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(
−
10
)
−
(
14
)
=
(
3
)
−
(
18
)
=
(
19
)
+
(
−
19
)
=
(
−
27
)
−
(
−
25
)
=
(
38
)
−
(
20
)
=
(
10
)
+
(
−
16
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=
(
−
21
)
+
(
7
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=
(
−
11
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+
(
−
13
)
=
(
21
)
+
(
16
)
=
(
−
6
)
+
(
−
1
)
=
\begin{array}{c}(-10)-(14)= \\ (3)-(18)= \\ (19)+(-19)= \\ (-27)-(-25)= \\ (38)-(20)= \\ (10)+(-16)= \\ (-21)+(7)= \\ (-11)+(-13)= \\ (21)+(16)= \\ (-6)+(-1)=\end{array}
(
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10
)
−
(
14
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=
(
3
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−
(
18
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=
(
19
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+
(
−
19
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=
(
−
27
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−
(
−
25
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=
(
38
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−
(
20
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=
(
10
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+
(
−
16
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(
−
21
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+
(
7
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=
(
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+
(
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=
(
21
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+
(
16
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=
(
−
6
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+
(
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1
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=
View step-by-step help
Home
Math Problems
Calculus
Find higher derivatives of rational and radical functions
Full solution
Q.
(
−
10
)
−
(
14
)
=
(
3
)
−
(
18
)
=
(
19
)
+
(
−
19
)
=
(
−
27
)
−
(
−
25
)
=
(
38
)
−
(
20
)
=
(
10
)
+
(
−
16
)
=
(
−
21
)
+
(
7
)
=
(
−
11
)
+
(
−
13
)
=
(
21
)
+
(
16
)
=
(
−
6
)
+
(
−
1
)
=
\begin{array}{c}(-10)-(14)= \\ (3)-(18)= \\ (19)+(-19)= \\ (-27)-(-25)= \\ (38)-(20)= \\ (10)+(-16)= \\ (-21)+(7)= \\ (-11)+(-13)= \\ (21)+(16)= \\ (-6)+(-1)=\end{array}
(
−
10
)
−
(
14
)
=
(
3
)
−
(
18
)
=
(
19
)
+
(
−
19
)
=
(
−
27
)
−
(
−
25
)
=
(
38
)
−
(
20
)
=
(
10
)
+
(
−
16
)
=
(
−
21
)
+
(
7
)
=
(
−
11
)
+
(
−
13
)
=
(
21
)
+
(
16
)
=
(
−
6
)
+
(
−
1
)
=
Solve First Problem:
First, let's solve
(
−
10
)
−
(
14
)
(-10) - (14)
(
−
10
)
−
(
14
)
.
\newline
−
10
−
14
=
−
24
-10 - 14 = -24
−
10
−
14
=
−
24
.
Calculate Next Subtraction:
Next, calculate
(
3
)
−
(
18
)
(3) - (18)
(
3
)
−
(
18
)
.
\newline
3
−
18
=
−
15
3 - 18 = -15
3
−
18
=
−
15
.
Find Result of Addition:
Now, find the result of
(
19
)
+
(
−
19
)
(19) + (-19)
(
19
)
+
(
−
19
)
.
\newline
19
+
(
−
19
)
=
0
19 + (-19) = 0
19
+
(
−
19
)
=
0
.
Compute Negative Numbers:
Let's do
(
−
27
)
−
(
−
25
)
(-27) - (-25)
(
−
27
)
−
(
−
25
)
next.
−
27
−
(
−
25
)
=
−
27
+
25
=
−
2
-27 - (-25) = -27 + 25 = -2
−
27
−
(
−
25
)
=
−
27
+
25
=
−
2
.
Calculate Subtraction:
Now, compute
(
38
)
−
(
20
)
(38) - (20)
(
38
)
−
(
20
)
.
\newline
38
−
20
=
18
38 - 20 = 18
38
−
20
=
18
.
Addition Operation:
Next up,
(
10
)
+
(
−
16
)
(10) + (-16)
(
10
)
+
(
−
16
)
.
10
+
(
−
16
)
=
−
6
10 + (-16) = -6
10
+
(
−
16
)
=
−
6
.
Calculate Negative Sum:
Let's calculate
(
−
21
)
+
(
7
)
(-21) + (7)
(
−
21
)
+
(
7
)
.
\newline
−
21
+
7
=
−
14
-21 + 7 = -14
−
21
+
7
=
−
14
.
Solve Negative Addition:
Now, solve
(
−
11
)
+
(
−
13
)
(-11) + (-13)
(
−
11
)
+
(
−
13
)
.
\newline
−
11
+
(
−
13
)
=
−
24
-11 + (-13) = -24
−
11
+
(
−
13
)
=
−
24
.
Find Sum of Two Numbers:
Next, find the sum of
(
21
)
+
(
16
)
(21) + (16)
(
21
)
+
(
16
)
.
\newline
21
+
16
=
37
21 + 16 = 37
21
+
16
=
37
.
Calculate Negative Addition:
Finally, calculate
(
−
6
)
+
(
−
1
)
(-6) + (-1)
(
−
6
)
+
(
−
1
)
.
\newline
−
6
+
(
−
1
)
=
−
7
-6 + (-1) = -7
−
6
+
(
−
1
)
=
−
7
.
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The second derivative of the function
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cos
(
2
x
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f^{\prime \prime}(x)=x^{2}-5 \cos (2 x)
f
′′
(
x
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=
x
2
−
5
cos
(
2
x
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for
−
2.5
<
x
<
3.5
-2.5<x<3.5
−
2.5
<
x
<
3.5
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x
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f
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3
3
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\newline
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x
=
x=
x
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f
′
(
x
)
=
12
e
x
and
f
(
4
)
=
−
16
+
12
e
4
.
f
(
0
)
=
\begin{array}{l}f^{\prime}(x)=12 e^{x} \text { and } f(4)=-16+12 e^{4} . \\ f(0)=\end{array}
f
′
(
x
)
=
12
e
x
and
f
(
4
)
=
−
16
+
12
e
4
.
f
(
0
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=
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2
−
6
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=
x
2
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g
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x
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=
x
2
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=
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g
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h
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(
x
)
\newline
9
9
9
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\newline
h
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x
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=
x
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x
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x
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h
⋅
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x
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\begin{array}{l} h(x)=x^{2}+x \\ g(x)=3 x+5 \\ \text { Find }(h \cdot g)(x) \end{array}
h
(
x
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=
x
2
+
x
g
(
x
)
=
3
x
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5
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h
⋅
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(
x
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Question
Factor completely:
\newline
8
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3
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27
m
6
8 c^{3}+27 m^{6}
8
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3
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27
m
6
\newline
Answer:
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