Resources

Resources

Understanding negative exponents

(x+1)^2-7

7

) The product of two numbers is the greatest

2

-digit number. If one of the numbers is

-11

, find the other number. On dividing

-8016

x

, the answer obtained is

-16

. Find the value of integer

x

. Evaluate the following. (

9

49 \times 89 \times (-107) \times 0 \times 412

1

(-8) \times (-16)

8

[12+9] \div [-9 \div 3]

\sqrt{([9+6-12-3] \div (-48))}

Which is equal to

7^{-7}

\newline

\newline

\frac{1}{7^7}

\newline

-(-7)^7

\newline

\frac{1}{(-7)^7}

\newline

-\frac{1}{(-7)^{-7}}

Which is equal to

\frac{1}{4^5}

\newline

\newline

-\frac{1}{(-4)^{-5}}

\newline

\frac{1}{(-4)^5}

\newline

\frac{1}{4^{-5}}

\newline

4^{-5}

Which is equal to

5^{-8}

\newline

\newline

-(-5)^8

\newline

(-5)^8

\newline

\frac{1}{5^8}

\newline

-\frac{1}{5^{-8}}

Which is equal to

\frac{1}{8^5}

\newline

\newline

-8^5

\newline

8^{-5}

\newline

(-8)^{-5}

\newline

-\frac{1}{8^{-5}}

Which is equal to

\frac{1}{8^7}

\newline

\newline

8^{-7}

\newline

(-8)^7

\newline

\frac{1}{(-8)^7}

\newline

-(-8)^7

Which is equal to

2^{-9}

\newline

\newline

\frac{1}{2^9}

\newline

2^9

\newline

\frac{1}{(-2)^9}

\newline

\frac{1}{(-2)^{-9}}

Which is equal to

\frac{1}{3^4}

\newline

\newline

3^4

\newline

-\frac{1}{3^{-4}}

\newline

3^{-4}

\newline

-(-3)^4

Which is equal to

\frac{1}{7^6}

\newline

\newline

7^{-6}

\newline

-7^6

\newline

-\frac{1}{7^{-6}}

\newline

(-7)^6

Which is equal to

\frac{1}{5^9}

\newline

\newline

5^{-9}

\newline

(-5)^9

\newline

\frac{1}{5^{-9}}

\newline

5^9

Which is equal to

\frac{1}{8^2}

\newline

\newline

-\frac{1}{8^{-2}}

\newline

8^{-2}

\newline

\frac{1}{8^{-2}}

\newline

-\frac{1}{(-8)^{-2}}

Which is equal to

\frac{1}{9^2}

\newline

\newline

-(-9)^2

\newline

9^{-2}

\newline

-9^2

\newline

-\frac{1}{9^{-2}}

Which is equal to

\frac{1}{2^5}

\newline

\newline

-2^5

\newline

-(-2)^5

\newline

(-2)^{-5}

\newline

2^{-5}

Which is equal to

\frac{1}{7^9}

\newline

\newline

-\frac{1}{(-7)^{-9}}

\newline

\frac{1}{(-7)^9}

\newline

(-7)^9

\newline

7^{-9}

Which is equal to

4^{-3}

\newline

\newline

-(-4)^3

\newline

\frac{1}{4^3}

\newline

(-4)^{-3}

\newline

4^3

Which is equal to

\frac{1}{2^3}

\newline

\newline

2^3

\newline

2^{-3}

\newline

(-2)^3

\newline

-(-2)^3

Which is equal to

3^{-7}

\newline

\newline

(-3)^{-7}

\newline

3^{7}

\newline

-\frac{1}{3^{-7}}

\newline

\frac{1}{3^{7}}

Which is equal to

\frac{1}{4^6}

\newline

\newline

\frac{1}{4^{-6}}

\newline

4^6

\newline

-(-4)^6

\newline

4^{-6}

Which is equal to

8^{-3}

\newline

\newline

-8^3

\newline

\frac{1}{8^3}

\newline

-\frac{1}{(-8)^{-3}}

\newline

-\frac{1}{8^{-3}}

Which is equal to

\frac{1}{4^7}

\newline

\newline

4^{-7}

\newline

\frac{1}{(-4)^7}

\newline

-\frac{1}{(-4)^{-7}}

\newline

-\frac{1}{4^{-7}}

Which is equal to

6^{-5}

\newline

\newline

-6^5

\newline

\frac{1}{6^5}

\newline

6^5

\newline

\frac{1}{(-6)^{-5}}

Which is equal to

3^{-2}

\newline

\newline

-(-3)^2

\newline

\frac{1}{3^2}

\newline

\frac{1}{3^{-2}}

\newline

3^2

Which is equal to

\frac{1}{2^7}

\newline

\newline

2^{-7}

\newline

-\frac{1}{(-2)^{-7}}

\newline

\frac{1}{2^{-7}}

\newline

(-2)^7

Which is equal to

\frac{1}{4^7}

\newline

\newline

4^{-7}

\newline

-\frac{1}{4^{-7}}

\newline

-4^7

\newline

\frac{1}{(-4)^7}

Which is equal to

7^{-2}

\newline

\newline

-(-7)^2

\newline

\frac{1}{7^2}

\newline

-\frac{1}{(-7)^{-2}}

\newline

-\frac{1}{7^{-2}}

Which is equal to

\frac{1}{6^6}

\newline

\newline

6^{-6}

\newline

(-6)^6

\newline

\frac{1}{6^{-6}}

\newline

-\frac{1}{(-6)^{-6}}

Which is equal to

5^{-8}

\newline

\newline

\frac{1}{5^8}

\newline

(-5)^8

\newline

-\frac{1}{5^{-8}}

\newline

-5^8

Which is equal to

6^{-3}

\newline

\newline

6^3

\newline

\frac{1}{6^3}

\newline

(-6)^{-3}

\newline

-\frac{1}{6^{-3}}

Which is equal to

9^{-4}

\newline

\newline

-9^4

\newline

\frac{1}{9^4}

\newline

\frac{-1}{(-9)^{-4}}

\newline

\frac{1}{(-9)^{-4}}

5

10

7

3

2

10

4

862^5/0182+7382=3x+5(729^7+092)

73739+3x=6[(572^{038}+7)737/9363]

12 \div 2(6-7+4) \times 2

\begin{array}{r}1 \frac{1}{2} \times \frac{3}{7}=- \\ +4 \frac{3}{7} \times \frac{}{7}=- \\ \hline\end{array}

2(0-3)^{-1}

(1.25 \times 10^{-6})^2 \times (4.8 \times 10^{5})

\begin{array}{l}12-8+6=10 \\ 3 x^{3}-8+2 x^{3}=10 \\ -8 \quad+8 \\ 4 x+2 x \\ 6 x=18 \\ 6 / 6 \\ x=3\end{array}

\newline

1

) Nilai hasil statistik I mahasista fakultas Psikologi adalah seperti di bawah ini:

\newline

\begin{array}{l} 90,100,55,62,87,30,55,65,60,95,100,10,74,76,37,25,20,10,0,100 \\ 62,34,40,75,82,96,81,10,25,47,63,18,0,14,50,55,67,95,83,75,47,30 \end{array}

\newline

a. Tentukan Nilai Median, Kuartil

1

3

, dan tentukan berapa besar modusnya?

\newline

1

) di atas, dosen statistik menentukan kriteria nilai sebagai berikut:

\newline

Mendapat A dengan prosentase antara

81 \%-100 \%

\newline

\checkmark

Mendapat B dengan prosentase antara

61 \%-80 \%

\newline

\checkmark

C

dengan prosentase antara

41 \%-60 \%

\newline

\checkmark

\mathrm{D}

dengan prosentase antara

21 \%-40 \%

\newline

\checkmark

Mendapat E dengan prosentase antara

\checkmark

0

\newline

b. Tentukan batas nilai dari nilai

\checkmark

1

, dan berapa orang yang mendapat masingmasing nilai

\checkmark

2

\checkmark

3

1200

300

150

600

4

-6

150

600

4

150

600

2

1200

300

-1

150

600

3

1

1200

300

150

600

\newline

Instruction: Add/subtract integers together. Don't forget the signs.

\newline

\begin{array}{l} 3+(-8)=\square \quad(-9)-(-4)=\square 7-5=\square \\ 6-(-4)=\square(-4)-(-2)=\square(-4)-10=\square \\ 6-5= \\ (-2)-5= \\ (-2)-7= \\ (-8)+(-2)=\square 8+6=\square(-9)+10=\square \\ 8+(-10)=\square 2-(-10)=\square \quad 8-5=\square \\ 8-(-2)=\square \quad 1-(-7)=\square \quad 4+2=\square \\ (-2)+6= \\ (-4)-4= \\ \square \\ 9-(-7)=\square \\ (-1)-0= \\ 7-5= \\ (-5)+(-10)= \\ (-1)-(-2)= \\ (-5)-(-6)= \\ 9-(-9)= \\ 7-4= \\ (-2)+5= \\ \end{array}

\newline

(-4)-(-10)=

y=4(x+3)^2-8

x

\newline

\dfrac{-2x-5}{5x-3} + \dfrac{6x-16}{6-10x} = \dfrac{-1}{2}

Which is equal to

\frac{1}{7^4}

\newline

\newline

-7^4

\newline

7^{-4}

\newline

-\frac{1}{7^{-4}}

\newline

-(-7)^4

Which is equal to

\frac{1}{6^3}

\newline

\newline

-6^3

\newline

6^{-3}

\newline

(-6)^{-3}

\newline

-\frac{1}{(-6)^{-3}}

Which is equal to

\frac{1}{4^7}

\newline

\newline

\frac{1}{(-4)^7}

\newline

\frac{1}{(-4)^{-7}}

\newline

4^{-7}

\newline

-4^7

Which is equal to

\frac{1}{9^9}

\newline

\newline

9^{-9}

\newline

9^9

\newline

(-9)^{-9}

\newline

-\frac{1}{(-9)^{-9}}

Which is equal to

\frac{1}{7^5}

\newline

\newline

-(-7)^5

\newline

7^5

\newline

-7^5

\newline

7^{-5}

Which is equal to

\frac{1}{4^6}

\newline

\newline

-(-4)^6

\newline

\frac{1}{4^{-6}}

\newline

-4^6

\newline

4^{-6}

(4^{-2} \times 4^{-3})^{3}

1

4 x^{3}-2 x^{2}+1

7 x^{2}+12 x