Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Homeright chevron icon
Math Problemsright chevron icon
Grade 6right chevron icon

One-step inequalities: word problems

Example Problem\newlinea. If the cost of direct material is 60% 60 \% , direct labor is 10% 10 \% , and overhead is 25% 25 \% sales, what will be the improvement in profit if cost of direct material is reduced 55% 55 \% ?\newlineb. How much will sales have to increase to give the same increase in profit? (Remembe overhead cost is constant.)\newline\begin{tabular}{|c|c|c|c|c|}\newline\hline \begin{tabular}{l} \newlineANSWER \\\newlinea.\newline\end{tabular} & \multicolumn{22}{|c|}{\begin{tabular}{c} \newlineBefore \\\newlineImprovement\newline\end{tabular}} & \multicolumn{22}{|c|}{\begin{tabular}{c} \newlineAfter \\\newlineImprovement\newline\end{tabular}} \\\newline\hline Revenue (sales) & & 100% 100 \% & & 100% 100 \% \\\newline\hline \multicolumn{55}{|l|}{ Cost of Goods Sold } \\\newline\hline Direct Material & 60% 60 \% & & 55% 55 \% & \\\newline\hline Direct Labor & 10% 10 \% & & 10% 10 \% & \\\newline\hline Overhead & 10% 10 \% 00 & & 25% 25 \% & \\\newline\hline Total Cost of Goods Sold & & 10% 10 \% 22 & & 10% 10 \% 33 \\\newline\hline Gross Profit & & 10% 10 \% 44 & & 10% 10 \% \\\newline\hline\newline\end{tabular}\newlineb. 10% 10 \% 66 Profit 10% 10 \% 77 sales 10% 10 \% 88 direct material + direct labor +00.252510% 10 \% 99\newline= sales −(0.6 sales +0.1 sales +0.25)= sales −0.7 sales −0.250.1=0.3 sales −0.25 \begin{aligned} & =\text { sales }-(0.6 \text { sales }+0.1 \text { sales }+0.25) \\ & =\text { sales }-0.7 \text { sales }-0.25 \\ 0.1 & =0.3 \text { sales }-0.25 \end{aligned} \newline00.33 Sales 25% 25 \% 00\newline Sales =0.350.3=1.17 \text { Sales }=\frac{0.35}{0.3}=1.17 \newlineSales must increase 25% 25 \% 11 to give the same increase in profit.
Get tutor helpright-arrow
44\newline(b) Bank Hosei launch a new air miles credit card*\newlineThe rewands for new sign up are listed below. Mr Choy is a first time sign up and he can either go for Plan C C or Plan D D .\newline\begin{tabular}{|c|c|}\newline\hline \begin{tabular}{l} \newlinePlan C C \\\newline2424 miles for every dollar spent locally\newline\end{tabular} & \begin{tabular}{|l} \newlinePlan D D \\\newlineusing the credit card.\newline\end{tabular} \\\newline\hline \begin{tabular}{l} \newlineOn top of the above, you can get a \\\newlinebonus of 3500035000 miles if you spend a \\\newlineminimum of $1000 \$ 1000 per month using \\\newlinethe credit card for the first two \\\newlineconsecutive months and with an \\\newlineannual fee payment of $235 \$ 235 (subject \\\newlineto 9% 9 \% GST) paid.\newline\end{tabular} & \begin{tabular}{l} \newlineOn top of the above, get a bonus of \\\newline3000030000 miles if you spend a \\\newlineminimum of $500 \$ 500 per month for the \\\newlinefirst two consecutive months with an \\\newlineannual fee waived**.\newline\end{tabular} \\\newline\hline\newline\end{tabular}\newline*air miles credit card allows you to earn miles that you can redeem directly for free flights.\newline** fee waived refers to a bank that agrees to not charge a customer for a service.\newlineMr Choy x x ins to redeem a one-way air ticket to Japan which requires 5500055000 miles.\newline(i) Assume that Mr Choy decides to sign up for Plan C C where he spends $1000 \$ 1000 per month for the first two consecutive months, find the amount of money that he will need to spend using the credit card for the next 66 months so that he can redeem the one-way air ticket to Japan at the end of
Get tutor helpright-arrow
Due Mon, 4/15 4 / 15 \newlineTOPIC 44. CHAPTER TEST so POINTS\newlineNAME Ella Weth MOD 77\newline11. Factor the expression. −5 g+15 h−25 -5 \mathrm{~g}+15 \mathrm{~h}-25 \newline(a pointo)\newlineshow Worke\newline−5(g−3h+5) -5(g-3 h+5) \newline−5(9−3h+5) -5(9-3 h+5) \newline22. Angeline bought s yards of satin fabrio priced at $8.09 \$ 8.09 per yard, and c c yards of cotton fabric at $3.79 \$ 3.79 per yard. What expression could be used to determine the total cost of the fabric?\newline(33 points)\newlineC=8.095+3.79C C=8.095+3.79 \mathrm{C} \newlineIf she bought 55 yards of satin fabric and 88 yards of cotton fabric, how much did Angeline spend in all? Show work.\newlineShow work:\newline8.09(5)+3.796 8.09(5)+3.796 \newlineAnswer:\newline40,45+30,32 40,45+30,32 \newline−5 g+15 h−25 -5 \mathrm{~g}+15 \mathrm{~h}-25 00\newlineWrite an expression that is the product of two factors and is equivalen\newlinepoints)\newline−5 g+15 h−25 -5 \mathrm{~g}+15 \mathrm{~h}-25 11\newline−5 g+15 h−25 -5 \mathrm{~g}+15 \mathrm{~h}-25 22\newlinesitive GCF:\newlineUse a negative GCF: Show worke\newlineGu\newline−5 g+15 h−25 -5 \mathrm{~g}+15 \mathrm{~h}-25 33
Get tutor helpright-arrow
Visual Arts 88A (S22)\newlineJCPS ClassLink\newlineParent Sign In\newlineInbox (22) - zger542542\newlineDeltaMath Student\newlineDesmos | Scientific\newlineBytelearn- AI Math\newlineByteLearn\newlinedeltamath.com/app/student/31470093147009/2322019923220199/ac854854ba11cd4242c5656d99fcd88cb11ea4949eb66a\newlineall\newlinemonkey\newlineBlooket-Cheats/che...\newlineDashboard | Blooket\newlineshopping/camping\newlineList of presidents of...\newline000000\newlineAll Bookmarks\newlineDeltaMath\newline← \leftarrow Back to Home\newlineEOG Review \#11 (22 punches on card)\newlineDue: April 1818 at 11:3030 PM\newlineGrade: 2% 2 \% \newline∙ \bullet \newline□ \square \newlinePythagorean Theorem (Rounding)\newlineSolve Linear System Graphically (Graphs Given)\newlineDetermining Whether an Integer Satisfies an Inequality\newlineMultiply/Divide in Scientific Notation\newlineDetermine if Number is Rational / Irrational\newlineFunction and Relation Mapping Diagrams\newlineMultiply/Divide in Scientific Notation\newlineScore: 0/10 0 / 10 \newlinePenalty: 11 off\newline \qquad \newlineQuestion\newlineShow Examples\newlineWhat is the quotient of 5.688×109 5.688 \times 10^{9} and 7.9×102 7.9 \times 10^{2} expressed in scientific notation?\newlineAnswer Attempt 22 out of 22\newlineAnswer: □ \square \newline□ \square \newline□ \square \newlineSubmit Answer\newlineStill Stuck?\newlineCalculator\newlineZackary Gergis\newlineLog Out\newlineCopyright (9202492024 DeltaMath.com All Rights Reserved.\newlinePrivacy Policy | Terms of Service
Get tutor helpright-arrow
Samat tonyeridge\newlineSmat Restiter\newlinesom/\newlineDUE\newlineApr 11−11:5 11-11: 5 !\newline77 66−2-2: Example 33 \& Try it!\newlineDone\newline66−2-2: MathXL for School;\newlineDone\newline100% 100 \% \newlinePractice \& Problem Solving\newline94% 94 \% \newline66−3-3: MathxL for School:\newlinein Progest\newlinePractice \& Problem Solving\newline66.33: Example 11 \& Try its\newline66.33.PS. 1616\newlineQuestion Help\newlineChallenge A cell phone plan costs $28.80 \$ 28.80 per month for 500500 minutes of talk time. It costs an additional $0.07 \$ 0.07 per minute for each minute over 500500 minutes. To get e-mail access, it costs 10% 10 \% of the price for 500500 minutes of talk time. Your bill, which includes e-mail, is the same each month for 66 months. The total cost for all 66 months is $216.54 \$ 216.54 . Write and solve an equation to find the number of minutes of talk time you use each month. \qquad \newlineLet m m represent the number of minutes over 500500 minutes each month. Which equation represents the given situation?\newlineA. 216.54=6( m+28.80) 216.54=6(\mathrm{~m}+28.80) \newlineB. 100% 100 \% 00\newlineC. 100% 100 \% 11\newlineD. 100% 100 \% 22\newlineYou use 100% 100 \% 33 minutes of talk time each month.\newlineEnter your answer in the answer box and then click Check Answer.\newlineAll parts showing\newlineClear All\newlineCheck Answer\newlineQuestion\newline77\newlineof 88
Get tutor helpright-arrow
Classroom activity (Constructing the 'square root spiral') : Take a large sheet of paper and construct the 'square root spiral' in the following fashion. Start with a point OO and draw a line segment OP1OP_{1} of unit length. Draw a line segment P1P2P_{1}P_{2} perpendicular to OP1OP_{1} of unit length (see Fig. 11.99). Now draw a line segment P2P3P_{2}P_{3} perpendicular to OP2OP_{2}. Then draw a line segment P3P4P_{3}P_{4} perpendicular to OP3OP_{3}. Continuing in this manner, you can get the line segment Pn−1PnP_{n-1}P_{n} by drawing a line segment of unit length perpendicular to OPn−1OP_{n-1}. In this manner, you will have created the points OP1OP_{1}00, and joined them to create a beautiful spiral depicting OP1OP_{1}11
Get tutor helpright-arrow
Remaining Time: 1111 minutes, 1515 seconds.\newlineA Question Completion Status:\newline1 b 1 \mathrm{~b} \newline2 b 2 \mathrm{~b} \newline33\newline4 b 4 \mathrm{~b} \newline5 b 5 \mathrm{~b} \newline66\newline7 L 7 \mathrm{~L} \newline8181\newline9E 9 \mathrm{E} \newline100100\newline1111\newline1212\newline1313\newline1414\newline1515\newline160160\newline17c 17 \mathrm{c} \newline1818 L\newline1919\newline2020\newline218218\newline22x 22 x \newline23R 23 \mathrm{R} \newline24 b 24 \mathrm{~b} \newline22.\newlineMoving to another question will save this response.\newlineQuestion 1313\newlineUse an addition or subtraction formula to rewrite 2 b 2 \mathrm{~b} 00 and find its exact value. Your answer should include the rewritten answer and exact valu For the toolbar, press ALT+F1010 (PC) or ALT+FN+F1010 (Mac).\newline\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|}\newline\hline B & 2 b 2 \mathrm{~b} 11 & 2 b 2 \mathrm{~b} 22 & f & Par & graph & & 2 b 2 \mathrm{~b} 33 & Arial & & 2 b 2 \mathrm{~b} 44 & 2 b 2 \mathrm{~b} 55 & & & 2 b 2 \mathrm{~b} 44 & 2 b 2 \mathrm{~b} 77 & 2 b 2 \mathrm{~b} 88 & :Ev & & & 22 & 2 b 2 \mathrm{~b} 88 & 4 b 4 \mathrm{~b} 00 & & 厄市 & 俣 \\\newline\hline4 b 4 \mathrm{~b} 11 & 틈 & 三 & 4 b 4 \mathrm{~b} 11 & 㭅 & 巨 & 4 b 4 \mathrm{~b} 33 & 4 b 4 \mathrm{~b} 44 & 湒 & गा & 4 b 4 \mathrm{~b} 55 & - & 4 b 4 \mathrm{~b} 66 & 4 b 4 \mathrm{~b} 77 & 2 b 2 \mathrm{~b} 44 & 2 b 2 \mathrm{~b} 88 & 99 & 9797 & 5 b 5 \mathrm{~b} 00 & 5 b 5 \mathrm{~b} 11 & & & 2 b 2 \mathrm{~b} 44 & 5 b 5 \mathrm{~b} 33 & 田 & 5 b 5 \mathrm{~b} 44 \\\newline\hline 尔 & 耻 & 자 & ர் & (b) & (C) & (22) & \begin{tabular}{l}\newline5 b 5 \mathrm{~b} 55 \\\newline5 b 5 \mathrm{~b} 66\newline\end{tabular} & & & & & & & & & & & & & & & & & & \\\newline\hline\newline\end{tabular}\newlineMoving to another question will save this response.
Get tutor helpright-arrow
Exam 33 on.com/Student/PlayerTest.aspx?testid=25917940382591794038centerwin=yes Finish update 2024−102024 - 10 Alanna Winder-Mosley 0404/0505/2424 1010:0505 AM Question 22 of 66 This test: 66 point(s) possible This question: 11 point(s) possible Submit test A company claims that the mean monthly residential electricity consumption in a certain region is more than 660 kWh660 \, \text{kWh}. You want to test this claim. You find that a random sample of 6565 residential customers has a mean monthly consumption of 890 kWh890\,\text{kWh}. Assume the population standard deviation is 128 kWh128\,\text{kWh}. At α=0.01\alpha=0.01, can you support the claim? Complete parts (a) through (c). (a) Identify H0H_{0} and HaH_{a}. Choose the correct answer below
Get tutor helpright-arrow
Khan Academy\newlineGet Al Tutoring\newlineNEW\newline[a.\newlineDonate λ { }^{\lambda} \newlineYou might need: Calculator\newlineThe price of a train ticket consists of an initial fee of $5 \$ 5 plus a fee of $2.75 \$ 2.75 per stop. Julia has $21 \$ 21 and would like to travel 5050 kilometers. She wants to know the largest number of stops she can afford to buy on a ticket.\newlineLet S S represent the number of stops that Julia buys.\newline11) Which inequality describes this scenario?\newlineChoose 11 answer:\newline(A) 5+2.75⋅S≤21 5+2.75 \cdot S \leq 21 \newline(B) 5+2.75⋅S≥21 5+2.75 \cdot S \geq 21 \newline(C) 5+2.75⋅S≤50 5+2.75 \cdot S \leq 50 \newline(D) 5+2.75⋅S≥50 5+2.75 \cdot S \geq 50 \newline22) What is the largest number of stops that Julia can afford?
Get tutor helpright-arrow
−2 -2 .\newlineSBA Task: Assignment November 20242024\newlineIVITY 11: ASSIGNIMENT\newlineTRUCTIONS AND INFORMATION\newlineAnswer ALL the questions.\newlineCalculators may be used and ALI calculations must be shown.\newlineAll answers must be rounded off to TWO decimal places, unless otherwise stated.\newlineIVITY 11: ASSIGNMENT\newlinePatel and Karen started a business and contributed money in the ratio 5:4 5: 4 . The business was started with a capital of R44 500500.\newline11.11.11 Calculate how much money did Patel contribute to start the business.\newline11.11.22 Hence, find how mueh did Karen contribute.\newlineThe business made a profit. Patel and Karen decided to share the profit in the ratio 5:4 5: 4 .\newline11.22.11 Determine Patel's share of the profit if Karen received R11 600600.\newline11.22.22 How much profit did the business make altogether?\newline11.22.33 How much more profit does Patel receive than Karen?\newlineKaren says they are planning to inerease their business capital of R 45004500 by 45% 45 \% .\newlineCalculate the new business capital.\newlinePatel says it is too risky for them to put a lot of money into the business. So they got other people to contribute equal amounts of money as capital for the business and they will share profits equally.\newline\begin{tabular}{|c|c|c|c|c|c|c|}\newline\hline \begin{tabular}{c} \newlineNumber \\\newlineof People\newline\end{tabular} & 11 & 22 & 33 & 44 & B & 1818 \\\newline\hline \begin{tabular}{c} \newlineAmount \\\newlineof money\newline\end{tabular} & R6525 \mathrm{R} 6525 & R3262,50 \mathrm{R} 3262,50 &  A \mathrm{~A} & R1631,25 \mathrm{R} 1631,25 & 725725 & R362,50 \mathrm{R} 362,50 \\\newline\hline\newline\end{tabular}\newline11.44.11 Complete the table above.\newline11.44.22 Does the relationship represent direct or inverse proportion? Give a reason for your answer.\newlineTOTAL ACTIVITY
Get tutor helpright-arrow
Write zero, 11 , or more than 11 .\newline11.\newline11\newline22.\newlinemore thanl\newline33.\newline77.\newlineno\newline44.\newline88.\newlineDraw a shape for the statement. Draw the line or lines of symmetry.\newline99. zero lines of symmetry\newline1010. 11 line of symmetry\newline1111. 22 lines of symmetry\newlineDoes the design have line symmetry? Write yes or no.\newlineIf your answer is yes, draw all lines of symmetry.\newline55.\newline66.\newline44.\newline88.\newlineProblem Solving (Real)\newlineUse the chart for 1212.\newline(44) 22\newline3434\newline88\newline1212. Which number or numbers appear to have lines of symmetry?\newline1313. WRITE Math Draw a picture of a figure that has more than 33 lines of symmetry. Drawthe lines of symmetry.\newlineChapter 1010
Get tutor helpright-arrow
The function f(x,y)=3xy f(x, y)=3 x y has an absolute maximum value and absolute minimum value subject to the constraint 2x2+2y2−3xy=49 2 x^{2}+2 y^{2}-3 x y=49 . Use Lagrange multipliers to find these values.\newlinerina the gradient or g(x,y)=∠x+2y−3xy−4y g(x, y)=\angle x+2 y-3 x y-4 y .\newlineablag(x,y)=⟨4x−3y,4y−3x⟩ abla g(x, y)=\langle 4 x-3 y, 4 y-3 x\rangle \newlineWrite the Lagrange multiplier conditions. Choose the correct answer below.\newlineA. 3x=λ(4x−3y),3y=λ(4y−3x),3xy=0 3 x=\lambda(4 x-3 y), 3 y=\lambda(4 y-3 x), 3 x y=0 \newlineB. 3xy=λ(4x−3y),3xy=λ(4y−3x),2x2+2y2−3xy−49=0 3 x y=\lambda(4 x-3 y), 3 x y=\lambda(4 y-3 x), 2 x^{2}+2 y^{2}-3 x y-49=0 \newlineC. 3x=λ(4x−3y),3y=λ(4y−3x),2x2+2y2−3xy−49=0 3 x=\lambda(4 x-3 y), 3 y=\lambda(4 y-3 x), 2 x^{2}+2 y^{2}-3 x y-49=0 \newlineD. 3y=λ(4x−3y),3x=λ(4y−3x),2x2+2y2−3xy−49=0 3 y=\lambda(4 x-3 y), 3 x=\lambda(4 y-3 x), 2 x^{2}+2 y^{2}-3 x y-49=0 \newlineThe absolute maximum value is 55 .
Get tutor helpright-arrow
QuIz 11\newlineGoogle Classroom\newlineLet h(x)=x5−2x4+10x2−10x h(x)=x^{5}-2 x^{4}+10 x^{2}-10 x .\newlineBelow is Omar's attempt to write a formal justification for the fact that there exists a value c c where −2<c<2 -2<c<2 such that h′(c)=6 h^{\prime}(c)=6 .\newlineIs Omar's justification complete? If not, why?\newlineOmar's justification:\newlineh(−2)=−4 and h(2)=20, so h(2)−h(−2)2−(−2)=6. h(-2)=-4 \text { and } h(2)=20 \text {, so } \frac{h(2)-h(-2)}{2-(-2)}=6 . \newlineSo, according to the mean value theorem, there exists a value c c somewhere in the interval −2<c<2 -2<c<2 such that h′(c)=6 h^{\prime}(c)=6 .\newlineChoose 11 answer:\newline33 of 55
Get tutor helpright-arrow
22 The table shows Ricky's monthly budget. Ricky earns $1,200 \$ 1,200 each month.\newlineMonthly Budget\newline\begin{tabular}{|l|c|}\newline\hline \multicolumn{11}{|c|}{ Expense } & \begin{tabular}{c} \newlineAmount of \\\newlineMoney\newline\end{tabular} \\\newline\hline Clothes & $175 \$ 175 \\\newline\hline Food & $425 \$ 425 \\\newline\hline Cell phone & $80 \$ 80 \\\newline\hline College savings & $120 \$ 120 \\\newline\hline Car payment & $300 \$ 300 \\\newline\hline Other & $100 \$ 100 \\\newline\hline\newline\end{tabular}\newlineWhich statement is NOT supported by the information in the table?\newlineA Ricky spends 25% 25 \% of his monthly budget on his car payment.\newline(B) Ricky spends 10% 10 \% of his monthly budget on college savings.\newline(C) Ricky spends 50% 50 \% of his monthly budget on clothes and food.\newlineD Ricky spends $175 \$ 175 00 of his monthly budget on his cell phone and college savings.
Get tutor helpright-arrow
Question 33. Points possible: 33 Unlimited attempts. Score on last attempt: 00 . Score in gradebook: 00 Message instructor about this question For triangle ABCABC, we are given that m∠C=93.7∘m\angle C=93.7^\circ, AC=12.5 ftAC=12.5\,\text{ft}, and BC=22.6 ftBC=22.6\,\text{ft}. We can use the Law of Cosines, Law of Sines, and other properties of triangles to determine all of the missing information. Note that the diagram may not be drawn to scale. Determine all of the missing information about this triangle. a. AB=AB= ** feet Preview b. Draw the triangle and add the length of AB‾\overline{AB} to your diagram. c. m∠A=m\angle A= * degrees Preview d. m∠B=m\angle B= degrees Preview Note that this question allows you to use trig functions that evaluate for angle measures in degrees. To remind yourself how to evaluate trig functions for angle measures in degrees in this program, click here. Submit Question 44. Points possible: 33 Unlimited attempts. Score on last attempt: 00 . Score in gradebook: 00 Message instructor about this question Triangle ABCABC is shown below with all three side lengths known.
Get tutor helpright-arrow
www-awu.aleks.com\newlineVitalSource Bookshelf: Print Reading for Cónstruction\newlineA ALEKS - Zachary Zawacki - Learn\newlinePolynomial and Rational Functions\newlineWord problem involving optimizing area by using a quadratic function\newlineZachary\newlineReuben has 360360 meters of fencing. He will use it to form three sides of a rectangular garden. The fourth side will be along a house and will not need fencing.\newlineEspañol\newlineAs shown below, one of the sides has length x x (in meters).\newline(a) Find a function that gives the area A(x) A(x) of the garden (in square meters) in terms of x x .\newlineA(x)= A(x)= \newline(b) What side length x x gives the maximum area that the garden can have?\newlineSide length x:□ x: \square meters\newline(c) What is the maximum area that the garden can have?\newlineMaximum area: □ \square square meters\newlineExplanation\newlineCheck\newline(33) 20242024 McGraw HIII LLC. All Righits Reserved. Terms of Use\newlinePrivacy Center\newlineAccessibility
Get tutor helpright-arrow
Previous
1

...

234

...

5
Next