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{:[-(1)/(2)z^(3)=-108],[z=◻]:}

−12z3=−108z=□ \begin{array}{l}-\frac{1}{2} z^{3}=-108 \\ z=\square\end{array}

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Find the vertex of the transformed functionright chevron icon

Full solution

Q. −12z3=−108z=□ \begin{array}{l}-\frac{1}{2} z^{3}=-108 \\ z=\square\end{array}
  1. Isolate z3z^3: First, let's isolate z3z^3 by multiplying both sides by −2-2.\newline−2×(−(12)z3)=−2×(−108)-2 \times (-(\frac{1}{2})z^3) = -2 \times (-108)\newlinez3=216z^3 = 216
  2. Find cube root of 216216: Now, we need to find the cube root of 216216 to find zz.\newlinez=2161/3z = 216^{1/3}\newlinez=6z = 6

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