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Interpret confidence intervals for population means

FSPotW Week 33 (1111).PNG\newlineFuneral Services Problem of the Week\newlineInvoice\newlineYou're about to give the following invoice\newlineNVOICENO: 123456123456\newlineDATE:\newlineto a customer, but the\newlinecomputer has been giving weird totals lately\newline\newlineP.O. NUMBER\newlineTERMS\newlinePROJECT\newline\newline\newlineThe computer says that this customer owes \newline$5,068.13\$5,068.13.\newlineExplain at least two places where the computer could have made a mistake.\newlineSupport your answer with numbers from\newlineBill to:\newlineMr. customer 13001300 Goodceal Lane New Orleans, LA 7011370113\newlineML\newlineIR\newlineMinx Le...\newlineIsaac Ra.\newlineKT\newlineCamerón...\newlineKeshawt\newlineJG\newlineKT\newline\newlineQUANTITY\newlineRATE\newlineAMOUNT\newline\newline11\newlineTransportation (hearse)\newline$50.00\$50.00\newline$50.00\$50.00\newline\newline11\newlineGravesite\newline$2,345.25\$2,345.25\newline$2,345.25\$2,345.25\newline\newline11\newlineFieldstone - 1818 Gauge Steel Casket\newline$1,095.00\$1,095.00\newline$1,095.00\$1,095.00\newline\newline11\newlineTax\newline$76.65\$76.65\newline$76.65\$76.65\newline\newline88\newlineFlower Arrangements\newline$25.50\$25.50\newline$50.00\$50.0000\newline\newline99.2525\newlineHourly staff\newline$50.00\$50.0011\newline$50.00\$50.0022\newline\newline11\newlinePartial refund on gravesite from town\newline($50.00\$50.0033)\newline($50.00\$50.0033)\newline\newline6060\newlineMemorial printed cards\newline$50.00\$50.0055\newline$50.00\$50.0066\newline\newline55\newlineEmbalming\newline$50.00\$50.0077\newline$50.00\$50.0088\newline\newline\newlinethe invoice.
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A simple random sample of size n=14 n=14 is obtained from a population with μ=69 \mu=69 and σ=16 \sigma=16 .\newline(a) What must be true regarding the distribution of the population in order to use the normal model to compute probabilities involving the sample mean? Assuming that this condition is true, describe the sampling distribution of xˉ \bar{x} .\newline(b) Assuming the normal model can be used, determine P(xˉ<73.4) P(\bar{x}<73.4) .\newline(c) Assuming the normal model can be used, determine P(x≥70.7) P(x \geq 70.7) .\newline(a) What must be true regarding the distribution of the population?\newlineA. Since the sample size is large enough, the population distribution doe need to be normal.\newlineB. The sampling distribution must be assumed to be normal.\newlineC. The population must be normally distributed.\newlineD. The population must be normally distributed and the sample size must be large.\newlineAssuming the normal model can be used, describe the sampling distribution xˉ \bar{x} . Choose the correct answer below.\newlineA. Normal, with μxˉ=69 \mu_{\bar{x}}=69 and σxˉ=16 \sigma_{\bar{x}}=16 \newlineB. Normal, with μxˉ=69 \mu_{\bar{x}}=69 and μ=69 \mu=69 00\newlineC. Normal, with μxˉ=69 \mu_{\bar{x}}=69 and μ=69 \mu=69 22\newline(b) μ=69 \mu=69 33 μ=69 \mu=69 44 (Round to four decimal places as needed.)
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DeltaMath\newline←\leftarrow Back to Home\newline44/1919 Basics of Polar Coordinates\newlineDue: April 2626 at 1111:5959 PM\newlineGrade: \newline6767%\newline✓\checkmark Polar Coordinates to Rectangular Form\newline✓\checkmark Rectangular Coordinates to Polar Form\newline✓\checkmark Graphing Polar Curves\newline✓\checkmark Tangent Lines to Polar Curves\newlineInterpreting Polar Derivatives\newlineAbsolute Extreme Values in Polar\newlineCalculator\newlineTroy Martinez\newlineLog Out\newlineInterpreting Polar Derivatives\newlineScore: \newline00//55\newlinePenalty: none\newlineQuestion\newlineShow Examples\newlineA curve is described by the equation in polar coordinates \newliner=2cos⁡θr=2\cos \theta. Determine \newliney(θ)y(\theta) and \newlinedydθ\frac{dy}{d\theta} when \newlineθ=4π3\theta=\frac{4\pi}{3} and answer the analysis question below. Write your answers as exact values or rounded to three decimal places.\newlineAnswer Attempt 11 out of 22\newliney(θ)=□(4π3),=□ dydθ=□,dydθ∣θ=4π3=□ ＂Based on the above information, the curve is moving ＂, the undefined when θ=4π3:\begin{array}{l} y(\theta)\quad=\square\left(\frac{4\pi}{3}\right),=\square \ \frac{dy}{d\theta}\quad=\square,\left.\frac{dy}{d\theta}\right|_{\theta=\frac{4\pi}{3}}=\square \ \text{＂Based on the above information, the curve is moving ＂},\overrightarrow{\text{ the }} \text{ when }\theta=\frac{4\pi}{3}: \end{array}\newlineBased on the above information, the curve is moving the when \newlineθ=4π3\theta=\frac{4\pi}{3} since \newline✓\checkmark11\newline✓\checkmark22 \newline✓\checkmark11\newlineSubmit Answer
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lath To Do, i-Ready\newlineBeanstack: Reading Chall\newlinemath\newlineSS\newlineELA\newlineScience\newlineCTE\newlineDesmos | Graphing Calcu\newline11.com/student/dashboard/home\newlineistant future\newlineOxford Block Teach.\newlineClasswork for Yello...\newlineJean wants to invest a gift of $4,250 \$ 4,250 in the stock market. A broker suggests two companies, Solar Solutions (SOLR) and Frontline Medical (FLMD). He provides the probabilities for an annual return on $4,250 \$ 4,250 based on their historical gains:\newlineSOLR: 50% 50 \% chance of $1,000 \$ 1,000 gain, 35% 35 \% chance of $200 \$ 200 gain, 15% 15 \% chance of $600 \$ 600 loss.\newlineFLMD: 80% 80 \% chance of $750 \$ 750 gain, $4,250 \$ 4,250 00 chance of $4,250 \$ 4,250 11 loss.\newlineWhich is the best analysis of these investments?
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ANGLES, PARALLEL LINES \& PRACTICE\newlineANGLES, PARALLEL LINES \& TRANSVERSALS\newlineDirections: Use the diagram to answer the following questions.\newlineTypes of Angles:\newline11. Name one pair of corresponding angles.\newline22. Name one pair of vertical angles.\newline33. Name one pair of supplementary angles. \qquad 44. List the two pairs of alternate interior angles. \qquad \newline55. List all exterior angles. \qquad \newlineAngle Measurements:\newline11. If ∠2 \angle 2 is 120∘ 120^{\circ} , what is the measure of ∠1 \angle 1 ? \qquad \newline22. If ∠6 \angle 6 is 112∘ 112^{\circ} , what is the measure of ∠8 \angle 8 ? \qquad \newline33. If ∠8 \angle 8 is \qquad 22, what is the measure of \qquad 33 ? \qquad \newline44. If \qquad 55 is \qquad 66, what is the measure of \qquad 77 ? \qquad \newline55. If \qquad 33 is \qquad 00, what is the measure of \qquad 11 ? \qquad \newline66. If ∠2 \angle 2 is \qquad 44, what is the measure of all other angles?\newline∠1=∠2=∠3=∠4=∠5=∠6=∠7=∠8= \begin{array}{ll} \angle 1= & \angle 2= \\ \angle 3= & \angle 4= \\ \angle 5= & \angle 6= \\ \angle 7= & \angle 8= \end{array} \newline \qquad \newline \qquad \newline \qquad \newline \qquad \newline \qquad
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There are two spinners containing only white and orange slices.\newlineSpinner A has 44 white slices and 11 orange slice.\newlineAll the slices are the same size.\newlineSpinner B has 1212 white slices and 44 orange slices.\newlineAll the slices are the same size.\newlineEach spinner is spun.\newlineList these events from least likely to most likely.\newlineEvent 11: Spinner B lands on a white slice.\newlineEvent 22: Spinner A lands on a white slice.\newlineEvent 33: Spinner B lands on a white or orange slice.\newlineEvent 44: Spinner A \mathrm{A} lands on an orange slice.\newline\begin{tabular}{|c|c|c|c|}\newline\hline Least likely & & ⟶ \longrightarrow & Most likely \\\newline\hline Event 44 & Event 44 & Event 22 & Event 33 \\\newline\hline\newline\end{tabular}
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Data Analysis and Probability\newlineUnderstanding Iikelihood\newlineSadie\newlineEspañol\newlineThere are two boxes containing only red and black pens.\newlineBox A \mathbf{A} has 44 black pens and 44 red pens.\newlineBox B \mathbf{B} has 55 black pens and 1515 red pens.\newlineA pen is randomly chosen from each box.\newlineList these events from least likely to most likely.\newlineEvent 11: choosing an orange pen from Box B B .\newlineEvent 22: choosing a black pen from Box B.\newlineEvent 33: choosing a black or red pen from Box A.\newlineEvent 44: choosing a black pen from Box A.\newline\begin{tabular}{|c|c|c|}\newline\hline Least likely & ⟶ \longrightarrow & Most likely \\\newline\hline Event [్] & Event □ \square , Event □ \square & Event □ \square \\\newline\hline\newline\end{tabular}
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Clover IF × \times | F Education x x \newlineTopie Hi:\newlineClever\newlineMLAQue x x \newlineIMLÁQu\newlineProblem\newlineUSE AS R\newlinepwcs.instructure.com/courses/312966312966/assignments/1784396817843968\newline20232023/20242024 YEM\newlinePWCS\newlineHome\newlineAnnouncements\newlineAssignments\newlineClever\newlineDesmos Scientific Calculator\newlineMastery Tracker\newlineModules\newlineQuizzes\newlineGet Help on Paper\newlineRubin Emerge MS\newlineZoom - New\newlineCanva for Education\newlineNewsela (LTI 11.33)\newlineBook Creator\newlinePook Creator\newlineDue Apr 1616 by 1212:3434pm Points 1717 Submitting an external tool Attempts 00 Allowed Attempts\newlineAvailable Mar 1616 at 99:3838am - Apr 2424 at 99:3535am\newlineThe list shows the test scores of students on a math test.\newline84,95,76,84,87,90,93,81,57,78,85,92 84,95,76,84,87,90,93,81,57,78,85,92 \newlineWhich box plot displays the information?\newlineType here to search\newline(11)
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a. Explain the following terms\newlinei. Mean\newlineii. Median\newlineiii. Mode\newlineiv. Standard Deviation\newlineb. The data below shows the marks scored by 4040 students in a class.\newline\begin{tabular}{lllll}\newline1515 & 1212 & 1515 & 2222 & 2828 \\\newline3030 & 1919 & 2525 & 2424 & 2828 \\\newline1010 & 1515 & 1616 & 2020 & 2626 \\\newline2222 & 1818 & 2020 & 2727 & 1414\newline\end{tabular}\newline7070 | Pag e\newline\begin{tabular}{lllll}\newline1212 & 1919 & 2121 & 1818 & 1919 \\\newline3030 & 1313 & 1010 & 2121 & 2424 \\\newline1515 & 2020 & 2222 & 1818 & 2020 \\\newline1212 & 2323 & 2929 & 2222 & 2424\newline\end{tabular}\newlinei. Convert this data into a grouped frequency distribution using class intervals 10−14,15− 10-14,15- 1919 , etc.\newlineii. Use your table to compute each of the following:\newlinei. Mean\newlineii. Median\newlineiii. Mode\newlineiv. Standard Deviation
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a. Explain the following terms\newlinei. Mean\newlineii. Median\newlineiii. Mode\newlineiv. Standard Deviation\newlineb. The data below shows the marks scored by 4040 students in a class.\newline\begin{tabular}{lllll}\newline1515 & 1212 & 1515 & 2222 & 2828 \\\newline3030 & 1919 & 2525 & 2424 & 2828 \\\newline1010 & 1515 & 1616 & 2020 & 2626 \\\newline2222 & 1818 & 2020 & 2727 & 1414\newline\end{tabular}\newline7070\newlinePag e\newline\begin{tabular}{lllll}\newline1212 & 1919 & 2121 & 1818 & 1919 \\\newline3030 & 1313 & 1010 & 2121 & 2424 \\\newline1515 & 2020 & 2222 & 1818 & 2020 \\\newline1212 & 2323 & 2929 & 2222 & 2424\newline\end{tabular}\newlinei. Convert this data into a grouped frequency distribution using class intervals 10−14,15 10-14,15 1919. etc.\newlineii. Use your table to compute each of the following:\newlinei. Mean\newlineii. Median\newlineiii. Mode\newlineiv. Standard Deviation
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Suppose that an airplane is asked to stay in a holding pattern near an airport. The distance of the plane to the airport is described by the following.\newlined(t)=132+66sin⁡(2π11t)d(t)=132+66 \sin\left(\frac{2\pi}{11}t\right)\newlineIn this equation, \newlined(t)d(t) is the distance of the plane to the airport (in miles), and \newlinett is the time (in minutes) after the plane enters the holding pattern.\newlineDuring the first 1111 minutes after the plane enters the holding pattern, when will the plane be 170170 miles from the airport?\newlineDo not round any intermediate computations, and round your answer(s) to the nearest hundredth of a minute. (If there is more than one answer, enter additional answers with the ＂or＂ button.)\newlinet=t=◻＂ minutes ＂◻＂ or ＂
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Import favorites\newlineMVNU Students Ho...\newlineA\newlineALEKS - Jameson C...\newlineTrigonometric Identities and Equations\newlineSolving a trigonometric equation modeling a real-world situation\newlineJameson\newlineEspañol\newlineSuppose that an airplane is asked to stay in a holding pattern near an airport. The distance of the plane to the airport is described by the following.\newlined(t)=132+66sin⁡(2π11t) d(t)=132+66 \sin \left(\frac{2 \pi}{11} t\right) \newlineIn this equation, d(t) d(t) is the distance of the plane to the airport (in miles), and t t is the time (in minutes) after the plane enters the holding pattern.\newlineDuring the first 1111 minutes after the plane enters the holding pattern, when will the plane be 170170 miles from the airport?\newlineDo not round any intermediate computations, and round your answer(s) to the nearest hundredth of a minute. (If there is more than one answer, enter additional answers with the
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A school district wanted to compare ACT scores between two of its schools (school A and school B). The dotplots below summarize the ACT scores for simple random samples of 3030 students from each school.\newlineACT Scores\newlineThe median score was 2222 for both samples. Which of the following statements is true about the mean ACT for each sample?\newlineThe mean score for the sample from school A \mathrm{A} is equal to the mean score for the sample from school B.\newlineThe mean score for the sample from school A \mathrm{A} is less than the mean score for the sample from school B.\newlineThe mean score for the sample from school A \mathrm{A} is greater than the mean score for the sample from school B.\newlineWe cannot determine the relationship between the mean ACT scores without knowing the actual scores on the exam.
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The following data represent the number of games played in each series of an annual tournament from 19231923 to 20192019 . Complete parts (a) through (d) below.\newline\begin{tabular}{|c|c|c|c|c|}\newline\hline x \mathbf{x} (games played) & 44 & 55 & 66 & 77 \\\newline\hline Frequency & 1919 & 2222 & 2222 & 3333 \\\newline\hline\newline\end{tabular}\newline(a) Construct a discrete probability distribution for the random variable X X .\newline\begin{tabular}{|c|c|}\newline\hline X \mathbf{X} (games played) & P(x) \mathbf{P}(\mathbf{x}) \\\newline\hline 44 & 00.19791979 \\\newline\hline 55 & 00.22922292 \\\newline\hline 66 & 00.22922292 \\\newline\hline 77 & 00.34383438 \\\newline\hline\newline\end{tabular}\newline(Round to four decimal places as needed.)\newline(b) Graph the discrete probability distribution. Choose the correct graph below.\newlineA.\newlineB B .\newlineC.\newlinexD, \mathbf{x}_{\mathrm{D},} \newline(c) Compute and interpret the mean of the random variable X X .\newlineμX=□ game(s)  \mu_{\mathrm{X}}=\square \text { game(s) } \newline(Round to one decimal place as needed.)
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You may need to use the appropriate technology to answer this question.\newlineTourism is extremely important to the economy of Florida. Hotel occupancy is an often-reported measure of visitor volume and visitor activity. Hotel occupancy data for February in two consecutive years are as follows.\newline\begin{tabular}{|l|c|c|}\newline\hline & Current Year & Previous Year \\\newline\hline \begin{tabular}{l} \newlineOccupied \\\newlineRooms\newline\end{tabular} & 11,470470 & 11,440440 \\\newline\hline \begin{tabular}{l} \newlineTotal \\\newlineRooms\newline\end{tabular} & 11,750750 & 11,800800 \\\newline\hline\newline\end{tabular}\newlineprevious year.)\newlineH0:p1−p2≠0 H_{0}: p_{1}-p_{2} \neq 0 Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 \newlineH0:p1−p2=0 H_{0}: p_{1}-p_{2}=0 \newlineHa:p1−p2≠0 H_{\mathrm{a}}: p_{1}-p_{2} \neq 0 \newlineH0:p1−p2≤0 H_{0}: p_{1}-p_{2} \leq 0 \newlineHa:p1−p2>0 H_{\mathrm{a}}: p_{1}-p_{2}>0 \newlineH0:p1−p2<0 H_{0}: p_{1}-p_{2}<0 \newlineHa:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 \newlineH0:p1−p2≥0 H_{0}: p_{1}-p_{2} \geq 0 Ha:p1−p2<0 H_{\mathrm{a}}: p_{1}-p_{2}<0 \newline(b) What is the estimated proportion of hotel rooms occupied each year?\newlinecurrent Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 00\newlineprevious Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 00\newline(c) Calculate the test statistic. (Round your answer to two decimal places.)\newlineHa:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 00\newlineWhat is the Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 33-value? (Round your answer to four decimal places.)\newlineHa:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 33-value Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 55 Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 00\newlineUsing a 00.0505 level of significance, what is your hypothesis test conclusion?
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You may need to use the appropriate technology to answer this question.\newline\begin{tabular}{|l|c|c|}\newline\hline & Current Year & Previous Year \\\newline\hline \begin{tabular}{l} \newlineOccupied \\\newlineRooms\newline\end{tabular} & 11,470470 & 11,440440 \\\newline\hline \begin{tabular}{l} \newlineTotal \\\newlineRooms\newline\end{tabular} & 11,750750 & 11,800800 \\\newline\hline\newline\end{tabular}\newlineprevious year.)\newlineH0:p1−p2≠0 H_{0}: p_{1}-p_{2} \neq 0 \newlineHa:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 \newlineH0:p1−p2=0 H_{0}: p_{1}-p_{2}=0 \newlineHa:p1−p2≠0 H_{\mathrm{a}}: p_{1}-p_{2} \neq 0 \newlineH0:p1−p2≤0 H_{0}: p_{1}-p_{2} \leq 0 \newlineHa:p1−p2>0 H_{\mathrm{a}}: p_{1}-p_{2}>0 \newlineH0:p1−p2<0Ha:p1−p2=0H0:p1−p2≥0Ha:p1−p2<0 \begin{array}{l} H_{0}: p_{1}-p_{2}<0 \\ H_{\mathrm{a}}: p_{1}-p_{2}=0 \\ H_{0}: p_{1}-p_{2} \geq 0 \\ H_{\mathrm{a}}: p_{1}-p_{2}<0 \end{array} \newline(b) What is the estimated proportion of hotel rooms occupied each year?\newlinecurrent\newlineprevious\newline□ \square \newline□ \square \newline(c) Calculate the test statistic. (Round your answer to two decimal places.)\newline□ \square \newlineWhat is the p p -value? (Round your answer to four decimal places.)\newlinep p -value Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 11 □ \square \newlineUsing a 00.0505 level of significance, what is your hypothesis test conclusion?\newlineReject Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 33. There is insufficient evidence to conclude that there has been an increase in the hotel occupancy rate.\newlineDo not reject Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 33. There is sufficient evidence to conclude that there has been an increase in the hotel occupancy rate.\newlineDo not reject Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 33. There is insufficient evidence to conclude that there has been an increase in the hotel occupancy rate.\newlineReject Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 33. There is sufficient evidence to conclude that there has been an increase in the hotel occupancy rate.\newline(d) What is the Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 77 confidence interval estimate of the change in occupancy for the one-year period? (Round your answers to four decimal places.)\newline□ \square to □ \square \newlineDo you think area officials would be pleased with the results?\newlineThe Ha:p1−p2=0 H_{\mathrm{a}}: p_{1}-p_{2}=0 77 confidence interval\newlineH0:p1−p2=0 H_{0}: p_{1}-p_{2}=0 11\newline--Select--zero. This suggests that the occupancy rates for the current year are H0:p1−p2=0 H_{0}: p_{1}-p_{2}=0 11\newlineH0:p1−p2=0 H_{0}: p_{1}-p_{2}=0 11 than the occupancy rates for the previous year, therefore the officials would H0:p1−p2=0 H_{0}: p_{1}-p_{2}=0 11\newlineH0:p1−p2=0 H_{0}: p_{1}-p_{2}=0 11 pleased with the results.
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11. What is the median? \qquad \newline22. What are the lower and upper quartiles?\newline2121 and 2929\newline33. What are the lower and upper extremes and the range? \qquad \newline \qquad \newlineFor Exercises 44−8-8, use the data in the chart below.\newline\begin{tabular}{|llllllllll|}\newline\hline \multicolumn{1010}{c|}{ Lengths of Phone Calls ( ( in min⁡) \min ) } \\\newline\hline 1717 & 2121 & 1616 & 2222 & 2424 & 2626 & 1818 & 2828 & 2525 & 2929 \\\newline2121 & 1818 & 1414 & 2323 & 2525 & 1818 & 2626 & 2424 & 2222 & 2323 \\\newline\hline\newline\end{tabular}\newline44. What is the median? \qquad \newline55. What are the lower and upper quartiles? \qquad \newline66. What are the lower and upper extremes and the range? \qquad \newline77. Make a box-and-whisker graph.\newline88. What fractional part of the data is less than 2525 minutes?\newlineQuartiw11\newlineMixed Review\newlineFor 99−10-10, use the data in the chart above for 44−8-8.\newline99. Complete the cumulative frequency\newline1010. Make a line plot for the data. table below for the data.\newline\begin{tabular}{|c|c|c|}\newline\hline \multicolumn{33}{|c|}{ Lengths of Phone Calls } \\\newline\hline Minutes & Frequency & \begin{tabular}{l} \newlineCumulative \\\newlineFrequency\newline\end{tabular} \\\newline\hline 11−15 11-15 & & \\\newline16−20 16-20 & & \\\newline \qquad 00 & & \\\newline \qquad 11 & & \\\newline\hline\newline\end{tabular}\newlinePW3030\newlinePractice
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A poll asked college students in 20162016 and again in 20172017 whether they believed the First Amendment guarantee of freedom of religion was secure of threatened in the country today. In 20162016,20752075 of 31243124 students surveyed said that freedom of religion was secure or very secure. In 20172017,19671967 of 29512951 students surveyed felt this way. Complete parts (a) and (b).\newlinea. Determine whether the proportion of college students who believe that freedom of religion is secure or very secure in this country has changed from 20162016. Use a significance level of 00.0505 .\newlineConsider the first sample to be the 20162016 survey, the second sample to be the 20172017 survey, and the number of sucoesses to be the number of people who believe that freedom of religion is secure or very secure. What are the null and alternative hypotheses for the hypothesis test?\newlineA. H0:p1>p2 H_{0}: p_{1}>p_{2} \newlineB. H0:p1<p2 H_{0}: p_{1}<p_{2} \newlineC.\newlineH0:p1=p2H2=p1>p2 \begin{array}{l} H_{0}: p_{1}=p_{2} \\ H_{2}=p_{1}>p_{2} \end{array} \newlineH2:p1=p2H2:p1=p2 \mathrm{H}_{2}: p_{1}=p_{2} \quad \mathrm{H}_{2}: p_{1}=p_{2} \newlineD.\newlineH0:p1=p2Ha:p1≠p2 \begin{array}{l} H_{0}: p_{1}=p_{2} \\ H_{a}: p_{1} \neq p_{2} \end{array} \newline E. H0:p1=p2H3:p1<p2 \begin{array}{l} \text { E. } \\ \begin{array}{l} H_{0}: p_{1}=p_{2} \\ H_{3}: p_{1}<p_{2} \end{array} \\ \end{array} \newlineF.\newlineH0:p1≠p2H2:p1=p2 \begin{array}{l} H_{0}: p_{1} \neq p_{2} \\ H_{2}: p_{1}=p_{2} \end{array} \newlineIdentify the test statistic.\newlinez=−0.18′ z=-0.18^{\prime} \newline(Round to two decimal places as needed.)\newlineIdentify the p-value.\newlinep p -value =0.847 =0.847 \newline(Round to three decimal places as needed.)\newlineSince the p-value is greater than the significance level of α=0.05 \alpha=0.05 , fail to reject the null hypothesis. There is insufficient evidence to support the claim that the 20162016 proportion is different from the 20172017 proportion.\newlineb. Use the sample data to construct a 95% 95 \% confidence interval for the difference in the proportions of college students in 20162016 and 20172017 who felt freedom of religion was secure or very secure. How does your confidence interval support your hypothesis test conclusion?\newlineThe 95% 95 \% confidence interval is ( −0.026,0.046 -0.026,0.046 ).\newline(Round to three decimal places as needed.)
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The number of chocolate chips in an 1818-ounce bag of chocolate chip cookies is approximately normally distributed with mean 12521252 and standard deviation 129129 chips.\newline(a) What is the probability that a randomly selected bag contains between 11001100 and 15001500 chocolate chips?\newline(b) What is the probability that a randomly selected bag contains fewer than 10501050 chocolate chips?\newline(c) What proportion of bags contains more than 12251225 chocolate chips?\newline(d) What is the percentile rank of a bag that contains 14751475 chocolate chips?\newlineClick the icon to view a table of areas under the normal curve.\newline(a) The probability that a randomly selected bag contains between 11001100 and 15001500 chocolate chips is \newline1252125200 (Round to four decimal places as needed.)
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The number of chocolate chips in an 1818-ounce bag of chocolate chip cookies is approximately normally distributed with mean 12521252 and standard deviation 129129 chips.\newline(a) What is the probability that a randomly selected bag contains between 11001100 and 15001500 chocolate chips?\newline(b) What is the probability that a randomly selected bag contains fewer than 10501050 chocolate chips?\newline(c) What proportion of bags contains more than 12251225 chocolate chips?\newline(d) What is the percentile rank of a bag that contains 14751475 chocolate chips?\newline\# Click the icon to view a table of areas under the normal curve.\newline(a) The probability that a randomly selected bag contains between 11001100 and 15001500 chocolate chips is □ \square (Round to four decimal places as needed.)
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mylab.pearson.com\newlineJessica Anguiano 0404/1616/2424 1111:0202 PM\newlineThis quiz: 2828 point(s)\newlinepossible\newlineThis question: 22\newlineResume later\newlinepoint(s) possible\newlineSubmit quiz\newlineSuppose babies born after a gestation period of 3232 to 3535 weeks have a mean weight of 27002700 grams and a standard deviation of 900900 grams while babies born after a gestation period of 4040 weeks have a mean weight of 33003300 grams and a standard deviation of 455455 grams. If a 3333-week gestation period baby weighs 29252925 grams and a 4141 -week gestation period baby weighs 3525grams 3525 \mathrm{grams} , find the corresponding z \mathrm{z} -scores. Which baby weighs more relative to the gestation period?\newlineFind the corresponding z-scores. Which baby weighs relatively more? Select the correct choice below and fill in the answer boxes to complete your choice.\newline(Round to two decimal places as needed.)\newlineA. The baby born in week 3333 weighs relatively more since its z-score, □ \square , is smallerthan the z z -score of □ \square for the baby born in week 4141 .\newlineB. The baby born in week 3333 weighs relatively more since its z z -score, □ \square , is largerthan the z z -score of □ \square for the baby born in week 4141 .\newlineC. The baby born in week 4141 weighs relatively more since its z z -score, 00.4444 , is smallerthan the z z -score of 00.3333 for the baby born in week 3333 .\newlineD. The baby born in week 4141 weighs relatively more since its z z -score, □ \square is largerthan the z z -score of □ \square for the baby born in week 3333.\newline□ \square \newline□ \square z \mathrm{z} 77\newline
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Classroom 88:1515PM Tue Apr 1616\newlineSavvas Sign In\newlineSavvas Realize\newline11%14 11 \% 14 \newlinesavasrealize.com\newlineOB PREAL\newline66−9-9: MathXL for School: Additional Practice\newlineApr 1717 - 1111:5959 pm\newlinePart 11 of 22\newlineIn the figure, m∠1=(7x+9)∘,m∠2=(4x+14)∘ \mathrm{m} \angle 1=(7 x+9)^{\circ}, \mathrm{m} \angle 2=(4 \mathrm{x}+14)^{\circ} , and m∠4=(12x+12)∘ \mathrm{m} \angle 4=(12 x+12)^{\circ} . Your friend incorrectly says that m∠4=58∘ \mathrm{m} \angle 4=58^{\circ} . What is m∠4 \mathrm{m} \angle 4 ? What mistake might your friend have made?\newline(This figure is not to scale.)\newlinem∠4= \mathrm{m} \angle 4= □ \square □∘ \square^{\circ} \newlineHelp me solve this\newlineView an example\newlineGet more help:\newlineCheck answ\newlineClear all\newlineQuestion 44 of ?\newlineBack\newlineNext\newlineReview Progress
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c) Suppose a bookstore estimates it will sell 4040 copies of the book. How manhy books can, in fact, be ordered for the same prices as those 4040 copies?\newline33. Solve, write your answer using interval notation. ∣4−3t∣−6≥5 |4-3 t|-6 \geq 5 \newline44. While participating in the hammer throw in the Highland Games, the height of the hammer above the ground seconds after it is thrown can be modeled by the function h(t)=−16t2+24.96t+5 h(t)=-16 t^{2}+24.96 t+5 . What is the hammer's maximum height? What is the hammer's total time in the air? Round answers to two decimal places.\newline11. How did you approach learning this material?\newline22. What issues to you feel you need more support in?\newline33. What can I do to support you?\newline44. What might you do differently?
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A local package delivery service wants to improve the efficiency of its deliveries. As a first step, the management team decides to conduct a study to determine the average length of time from the arrival of a package at the company's mail center until its delivery at a home. Which of the following methods is most likely to produce valid results?\newlineChoose 11 answer:\newline(A) The team selects the 11,000000 heaviest packages in a one-week, non-holiday period and records how long it takes for each package to reach its destination.\newline(B) The team calls 11,000000 residents in their delivery area and asks them whether they have received a package from their service in the past week. They will then record how long it took for those packages to reach their destination.\newline(C) The team selects a random sample of 11,000000 packages arriving at the center over a one-week, non-holiday period and records how long it takes for each package to reach its destination.\newline(D) None of the above
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In a study of 4040 randomly selected captive Octopus vulgaris, researchers found that the octopuses could learn to integrate visual and tactile information to find food after a mean of 119119 trials. The estimate had a margin of error of 1818 trials at a 95% 95 \% confidence level. Which of the following is the most reasonable conclusion about the number of trials it would take all captive Octopus vulgaris in general to learn to find the food?\newlineChoose 11 answer:\newline(A) The evidence suggests that half of them would require 119119 or fewer trials.\newline(B) The evidence suggests that the mean number of trials would be 119119 trials.\newline(C) The evidence suggests that the mean number of trials would be between 119119 and 137137 trials.\newline(D) The evidence suggests that the mean number of trials would be between 101101 and 137137 trials.
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In a random survey of US adults, a political scientist found that 56% 56 \% of the survey respondents are confident in the current administration's ability to make good foreign policy decisions. The margin of error for this estimation is 1% 1 \% . Based on this information, which of the following is the most appropriate conclusion?\newlineChoose 11 answer:\newline(A) Exactly 56% 56 \% of US adults are confident that 99% 99 \% of the foreign policy decisions made by the current administration will be good.\newline(B) The political scientist is 99% 99 \% sure that 56% 56 \% of the foreign policy decisions made by the current administration will be good ones.\newline(C) Most US adults believe that 55% 55 \% to 57% 57 \% of the foreign policy decisions made by the current administration will be good ones.\newline(D) It is likely that 55% 55 \% to 57% 57 \% of all US adults are confident in the current administration's ability to make good foreign policy decisions.
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In a survey of smartphone owners, 64% 64 \% of a random sample of younger adults aged 1818−29-29 used their phones to listen to music or podcasts, compared to 21% 21 \% of a random sample of older users who did so. Based on the results of this survey, which of the following conclusions are valid?\newlineI : Younger adults are more likely to listen to music or podcasts on their smartphones than are older adults.\newlineII : Older adults like music less than younger adults.\newlineIII : Older adults do not listen to music on their smartphones because they find it inconvenient.\newlineIV : Younger adults are more likely than older adults to own smartphones.\newlineChoose 11 answer:\newline(A) I only\newline(B) I and II\newline(C) II only\newline(D) I, II, III, and IV
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A study was conducted to compare two biology study aids: a new online game and physical flashcards. 8080 middle school biology students were selected at random, and their parent(s) chose which study aid their child used. The results showed that the students who used flashcards had significantly better outcomes than students who used the online game. Based on this information, which of the following statements is true?\newlineChoose 11 answer:\newline(A) Flashcards are a more effective study aid than the online game for all middle school biology students.\newline(B) The lack of random assignment means there could be other explanations for the study results.\newline(C) The lack of a control group makes comparing flashcards and the online game impossible.\newline(D) None of the statements are true.
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A study was conducted on an elementary school's extracurricular programs. The study divided the students into two groups, those who attended after school electives and those who did not. The results of the study showed that students who attended after school electives were more likely to attend summer camp than students who did not attend these electives. Based on the information provided, which of the following is an appropriate conclusion?\newlineChoose 11 answer:\newline(A) Attending after school electives is a requirement for attending summer camp.\newline(B) After school elective attendance is the strongest predictor of whether a student will attend summer camp.\newline(C) There is a positive association between after school electives attendance and summer camp attendance.\newline(D) If a student stops attending after school electives, then they will not attend summer camp.
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A company wants to study the effects of its new protein shake on muscle gain. 5050 people who exercise regularly and 5050 people who do not exercise regularly were selected for the study. The people who do not exercise regularly were given the shake, while the people who exercise regularly were not. The results showed that, on average, the group that received the shake did not gain any muscle mass. Based on the information provided, which of the following is an appropriate conclusion?\newlineChoose 11 answer:\newline(A) The shake will not help anyone gain muscle mass.\newline(B) The shake can only help people who exercise regularly gain muscle mass.\newline(C) People who do not exercise regularly are likely to gain more muscle mass without the shake than with the shake.\newline(D) None of the conclusions are appropriate.
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A company wants to determine the effectiveness of its Spanish language learning app. The company studied a large random sample of first-year Spanish majors and found that, on average, students who used the app received higher grades in their Spanish classes than students who did not use the app. Based on the design and results of the study, which of the following is an appropriate conclusion?\newlineChoose 11 answer:\newline(A) Using the app will improve the grades of any college student.\newline(B) Using the app will improve the grades of any Spanish major.\newline(C) Using the app is likely to improve the grades of firstyear Spanish majors.\newline(D) There is an association between using the app and higher grades in Spanish classes for first-year Spanish majors, but the effect of using the app is unclear.
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A study was conducted to determine the effect of sulfur on the taste of onions. 200200 onion seeds of the same variety were selected at random. Half of the seeds were randomly assigned to be grown in soil treated to have lower sulfur content, and the other half were grown in untreated soil. In a blind taste test of the onions, tasters indicated that the onion grown in soil with lower sulfur content was sweeter. Based on the information provided, which of the following is a reasonable conclusion?\newlineChoose 11 answer:\newline(A) The variety of onion seeds used produces the sweetest onions.\newline(B) For the variety of onion seeds used, onions grown in soil with lower sulfur content are likely to taste sweeter.\newline(C) Sulfur in soil improves the sugar production of onions.\newline(D) Sulfur content is the only determining factor of onion sweetness.
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A study was conducted to test a feed additive's ability to increase the milk production of dairy cows. 100100 dairy cows between 22 and 33 years of age were selected at random. Half of the cows were randomly assigned to eat feed containing the additive, and the other half ate feed without the additive. The results showed that the cows that ate the additive produced significantly more milk than the cows that did not. Based on this information, which of the following is an appropriate conclusion?\newlineChoose 11 answer:\newline(A) The feed additive will improve the milk production of any dairy cow that eats it.\newline(B) The feed additive is more effective at increasing the milk production of 22- to 33- year old dairy cows than dairy cows in other age groups.\newline(C) The feed additive is likely to increase the milk production of dairy cows between 22 and 33 years old.\newline(D) The feed additive is likely to have no effect on the milk production of dairy cows that are not between 22 and 33 years of age.
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