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Math Problems
Grade 8
Solve multi-step equations with fractional coefficients
12
(
5
+
2
y
)
=
4
y
−
(
5
−
9
y
)
12(5+2y)=4y - (5 - 9y)
12
(
5
+
2
y
)
=
4
y
−
(
5
−
9
y
)
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Solve the equation
2
x
+
7
3
=
2
−
x
4
\frac{2 x+7}{3}=\frac{2-x}{4}
3
2
x
+
7
=
4
2
−
x
.
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Find the solution to this equation.
\newline
−
x
+
2
(
x
+
3
)
=
6
+
x
-x+2(x+3)=6+x
−
x
+
2
(
x
+
3
)
=
6
+
x
\newline
(A) No solution
\newline
(B) All real numbers
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2
x
(
2
x
−
3
)
≥
4
x
2
−
3
(
2
x
+
1
)
2 x(2 x-3) \geq 4 x^{2}-3(2 x+1)
2
x
(
2
x
−
3
)
≥
4
x
2
−
3
(
2
x
+
1
)
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7
3
(
1
2
x
−
10
3
)
=
−
35
3
−
1
2
x
\frac{7}{3}(\frac{1}{2}x - \frac{10}{3}) = \frac{-35}{3} - \frac{1}{2}x
3
7
(
2
1
x
−
3
10
)
=
3
−
35
−
2
1
x
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if
(
3
y
−
5
x
)
/
(
7
x
−
4
y
)
=
3
/
4
(3y -5x)/(7x-4y) = 3/4
(
3
y
−
5
x
)
/
(
7
x
−
4
y
)
=
3/4
, find the value of
x
/
y
x/y
x
/
y
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find all solutions to the equations
15
x
(
x
+
4
)
=
x
+
2
x
+
4
\frac{15}{x(x+4)} = \frac{x+2}{x+4}
x
(
x
+
4
)
15
=
x
+
4
x
+
2
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Solve for
x
x
x
. Express your answer as a proper or improper fraction in simplest terms.
\newline
−
1
4
=
1
5
x
+
1
4
-\frac{1}{4}=\frac{1}{5} x+\frac{1}{4}
−
4
1
=
5
1
x
+
4
1
\newline
Answer:
x
=
x=
x
=
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Solve for
b
b
b
. Express your answer as a proper or improper fraction in simplest terms.
\newline
−
7
8
−
1
8
b
=
−
1
2
-\frac{7}{8}-\frac{1}{8} b=-\frac{1}{2}
−
8
7
−
8
1
b
=
−
2
1
\newline
Answer:
b
=
b=
b
=
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Solve for
m
m
m
.
\newline
4
+
5
m
=
9
m
\sqrt{4 + 5m} = \sqrt{9m}
4
+
5
m
=
9
m
\newline
m
=
m =
m
=
_____
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g
(
x
)
=
2
x
−
1
g(x)=2 x-1
g
(
x
)
=
2
x
−
1
\newline
h
(
x
)
=
3
x
−
1
h(x)=3 x-1
h
(
x
)
=
3
x
−
1
\newline
Find
(
g
+
h
)
(
x
)
(g+h)(x)
(
g
+
h
)
(
x
)
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Simplify.
7
x
−
8
=
3
x
\frac{7}{x}-8=\frac{3}{x}
x
7
−
8
=
x
3
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3
z
−
4
y
=
2
z
−
4.5
3z-4y=2z-4.5
3
z
−
4
y
=
2
z
−
4.5
8
y
=
2
z
+
5
8y=2z+5
8
y
=
2
z
+
5
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solve and find
(
x
+
10
)
(
x
+
10
)
(x+10)(x+10)
(
x
+
10
)
(
x
+
10
)
3
x
−
7
=
11
3x-7=11
3
x
−
7
=
11
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Solve for
a
a
a
.
\newline
4
5
a
−
8
=
a
+
2
\frac{4}{5}a - 8 = a + 2
5
4
a
−
8
=
a
+
2
\newline
a
=
a =
a
=
__
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If
−
2
x
x
−
10
=
−
3
\frac{-2 x}{x-10}=-3
x
−
10
−
2
x
=
−
3
, what is the value of
x
x
x
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
30
-30
−
30
\newline
(B)
−
10
-10
−
10
\newline
(C)
6
6
6
\newline
(D)
30
30
30
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5
x
−
y
=
3
−
5
x
+
2
y
=
4
\begin{aligned} 5x-y&=3 \ -5x+2y&=4 \end{aligned}
5
x
−
y
=
3
−
5
x
+
2
y
=
4
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2
x
+
3
y
=
2
;
4
x
−
9
y
=
−
1
,
x
,
y
>
0
\frac{2}{\sqrt{x}}+\frac{3}{\sqrt{y}}=2 ; \frac{4}{\sqrt{x}}-\frac{9}{\sqrt{y}}=-1, \mathrm{x}, \mathrm{y}>0
x
2
+
y
3
=
2
;
x
4
−
y
9
=
−
1
,
x
,
y
>
0
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log
2
(
4
x
−
3
)
+
log
2
(
3
x
+
5
)
=
3
\log_{2}(4x-3)+\log_{2}(3x+5)=3
lo
g
2
(
4
x
−
3
)
+
lo
g
2
(
3
x
+
5
)
=
3
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Solve the equation:
2
(
x
2
+
x
−
11
)
3
2
=
54
2(x^{2}+x-11)^{\frac{3}{2}}=54
2
(
x
2
+
x
−
11
)
2
3
=
54
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Su respuesta es Incorrecta.
\newline
Resolver para
x
x
x
.
\newline
9
−
5
x
=
1
1
x
−
4
9^{-5x}=11^{x-4}
9
−
5
x
=
1
1
x
−
4
\newline
Redondear la respuesta a la mil\'esima m\'as cercana No redondar los c\'alculos Intermedios.
\newline
x
=
x=
x
=
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8
x
+
3
5
=
2
x
\frac{8 x+3}{5}=2 x
5
8
x
+
3
=
2
x
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Find the difference.
\newline
x
2
−
5
x
2
+
5
x
−
14
−
x
+
3
x
+
7
=
\frac{x^{2}-5}{x^{2}+5 x-14}-\frac{x+3}{x+7}=
x
2
+
5
x
−
14
x
2
−
5
−
x
+
7
x
+
3
=
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Solve for
x
x
x
.
\newline
x
+
7
6
x
+
2
=
2
x
−
1
x
\frac{x+7}{6 x}+2=\frac{2 x-1}{x}
6
x
x
+
7
+
2
=
x
2
x
−
1
\newline
Answer:
x
=
x=
x
=
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Solve for
x
x
x
.
\newline
−
5
3
−
4
3
x
=
−
2
\frac{-5}{3}-\frac{4}{3 x}=-2
3
−
5
−
3
x
4
=
−
2
\newline
Answer:
x
=
x=
x
=
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Solve for
x
\mathrm{x}
x
:
\newline
8
x
−
24
−
15
=
−
11
\sqrt{8 x-24}-15=-11
8
x
−
24
−
15
=
−
11
\newline
Answer:
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Solve the equation
x
2
−
4
x
+
38
=
8
x
+
4
x^{2}-4 x+38=8 x+4
x
2
−
4
x
+
38
=
8
x
+
4
to the nearest tenth.
\newline
Answer:
x
=
x=
x
=
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Solve for all values of
x
x
x
.
\newline
x
−
7
x
+
8
=
3
x
\frac{x-7}{x+8}=\frac{3}{x}
x
+
8
x
−
7
=
x
3
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
:
\newline
(
7
x
−
10
)
2
+
(
7
x
−
10
)
=
0
(7 x-10)^{2}+(7 x-10)=0
(
7
x
−
10
)
2
+
(
7
x
−
10
)
=
0
\newline
Answer:
x
=
x=
x
=
Get tutor help
quality.
−
5
b
+
2
(
b
−
1
)
≥
6
−
(
2
b
−
1
)
+
2
b
-5 b+2(b-1) \geq 6-(2 b-1)+2 b
−
5
b
+
2
(
b
−
1
)
≥
6
−
(
2
b
−
1
)
+
2
b
Get tutor help
Solve for p.
\newline
2
3
p
=
8
9
\frac{2}{3}p = \frac{8}{9}
3
2
p
=
9
8
\newline
p
=
□
p=\square
p
=
□
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Solve
x
2
−
4
=
x
3
+
2
\frac{x}{2}-4=\frac{x}{3}+2
2
x
−
4
=
3
x
+
2
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Solve for
x
\mathrm{x}
x
.
\newline
x
+
3
8
=
x
−
6
5
\frac{x+3}{8}=\frac{x-6}{5}
8
x
+
3
=
5
x
−
6
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
2
−
1
4
=
2
x
−
5
12
2-\frac{1}{4}=\frac{2 x-5}{12}
2
−
4
1
=
12
2
x
−
5
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
−
1
+
5
4
=
2
x
−
5
12
-1+\frac{5}{4}=\frac{2 x-5}{12}
−
1
+
4
5
=
12
2
x
−
5
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
−
7
+
9
2
=
2
x
−
7
6
-7+\frac{9}{2}=\frac{2 x-7}{6}
−
7
+
2
9
=
6
2
x
−
7
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
4
x
+
9
x
−
2
=
3
5
\frac{4 x+9}{x-2}=\frac{3}{5}
x
−
2
4
x
+
9
=
5
3
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
x
+
9
2
=
4
x
−
3
9
\frac{x+9}{2}=\frac{4 x-3}{9}
2
x
+
9
=
9
4
x
−
3
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
5
x
−
1
8
=
5
x
+
7
9
\frac{5 x-1}{8}=\frac{5 x+7}{9}
8
5
x
−
1
=
9
5
x
+
7
\newline
Answer:
Get tutor help
In
△
D
E
F
,
m
∠
D
=
(
10
x
−
13
)
∘
,
m
∠
E
=
(
x
−
4
)
∘
\triangle \mathrm{DEF}, \mathrm{m} \angle D=(10 x-13)^{\circ}, \mathrm{m} \angle E=(x-4)^{\circ}
△
DEF
,
m
∠
D
=
(
10
x
−
13
)
∘
,
m
∠
E
=
(
x
−
4
)
∘
, and
m
∠
F
=
(
2
x
+
15
)
∘
\mathrm{m} \angle F=(2 x+15)^{\circ}
m
∠
F
=
(
2
x
+
15
)
∘
. Find
m
∠
E
\mathrm{m} \angle E
m
∠
E
.
\newline
Answer:
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In
△
B
C
D
,
m
∠
B
=
(
8
x
+
12
)
∘
,
m
∠
C
=
(
3
x
−
17
)
∘
\triangle \mathrm{BCD}, \mathrm{m} \angle B=(8 x+12)^{\circ}, \mathrm{m} \angle C=(3 x-17)^{\circ}
△
BCD
,
m
∠
B
=
(
8
x
+
12
)
∘
,
m
∠
C
=
(
3
x
−
17
)
∘
, and
m
∠
D
=
(
x
+
17
)
∘
\mathrm{m} \angle D=(x+17)^{\circ}
m
∠
D
=
(
x
+
17
)
∘
. Find
m
∠
D
\mathrm{m} \angle D
m
∠
D
.
\newline
Answer:
Get tutor help
In
△
H
I
J
,
m
∠
H
=
(
6
x
+
10
)
∘
,
m
∠
I
=
(
3
x
−
6
)
∘
\triangle \mathrm{HIJ}, \mathrm{m} \angle H=(6 x+10)^{\circ}, \mathrm{m} \angle I=(3 x-6)^{\circ}
△
HIJ
,
m
∠
H
=
(
6
x
+
10
)
∘
,
m
∠
I
=
(
3
x
−
6
)
∘
, and
m
∠
J
=
(
6
x
+
11
)
∘
\mathrm{m} \angle J=(6 x+11)^{\circ}
m
∠
J
=
(
6
x
+
11
)
∘
.
\newline
Find
m
∠
J
\mathrm{m} \angle J
m
∠
J
.
\newline
Answer:
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Solve for
w
\mathrm{w}
w
.
\newline
−
1
=
w
7
-1=\frac{w}{7}
−
1
=
7
w
\newline
Answer:
w
=
w=
w
=
Get tutor help
Solve for
a
a
a
.
\newline
a
0.5
+
2.4
=
−
2.6
\frac{a}{0.5}+2.4=-2.6
0.5
a
+
2.4
=
−
2.6
\newline
Answer:
a
=
a=
a
=
Get tutor help
Rewrite in simplest terms:
−
2
(
4
x
+
1
)
+
6
(
5
x
−
1
)
-2(4 x+1)+6(5 x-1)
−
2
(
4
x
+
1
)
+
6
(
5
x
−
1
)
\newline
Answer:
Get tutor help
Find `x` value from the equation
\newline
3
(
7
−
2
x
)
=
5
(
4
x
+
11
)
3^{(7-2x)}=5^{(4x+11)}
3
(
7
−
2
x
)
=
5
(
4
x
+
11
)
Get tutor help
Evaluate
−
y
+
(
−
z
)
+
7.99
-y+(-z)+7.99
−
y
+
(
−
z
)
+
7.99
where
y
=
1.46
y=1.46
y
=
1.46
and
z
=
3.82
z=3.82
z
=
3.82
.
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Solve for
d
d
d
.
\newline
3
2
=
5
d
−
1
2
\frac{3}{2}=5 d-\frac{1}{2}
2
3
=
5
d
−
2
1
Get tutor help
Solve for
q
q
q
.
\newline
3
(
q
+
4
3
)
=
2
3\left(q+\frac{4}{3}\right)=2
3
(
q
+
3
4
)
=
2
Get tutor help
Solve for
r
r
r
.
\newline
4
r
−
6
r
−
7
=
2
\frac{4 r-6}{r-7}=2
r
−
7
4
r
−
6
=
2
\newline
r
=
r=
r
=
Get tutor help
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