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Algebra 2
Transformations of functions
∠
1
\angle 1
∠1
and
∠
2
\angle 2
∠2
are complementary angles. If
m
∠
1
=
(
x
+
18
)
∘
\mathrm{m} \angle 1=(x+18)^{\circ}
m
∠1
=
(
x
+
18
)
∘
and
m
∠
2
=
(
3
x
+
12
)
∘
\mathrm{m} \angle 2=(3 x+12)^{\circ}
m
∠2
=
(
3
x
+
12
)
∘
, then find the measure of
∠
1
\angle 1
∠1
.
\newline
Answer:
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∠
1
\angle 1
∠1
and
∠
2
\angle 2
∠2
are supplementary angles. If
m
∠
1
=
(
2
x
−
26
)
∘
\mathrm{m} \angle 1=(2 x-26)^{\circ}
m
∠1
=
(
2
x
−
26
)
∘
and
m
∠
2
=
(
5
x
−
11
)
∘
\mathrm{m} \angle 2=(5 x-11)^{\circ}
m
∠2
=
(
5
x
−
11
)
∘
, then find the measure of
∠
2
\angle 2
∠2
.
\newline
Answer:
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∠
1
\angle 1
∠1
and
∠
2
\angle 2
∠2
are complementary angles. If
m
∠
1
=
(
2
x
+
1
)
∘
\mathrm{m} \angle 1=(2 x+1)^{\circ}
m
∠1
=
(
2
x
+
1
)
∘
and
m
∠
2
=
(
4
x
+
11
)
∘
\mathrm{m} \angle 2=(4 x+11)^{\circ}
m
∠2
=
(
4
x
+
11
)
∘
, then find the measure of
∠
2
\angle 2
∠2
.
\newline
Answer:
Get tutor help
∠
1
\angle 1
∠1
and
∠
2
\angle 2
∠2
are complementary angles. If
m
∠
1
=
(
x
−
26
)
∘
\mathrm{m} \angle 1=(x-26)^{\circ}
m
∠1
=
(
x
−
26
)
∘
and
m
∠
2
=
(
x
−
28
)
∘
\mathrm{m} \angle 2=(x-28)^{\circ}
m
∠2
=
(
x
−
28
)
∘
, then find the measure of
∠
2
\angle 2
∠2
.
\newline
Answer:
Get tutor help
∠
1
\angle 1
∠1
and
∠
2
\angle 2
∠2
are supplementary angles. If
m
∠
1
=
(
x
−
11
)
∘
\mathrm{m} \angle 1=(x-11)^{\circ}
m
∠1
=
(
x
−
11
)
∘
and
m
∠
2
=
(
3
x
+
7
)
∘
\mathrm{m} \angle 2=(3 x+7)^{\circ}
m
∠2
=
(
3
x
+
7
)
∘
, then find the measure of
∠
2
\angle 2
∠2
.
\newline
Answer:
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Which of the following is the correct form of
−
3
i
8
−
3
i
6
−
3
i
−
1
-3i^8 - 3i^6 - 3i^{-1}
−
3
i
8
−
3
i
6
−
3
i
−
1
, where the imaginary number
i
i
i
is such that
i
2
=
−
1
i^2 = -1
i
2
=
−
1
?
\newline
(A)
−
1
-1
−
1
\newline
(B)
−
1
−
3
i
-1 - 3i
−
1
−
3
i
\newline
(C)
−
7
−
3
i
-7 - 3i
−
7
−
3
i
\newline
(D)
−
1
−
3
i
-1 - 3i
−
1
−
3
i
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Find
g
(
x
)
g(x)
g
(
x
)
, where
g
(
x
)
g(x)
g
(
x
)
is the translation
9
9
9
units down of
f
(
x
)
=
10
x
+
8
f(x) = 10x + 8
f
(
x
)
=
10
x
+
8
.
\newline
Choices:
\newline
(A)
g
(
x
)
=
10
x
−
82
g(x) = 10x - 82
g
(
x
)
=
10
x
−
82
\newline
(B)
g
(
x
)
=
10
x
+
98
g(x) = 10x + 98
g
(
x
)
=
10
x
+
98
\newline
(C)
g
(
x
)
=
10
x
−
1
g(x) = 10x - 1
g
(
x
)
=
10
x
−
1
\newline
(D)
g
(
x
)
=
10
x
+
17
g(x) = 10x + 17
g
(
x
)
=
10
x
+
17
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