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Math Problems
Algebra 2
Sum of finite series starts from 1
Calculate in two ways:
(
34
560
+
14
210
)
:
10
=
(
34
560
+
14
210
)
:
10
=
(34\,560+ 14\,210): 10 = (34\,560+ 14\,210): 10 =
(
34
560
+
14
210
)
:
10
=
(
34
560
+
14
210
)
:
10
=
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Solve the given equation
tan
x
sec
x
−
1
+
sin
x
1
−
cos
x
=
2
cosec
x
\frac{\tan x}{\sec x-1}+\frac{\sin x}{1-\cos x}=2 \operatorname{cosec} x
s
e
c
x
−
1
t
a
n
x
+
1
−
c
o
s
x
s
i
n
x
=
2
cosec
x
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Evaluate
∑
n
=
1
∞
(
−
1
)
n
cos
(
1
n
2
)
\sum_{n=1}^{\infty}(-1)^{n} \cos \left(\frac{1}{n^{2}}\right)
∑
n
=
1
∞
(
−
1
)
n
cos
(
n
2
1
)
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3
a
b
−
1
=
2
a
b
−
3
3 a b-1=2 a b-3
3
ab
−
1
=
2
ab
−
3
\newline
Given the equation, what is the value of
a
b
a b
ab
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
4
-4
−
4
\newline
(B)
−
3
-3
−
3
\newline
(C)
−
2
-2
−
2
\newline
(D)
−
1
-1
−
1
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Solve the equation
log
2
(
4
x
−
3
)
+
log
2
(
3
x
+
5
)
=
3
\log_{2}(4x-3)+\log_{2}(3x+5)=3
lo
g
2
(
4
x
−
3
)
+
lo
g
2
(
3
x
+
5
)
=
3
Get tutor help
Evaluate
∑
n
=
1
∞
2
+
n
1
−
2
n
\sum_{n=1}^{\infty}\frac{2+n}{1-2n}
n
=
1
∑
∞
1
−
2
n
2
+
n
Get tutor help
Evaluate
∑
k
=
0
9
1000
x
k
=
5
×
60
×
1000
\sum_{k=0}^{9}1000x^{k}=5\times60\times1000
∑
k
=
0
9
1000
x
k
=
5
×
60
×
1000
Get tutor help
Evaluate
∑
m
≥
1
∞
(
2
−
1
m
)
m
2
\sum_{m \geq 1}^{\infty}\left(2-\frac{1}{m}\right)^{m^{2}}
∑
m
≥
1
∞
(
2
−
m
1
)
m
2
Get tutor help
Evaluate
∑
m
=
1
∞
(
1
−
1
m
)
m
2
\sum_{m=1}^{\infty}\left(1-\frac{1}{m}\right)^{m^{2}}
∑
m
=
1
∞
(
1
−
m
1
)
m
2
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Evaluate
∑
m
≥
1
∞
(
1
−
1
m
)
m
2
=
\sum_{m \geq 1}^{\infty}\left(1-\frac{1}{m}\right)^{m^{2}}=
m
≥
1
∑
∞
(
1
−
m
1
)
m
2
=
Get tutor help
Evaluate
−
∑
i
=
1
100
(
−
1
)
i
(
5
!
×
5
4
!
)
1
2
-\sum_{i=1}^{100}(-1)^{i}\left(\frac{5!\times5}{4!}\right)^{\frac{1}{2}}
−
i
=
1
∑
100
(
−
1
)
i
(
4
!
5
!
×
5
)
2
1
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What is the sum of the solutions to the equation
(
t
+
3
)
(
t
−
357
)
=
0
(t+3)(t-357)=0
(
t
+
3
)
(
t
−
357
)
=
0
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
360
-360
−
360
\newline
(B)
−
354
-354
−
354
\newline
(C)
354
354
354
\newline
(D)
360
360
360
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3
(
m
+
2
)
9
=
5
(
m
−
4
)
10
\frac{3(m+2)}{9}=\frac{5(m-4)}{10}
9
3
(
m
+
2
)
=
10
5
(
m
−
4
)
\newline
In the equation above, what is the value of
\newline
m
m
m
?
\newline
A.
6
6
6
\newline
B.
11
11
11
\newline
C.
16
16
16
\newline
D.
28
28
28
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Simplify the given expression
8
(
x
−
2
)
2
+
y
2
−
x
+
y
−
3
x
y
(
1
−
12
x
)
=
4
x
(
2
x
−
9
x
y
)
+
(
y
+
9
)
2
−
3
x
(
y
−
7
)
8(x-2)^{2}+y^{2}-x+y-3xy(1-12x)=4x(2x-9xy)+(y+9)^{2}-3x(y-7)
8
(
x
−
2
)
2
+
y
2
−
x
+
y
−
3
x
y
(
1
−
12
x
)
=
4
x
(
2
x
−
9
x
y
)
+
(
y
+
9
)
2
−
3
x
(
y
−
7
)
Get tutor help
Select the answer which is equivalent to the given expression using your calculator.
\newline
−
5
10
+
6
\frac{-5}{10+\sqrt{6}}
10
+
6
−
5
\newline
−
50
−
5
6
94
\frac{-50-5 \sqrt{6}}{94}
94
−
50
−
5
6
\newline
−
350
−
35
6
94
\frac{-350-35 \sqrt{6}}{94}
94
−
350
−
35
6
\newline
−
50
+
5
6
94
\frac{-50+5 \sqrt{6}}{94}
94
−
50
+
5
6
\newline
−
350
+
35
6
94
\frac{-350+35 \sqrt{6}}{94}
94
−
350
+
35
6
Get tutor help
Select the answer which is equivalent to the given expression using your calculator.
\newline
−
6
−
16
−
12
\frac{-6}{-16-\sqrt{12}}
−
16
−
12
−
6
\newline
48
+
3
12
122
\frac{48+3 \sqrt{12}}{122}
122
48
+
3
12
\newline
144
+
9
12
122
\frac{144+9 \sqrt{12}}{122}
122
144
+
9
12
\newline
144
−
9
12
122
\frac{144-9 \sqrt{12}}{122}
122
144
−
9
12
\newline
48
−
3
12
122
\frac{48-3 \sqrt{12}}{122}
122
48
−
3
12
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Select the answer which is equivalent to the given expression using your calculator.
\newline
−
6
17
+
15
\frac{-6}{17+\sqrt{15}}
17
+
15
−
6
\newline
−
51
−
3
15
137
\frac{-51-3 \sqrt{15}}{137}
137
−
51
−
3
15
\newline
−
102
+
6
15
137
\frac{-102+6 \sqrt{15}}{137}
137
−
102
+
6
15
\newline
−
102
−
6
15
137
\frac{-102-6 \sqrt{15}}{137}
137
−
102
−
6
15
\newline
−
51
+
3
15
137
\frac{-51+3 \sqrt{15}}{137}
137
−
51
+
3
15
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5
2
x
−
1
=
2
x
+
1
5^{2 x-1}=2^{x+1}
5
2
x
−
1
=
2
x
+
1
Get tutor help
Evaluate the summation below.
\newline
5
∑
p
=
1
7
(
2
p
−
7
)
5 \sum_{p=1}^{7}(2 p-7)
5
p
=
1
∑
7
(
2
p
−
7
)
\newline
Answer:
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Evaluate the summation below.
\newline
7
∑
k
=
0
4
(
4
k
−
2
k
2
)
7 \sum_{k=0}^{4}\left(4 k-2 k^{2}\right)
7
k
=
0
∑
4
(
4
k
−
2
k
2
)
\newline
Answer:
Get tutor help
Evaluate the summation below.
\newline
2
∑
k
=
4
9
(
6
−
2
k
)
2 \sum_{k=4}^{9}(6-2 k)
2
k
=
4
∑
9
(
6
−
2
k
)
\newline
Answer:
Get tutor help
Evaluate the summation below.
\newline
4
∑
p
=
0
3
(
9
p
−
2
p
2
)
4 \sum_{p=0}^{3}\left(9 p-2 p^{2}\right)
4
p
=
0
∑
3
(
9
p
−
2
p
2
)
\newline
Answer:
Get tutor help
Evaluate the summation below.
\newline
5
∑
k
=
0
3
(
1
−
3
k
2
)
5 \sum_{k=0}^{3}\left(1-3 k^{2}\right)
5
k
=
0
∑
3
(
1
−
3
k
2
)
\newline
Answer:
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Evaluate the summation below.
\newline
7
∑
k
=
3
6
(
6
k
−
k
2
)
7 \sum_{k=3}^{6}\left(6 k-k^{2}\right)
7
k
=
3
∑
6
(
6
k
−
k
2
)
\newline
Answer:
Get tutor help
Evaluate the summation below.
\newline
∑
t
=
0
4
(
−
t
2
+
4
t
)
\sum_{t=0}^{4}\left(-t^{2}+4 t\right)
t
=
0
∑
4
(
−
t
2
+
4
t
)
\newline
Answer:
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Find the value of the following expression and round to the nearest integer:
\newline
∑
n
=
2
50
50
(
1.12
)
n
−
2
\sum_{n=2}^{50} 50(1.12)^{n-2}
n
=
2
∑
50
50
(
1.12
)
n
−
2
\newline
Answer:
Get tutor help
Evaluate:
\newline
∑
n
=
2
5
(
−
5
x
+
2
n
)
\sum_{n=2}^{5}(-5 x+2 n)
n
=
2
∑
5
(
−
5
x
+
2
n
)
\newline
Answer:
Get tutor help
Evaluate:
\newline
∑
n
=
0
2
(
−
4
x
−
3
n
)
\sum_{n=0}^{2}(-4 x-3 n)
n
=
0
∑
2
(
−
4
x
−
3
n
)
\newline
Answer:
Get tutor help
Evaluate:
\newline
∑
n
=
0
2
(
−
4
x
−
3
n
)
\sum_{n=0}^{2}(-4 x-3 n)
n
=
0
∑
2
(
−
4
x
−
3
n
)
\newline
Answer:
\newline
Submit Answer
Get tutor help
Evaluate:
\newline
∑
n
=
0
3
(
n
x
−
1
)
\sum_{n=0}^{3}(n x-1)
n
=
0
∑
3
(
n
x
−
1
)
\newline
Answer:
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Evaluate the summation below.
\newline
∑
i
=
0
4
(
−
7
+
7
i
)
\sum_{i=0}^{4}(-7+7 i)
i
=
0
∑
4
(
−
7
+
7
i
)
\newline
Answer:
Get tutor help
Evaluate the summation below.
\newline
∑
n
=
0
4
(
6
n
2
−
8
n
)
\sum_{n=0}^{4}\left(6 n^{2}-8 n\right)
n
=
0
∑
4
(
6
n
2
−
8
n
)
\newline
Answer:
Get tutor help
Evaluate the summation below.
\newline
3
∑
n
=
0
3
(
−
4
n
2
+
3
)
3 \sum_{n=0}^{3}\left(-4 n^{2}+3\right)
3
n
=
0
∑
3
(
−
4
n
2
+
3
)
\newline
Answer:
Get tutor help
Evaluate the summation below.
\newline
2
∑
i
=
0
3
(
3
i
−
3
i
2
)
2 \sum_{i=0}^{3}\left(3 i-3 i^{2}\right)
2
i
=
0
∑
3
(
3
i
−
3
i
2
)
\newline
Answer:
Get tutor help
Evaluate the summation below.
\newline
6
∑
p
=
0
3
(
−
p
2
+
2
p
)
6 \sum_{p=0}^{3}\left(-p^{2}+2 p\right)
6
p
=
0
∑
3
(
−
p
2
+
2
p
)
\newline
Answer:
Get tutor help
Evaluate the summation below.
\newline
5
∑
t
=
2
5
(
7
−
3
t
)
5 \sum_{t=2}^{5}(7-3 t)
5
t
=
2
∑
5
(
7
−
3
t
)
\newline
Answer:
Get tutor help
Find the numerical answer to the summation given below.
\newline
∑
n
=
0
64
(
2
n
+
5
)
\sum_{n=0}^{64}(2 n+5)
n
=
0
∑
64
(
2
n
+
5
)
\newline
Answer:
Get tutor help
Find the numerical answer to the summation given below.
\newline
∑
n
=
2
66
(
7
n
+
6
)
\sum_{n=2}^{66}(7 n+6)
n
=
2
∑
66
(
7
n
+
6
)
\newline
Answer:
Get tutor help
Find the numerical answer to the summation given below.
\newline
∑
n
=
1
70
(
3
n
+
10
)
\sum_{n=1}^{70}(3 n+10)
n
=
1
∑
70
(
3
n
+
10
)
\newline
Answer:
Get tutor help
Find the numerical answer to the summation given below.
\newline
∑
n
=
2
65
(
6
n
+
1
)
\sum_{n=2}^{65}(6 n+1)
n
=
2
∑
65
(
6
n
+
1
)
\newline
Answer:
Get tutor help
Find the numerical answer to the summation given below.
\newline
∑
n
=
0
69
(
2
n
+
9
)
\sum_{n=0}^{69}(2 n+9)
n
=
0
∑
69
(
2
n
+
9
)
\newline
Answer:
Get tutor help
Find the numerical answer to the summation given below.
\newline
∑
n
=
0
60
(
4
n
+
7
)
\sum_{n=0}^{60}(4 n+7)
n
=
0
∑
60
(
4
n
+
7
)
\newline
Answer:
Get tutor help
Find the numerical answer to the summation given below.
\newline
∑
n
=
2
86
(
5
n
+
6
)
\sum_{n=2}^{86}(5 n+6)
n
=
2
∑
86
(
5
n
+
6
)
\newline
Answer:
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Find the numerical answer to the summation given below.
\newline
∑
n
=
0
72
(
6
n
+
3
)
\sum_{n=0}^{72}(6 n+3)
n
=
0
∑
72
(
6
n
+
3
)
\newline
Answer:
Get tutor help
Find the numerical answer to the summation given below.
\newline
∑
n
=
0
89
(
3
n
+
8
)
\sum_{n=0}^{89}(3 n+8)
n
=
0
∑
89
(
3
n
+
8
)
\newline
Answer:
Get tutor help
Find the numerical answer to the summation given below.
\newline
∑
n
=
0
98
(
7
n
+
6
)
\sum_{n=0}^{98}(7 n+6)
n
=
0
∑
98
(
7
n
+
6
)
\newline
Answer:
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Find the numerical answer to the summation given below.
\newline
∑
n
=
1
89
(
2
n
+
9
)
\sum_{n=1}^{89}(2 n+9)
n
=
1
∑
89
(
2
n
+
9
)
\newline
Answer:
Get tutor help
Find the numerical answer to the summation given below.
\newline
∑
n
=
3
79
(
6
n
+
4
)
\sum_{n=3}^{79}(6 n+4)
n
=
3
∑
79
(
6
n
+
4
)
\newline
Answer:
Get tutor help
Find the numerical answer to the summation given below.
\newline
∑
n
=
6
61
(
6
n
+
7
)
\sum_{n=6}^{61}(6 n+7)
n
=
6
∑
61
(
6
n
+
7
)
\newline
Answer:
Get tutor help
Find the numerical answer to the summation given below.
\newline
∑
n
=
1
78
(
7
n
+
6
)
\sum_{n=1}^{78}(7 n+6)
n
=
1
∑
78
(
7
n
+
6
)
\newline
Answer:
Get tutor help
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