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{:[12-8+6=10],[3x^(3)-8+2x^(3)=10],[-8quad+8],[4x+2x],[6x=18],[6//6],[x=3]:}

12−8+6=103x3−8+2x3=10−8+84x+2x6x=186/6x=3 \begin{array}{l}12-8+6=10 \\ 3 x^{3}-8+2 x^{3}=10 \\ -8 \quad+8 \\ 4 x+2 x \\ 6 x=18 \\ 6 / 6 \\ x=3\end{array}

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Q. 12−8+6=103x3−8+2x3=10−8+84x+2x6x=186/6x=3 \begin{array}{l}12-8+6=10 \\ 3 x^{3}-8+2 x^{3}=10 \\ -8 \quad+8 \\ 4 x+2 x \\ 6 x=18 \\ 6 / 6 \\ x=3\end{array}
  1. Perform Division: Now, we do the division. x=3x = 3

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