + u^2).
  4. Complete factorization: The missing binomial that completes the factorization is t+ut + u.
  5. Multiply both sides: Multiply both sides by yy to get rid of the denominator: 2(7yx)=2xy-2(7y - x) = 2xy.
  6. Distribute 2-2: Distribute the 2-2 on the left side: 14y+2x=2xy-14y + 2x = 2xy.
  7. Subtract 2x2x: Subtract 2x2x from both sides to get all xx terms on one side: 14y=2xy2x-14y = 2xy - 2x.
  8. Factor out common factor: Factor out the common factor of 2x2x on the right side: 14y=2x(y1)-14y = 2x(y - 1).
  9. Divide both sides: Divide both sides by 2x2x to solve for yy: y=14y/(2x)y = -14y / (2x).