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-1*(1+(x^(2)+1)/(y))=

$-1 \cdot\left(1+\frac{x^{2}+1}{y}\right)=$

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Powers with negative bases

Full solution

Q.

-1 \cdot\left(1+\frac{x^{2}+1}{y}\right)=

Distribute $-1$ : Distribute the $-1$ to both terms inside the parentheses. $\newline$ $-1 \times (1) + -1 \times \left(\frac{x^2 + 1}{y}\right)$
Multiply $-1$ by $1$ : Multiply $-1$ by $1$ . $\newline$ $-1 \times 1 = -1$
Multiply $-1$ by second term: Multiply $-1$ by the second term. $\newline$ $-1 \times \left(\frac{x^2 + 1}{y}\right) = -\frac{x^2 + 1}{y}$
Combine results: Combine the results from Step $2$ and Step $3$ . $\newline$ $-1 - \frac{x^2 + 1}{y}$
Simplify expression: Simplify the expression. $\newline$ Final Answer: $-1 - \frac{x^2 + 1}{y}$

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