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Math Problems
Algebra 1
Solve linear equations with variables on both sides
Math To Do, i-Ready
\newline
4
x
=
−
x
+
3
4 x=-x+3
4
x
=
−
x
+
3
what is
x
x
x
-Google Ser
\newline
ady.com/student/dashboard/home
\newline
th Student
\newline
i-Ready
\newline
Solve Systems of Linear Equatior
\newline
Solve the system of equations.
\newline
x
=
3
y
−
7
y
=
x
+
1
⟶
y
=
3
y
−
7
+
1
\begin{array}{l} x=3 y-7 \\ y=x+1 \end{array} \longrightarrow y=3 y-7+1
x
=
3
y
−
7
y
=
x
+
1
⟶
y
=
3
y
−
7
+
1
\newline
What is one way you can use substitution to sol
\newline
Substitute
\newline
3
y
−
7
3 y-7
3
y
−
7
\newline
for
\newline
x
x
x
\newline
Now, find the solution to the system of equation
\newline
□
\square
□
\newline
□
\square
□
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Henry places a bottle of water inside a cooler. As the water cools, its temperature
C
(
t
)
C(t)
C
(
t
)
in degrees Celsius is given by the following function, where
t
t
t
is the number of minutes since the bottle was placed in the cooler.
\newline
C
(
t
)
=
3
+
19
e
−
0.045
t
C(t)=3+19e^{-0.045 t}
C
(
t
)
=
3
+
19
e
−
0.045
t
\newline
Henry wants to drink the water when it reaches a temperature of
16
16
16
degrees Celsius. How many minutes should he leave it in the cooler?
\newline
Round your answer to the nearest tenth, and do not round any intermediate computations.
\newline
□
\square
□
minutes
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bigideasmath com
\newline
(ty IS MATH
\newline
\#
2
2
2
i
\newline
Listen
\newline
Solve the system by graphing.
\newline
3
x
−
y
=
−
1
y
=
−
x
+
5
\begin{array}{l} 3 x-y=-1 \\ y=-x+5 \end{array}
3
x
−
y
=
−
1
y
=
−
x
+
5
\newline
The solution is
□
\square
□
,
□
\square
□
\newline
Previous
\newline
1
1
1
\newline
2
2
2
\newline
3
3
3
\newline
4
4
4
\newline
5
5
5
Get tutor help
2
y
−
8
=
x
+
3
2y-8=x+3
2
y
−
8
=
x
+
3
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y
=
6
x
+
8
y=6x+8
y
=
6
x
+
8
y
=
−
4
x
+
8
y=-4x+8
y
=
−
4
x
+
8
Get tutor help
Elimination (Level
1
1
1
)
\newline
Score:
0
0
0
/
1
1
1
\newline
Penalty:
1
1
1
off
\newline
stem
\newline
mplete:
29
%
29 \%
29%
\newline
Question
\newline
Watch
\newline
Find the solution of the system of equations.
\newline
Iy (Lev.
1
1
1
)
\newline
−
8
x
+
9
y
=
−
21
−
3
x
+
9
y
=
−
36
\begin{array}{l} -8 x+9 y=-21 \\ -3 x+9 y=-36 \end{array}
−
8
x
+
9
y
=
−
21
−
3
x
+
9
y
=
−
36
\newline
Answer Attempt
1
1
1
out of
2
2
2
\newline
tions in System
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−
5
=
6
d
−
7
d
+
4
-5=6 d-7 d+4
−
5
=
6
d
−
7
d
+
4
Get tutor help
5
x
−
5
=
9
x
+
3
5x-5=9x+3
5
x
−
5
=
9
x
+
3
Get tutor help
Wed Apr
17
17
17
\newline
AA
\newline
zearn.org
\newline
C
\newline
Log in to
\newline
SSO Launch...
\newline
Math | Top-r...
\newline
Math | Top-r... Z Zearn
\newline
Zearn
\newline
Log in to i-R...
\newline
M
4
4
4
|L
11
11
11
\newline
On Both of the Lines
\newline
Sign
\newline
Erica and Jared are tracking the number of kilometers they bike. Erica had already biked
8
k
m
8 \mathrm{~km}
8
km
, anc continued biking
4
k
m
4 \mathrm{~km}
4
km
per day. Jared had already biked
2
k
m
2 \mathrm{~km}
2
km
, and continued biking
6
k
m
6 \mathrm{~km}
6
km
per day. (
4
4
4
)
\newline
Write an equation that represents
y
y
y
, the total number of kilometers Erica has biked after
x
x
x
days.
\newline
1
1
1
\newline
2
2
2
\newline
3
3
3
Get tutor help
Exponents
X
L
L
\mathrm{XLL}
XLL
\newline
Wy Ápps
\newline
ixl.com/math/grade
−
8
-8
−
8
/which-x-satisfies-an-equation
\newline
greenvilleschools.us bookmarks
\newline
My Apps
\newline
Home
\newline
50
,
000
+
50,000+
50
,
000
+
Chess Pro...
\newline
(GCS) GTT
8
8
8
Autom...
\newline
My IXL
\newline
Learning
\newline
| Wanna |
\newline
a ru
\newline
24
24
24
\newline
Eighth grade
\newline
M.
1
1
1
Which
x
x
x
satisfies an equation?
\newline
Bvo
\newline
What value of
z
z
z
is a solution to this equation?
\newline
7
z
=
63
z
=
7
z
=
9
\begin{array}{l} 7 z=63 \\ z=7 \quad z=9 \end{array}
7
z
=
63
z
=
7
z
=
9
\newline
Submit
\newline
Work it out
\newline
Not feeling ready yet? These
\newline
Evaluate linear expressions
\newline
Does
\newline
math
Get tutor help
Two cars are driving towards an intersection from perpendicular directions.
\newline
The first car's velocity is
2
2
2
meters per second and the second car's velocity is
9
9
9
meters per second.
\newline
At a certain instant, the first car is
8
8
8
meters from the intersection and the second car is
6
6
6
meters from the intersection.
\newline
What is the rate of change of the distance between the cars at that instant (in meters per second)?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
85
-\sqrt{85}
−
85
\newline
(B)
−
7
-7
−
7
\newline
(C)
−
8
-8
−
8
.
4
4
4
\newline
(D)
−
10
-10
−
10
Get tutor help
Rashida was asked to determine whether
f
(
x
)
=
x
2
−
∣
x
∣
f(x)=x^{2}-|x|
f
(
x
)
=
x
2
−
∣
x
∣
is even, odd, or neither. Here is her work:
\newline
Step
1
1
1
: Find expression for
f
(
−
x
)
f(-x)
f
(
−
x
)
\newline
f
(
−
x
)
=
(
−
x
)
2
−
∣
(
−
x
)
∣
=
x
2
+
∣
x
∣
\begin{aligned} f(-x) & =(-x)^{2}-|(-x)| \\ & =x^{2}+|x| \end{aligned}
f
(
−
x
)
=
(
−
x
)
2
−
∣
(
−
x
)
∣
=
x
2
+
∣
x
∣
\newline
Step
2
2
2
: Check if
f
(
−
x
)
f(-x)
f
(
−
x
)
is equal to
f
(
x
)
f(x)
f
(
x
)
or
−
f
(
x
)
-f(x)
−
f
(
x
)
\newline
x
2
+
∣
x
∣
x^{2}+|x|
x
2
+
∣
x
∣
isn't the same as
f
(
x
)
=
x
2
−
∣
x
∣
f(x)=x^{2}-|x|
f
(
x
)
=
x
2
−
∣
x
∣
or
−
f
(
x
)
=
−
x
2
+
∣
x
∣
-f(x)=-x^{2}+|x|
−
f
(
x
)
=
−
x
2
+
∣
x
∣
.
\newline
Step
3
3
3
: Conclusion
\newline
f
(
−
x
)
f(-x)
f
(
−
x
)
isn't equivalent to either
f
(
x
)
f(x)
f
(
x
)
or
−
f
(
x
)
-f(x)
−
f
(
x
)
, so
f
f
f
is neither even nor odd.
\newline
Is Rashida's work correct? If not, what is the first step where Rashida made a mistake?
\newline
Choose
1
1
1
answer:
\newline
(A) Rashida's work is correct.
\newline
(B) Rashida's work is incorrect. She first made a mistake in Step
1
1
1
.
\newline
(C) Rashida's work is incorrect. She first made a mistake in Step
2
2
2
.
\newline
(D) Rashida's work is incorrect. She first made a mistake in Step
3
3
3
.
Get tutor help
Felix was asked whether the following equation is an identity:
\newline
(
x
2
+
1
)
2
=
(
x
2
−
1
)
2
+
(
2
x
)
2
\left(x^{2}+1\right)^{2}=\left(x^{2}-1\right)^{2}+(2 x)^{2}
(
x
2
+
1
)
2
=
(
x
2
−
1
)
2
+
(
2
x
)
2
\newline
He performed the following steps:
\newline
(
x
2
+
1
)
2
\left(x^{2}+1\right)^{2}
(
x
2
+
1
)
2
\newline
↪
Step
1
=
x
4
+
x
2
+
x
2
+
1
\stackrel{\text { Step } 1}{\hookrightarrow}=x^{4}+x^{2}+x^{2}+1
↪
Step
1
=
x
4
+
x
2
+
x
2
+
1
\newline
↪
Step
2
=
x
4
+
2
x
2
+
1
\stackrel{\text { Step } 2}{\hookrightarrow}=x^{4}+2 x^{2}+1
↪
Step
2
=
x
4
+
2
x
2
+
1
\newline
↪
Step
3
=
x
4
+
2
x
2
+
1
−
2
x
2
+
2
x
2
\stackrel{\text { Step } 3}{\hookrightarrow}=x^{4}+2 x^{2}+1-2 x^{2}+2 x^{2}
↪
Step
3
=
x
4
+
2
x
2
+
1
−
2
x
2
+
2
x
2
\newline
↪
Step
4
=
(
x
4
−
2
x
2
+
1
)
+
4
x
2
\stackrel{\text { Step } 4}{\hookrightarrow}=\left(x^{4}-2 x^{2}+1\right)+4 x^{2}
↪
Step
4
=
(
x
4
−
2
x
2
+
1
)
+
4
x
2
\newline
↪
Step
5
=
(
x
2
−
1
)
2
+
(
2
x
)
2
\stackrel{\text { Step } 5}{\hookrightarrow}=\left(x^{2}-1\right)^{2}+(2 x)^{2}
↪
Step
5
=
(
x
2
−
1
)
2
+
(
2
x
)
2
\newline
For this reason, Felix stated that the equation is a true identity.
\newline
Is Felix correct? If not, in which step did he make a mistake?
\newline
Choose
1
1
1
answer:
\newline
(A) Felix is correct.
\newline
(B) Felix is incorrect. He made a mistake in step
1
1
1
.
\newline
(C) Felix is incorrect. He made a mistake in step
3
3
3
.
\newline
(D) Felix is incorrect. He made a mistake in step
5
5
5
.
Get tutor help
Ethan sells
e
e
e
candy bars for
$
2.50
\$ 2.50
$2.50
apiece and Chloe sells
c
c
c
candy bars for
$
2.00
\$ 2.00
$2.00
apiece to raise money for a school trip. Ethan sold
15
15
15
fewer candy bars than Chloe, but he also got a
$
6.00
\$ 6.00
$6.00
donation. If Chloe and Ethan raised the same amount of money, which of the following systems could be used to find how many candy bars each sold?
\newline
Choose
1
1
1
answer:
\newline
(A)
2
c
=
2.5
e
+
6
2 c=2.5 e+6
2
c
=
2.5
e
+
6
\newline
c
=
e
−
15
c=e-15
c
=
e
−
15
\newline
(B)
2
c
=
2.5
e
+
6
2 c=2.5 e+6
2
c
=
2.5
e
+
6
\newline
e
=
c
−
15
e=c-15
e
=
c
−
15
\newline
(C)
2
c
+
6
=
2.5
e
2 c+6=2.5 e
2
c
+
6
=
2.5
e
\newline
c
=
e
−
15
c=e-15
c
=
e
−
15
\newline
(D)
2
c
+
6
=
2.5
e
2 c+6=2.5 e
2
c
+
6
=
2.5
e
\newline
e
=
c
−
15
e=c-15
e
=
c
−
15
Get tutor help
Jasina has a total of
$
0.80
\$ 0.80
$0.80
in nickels and dimes, and she has
4
4
4
more nickels than dimes. Which of the following systems of equations can be used to find out how many
n
n
n
nickels and
d
d
d
dimes she has?
\newline
Choose
1
1
1
answer:
\newline
(A)
d
+
n
=
4
d+n=4
d
+
n
=
4
\newline
0.1
d
+
0.05
n
=
0.8
0.1 d+0.05 n=0.8
0.1
d
+
0.05
n
=
0.8
\newline
(B)
d
+
4
=
n
d+4=n
d
+
4
=
n
\newline
0.1
d
+
0.05
n
=
0.8
0.1 d+0.05 n=0.8
0.1
d
+
0.05
n
=
0.8
\newline
(c)
d
−
n
=
4
d-n=4
d
−
n
=
4
\newline
0.1
d
+
0.05
n
=
0.8
0.1 d+0.05 n=0.8
0.1
d
+
0.05
n
=
0.8
\newline
(D)
n
−
d
=
−
4
n-d=-4
n
−
d
=
−
4
\newline
0.1
d
+
0.05
n
=
0.8
0.1 d+0.05 n=0.8
0.1
d
+
0.05
n
=
0.8
Get tutor help
Philip is downloading applications (apps) and songs to his tablet. He downloads
7
7
7
apps and
6
6
6
songs. Each song takes an average of
0
0
0
.
8
8
8
minutes longer to download than each app. If it takes
21
21
21
.
7
7
7
minutes for his downloads to finish, which of the following systems could be used to approximate
a
a
a
, the average number of minutes it takes to download one app, and
s
s
s
, the average number of minutes it takes to download one song?
\newline
Choose
1
1
1
answer:
\newline
(A)
a
+
s
=
21.7
a+s=21.7
a
+
s
=
21.7
\newline
6
s
=
7
a
−
0.8
6 s=7 a-0.8
6
s
=
7
a
−
0.8
\newline
(B)
a
+
s
=
21.7
a+s=21.7
a
+
s
=
21.7
\newline
7
a
=
6
s
−
0.8
7 a=6 s-0.8
7
a
=
6
s
−
0.8
\newline
(C)
7
a
+
6
s
=
21.7
7 a+6 s=21.7
7
a
+
6
s
=
21.7
\newline
s
=
a
−
0.8
s=a-0.8
s
=
a
−
0.8
\newline
(D)
7
a
+
6
s
=
21.7
7 a+6 s=21.7
7
a
+
6
s
=
21.7
\newline
a
=
s
−
0.8
a=s-0.8
a
=
s
−
0.8
Get tutor help
A vegetable stand sells
p
p
p
pumpkins for
$
5.00
\$ 5.00
$5.00
each and
s
s
s
squashes for
$
3.00
\$ 3.00
$3.00
each. On Monday, the stand sold
6
6
6
more squashes than pumpkins and made a total of
$
98.00
\$ 98.00
$98.00
. Which system of equations can be used to determine the number of pumpkins and squashes sold?
\newline
Choose
1
1
1
answer:
\newline
(A)
3
p
+
5
s
=
98
3 p+5 s=98
3
p
+
5
s
=
98
\newline
s
=
p
+
6
s=p+6
s
=
p
+
6
\newline
(B)
3
p
+
5
s
=
98
3 p+5 s=98
3
p
+
5
s
=
98
\newline
p
=
s
+
6
p=s+6
p
=
s
+
6
\newline
(C)
5
p
+
3
s
=
98
5 p+3 s=98
5
p
+
3
s
=
98
\newline
s
=
p
+
6
s=p+6
s
=
p
+
6
\newline
(D)
5
p
+
3
s
=
98
5 p+3 s=98
5
p
+
3
s
=
98
\newline
p
=
s
+
6
p=s+6
p
=
s
+
6
Get tutor help
Ricardo has two types of assignments for his class. The number of mini assignments,
m
m
m
, he has is
1
1
1
fewer than twice the number of long assignments,
l
l
l
, he has. If he has
46
46
46
assignments in total, which of the following systems of equations can be used to correctly solve for
m
m
m
and
l
l
l
?
\newline
Choose
1
1
1
answer:
\newline
(A)
m
=
2
l
−
1
m=2 l-1
m
=
2
l
−
1
\newline
m
+
l
=
46
m+l=46
m
+
l
=
46
\newline
(B)
m
=
2
l
−
1
m=2 l-1
m
=
2
l
−
1
\newline
m
=
l
+
46
m=l+46
m
=
l
+
46
\newline
(C)
l
=
2
m
−
1
l=2 m-1
l
=
2
m
−
1
\newline
m
+
l
=
46
m+l=46
m
+
l
=
46
\newline
(D)
l
=
2
m
−
1
l=2 m-1
l
=
2
m
−
1
\newline
m
=
l
+
46
m=l+46
m
=
l
+
46
Get tutor help
Liam deposits
l
l
l
dollars into an account that earns
0.9
%
0.9 \%
0.9%
in simple interest each year. Grace deposits
g
g
g
dollars into an account that earns
1.1
%
1.1 \%
1.1%
in simple interest each year. Both Liam and Grace let their money earn interest for one year and make no further deposits. If Liam's initial deposit was
$
800
\$ 800
$800
more than Grace's, and if both Liam and Grace earn the same amount of interest after one year, which of the following systems of equations could be used to find their initial deposits?
\newline
Choose
1
1
1
answer:
\newline
(A)
0.009
l
+
800
=
0.011
g
0.009 l+800=0.011 g
0.009
l
+
800
=
0.011
g
\newline
l
=
g
l=g
l
=
g
\newline
(B)
0.009
l
=
0.011
g
+
800
0.009 l=0.011 g+800
0.009
l
=
0.011
g
+
800
\newline
l
=
g
l=g
l
=
g
\newline
(c)
0.009
l
=
0.011
g
0.009 l=0.011 g
0.009
l
=
0.011
g
\newline
l
+
800
=
g
l+800=g
l
+
800
=
g
\newline
(D)
0.009
l
=
0.011
g
0.009 l=0.011 g
0.009
l
=
0.011
g
\newline
l
=
g
+
800
l=g+800
l
=
g
+
800
Get tutor help
A piece of paper is to display
150
150
150
square inches of text. If there are to be one-inch margins on the sides and the top and a two-inch margin at the bottom, what are the dimensions of the smallest piece of paper that can be used?
\newline
Choose
1
1
1
answer:
\newline
(A)
6
′
′
×
25
′
′
6 \prime \prime \times 25 \prime \prime
6′′
×
25′′
\newline
(B)
10
′
′
×
15
′
′
10 \prime \prime \times 15 \prime \prime
10′′
×
15′′
\newline
(C)
12
′
′
×
18
′
′
12 \prime \prime \times 18 \prime \prime
12′′
×
18′′
\newline
(D)
15
′
′
×
18
′
′
15 \prime \prime \times 18 \prime \prime
15′′
×
18′′
\newline
(E) None of these
Get tutor help
y
y
y
is between
x
x
x
and
z
z
z
.
x
y
=
4
x
+
3
xy=4x+3
x
y
=
4
x
+
3
,
X
=
90
X=90
X
=
90
,
y
z
=
8
x
−
9
yz =8x-9
yz
=
8
x
−
9
solve for
x
x
x
.
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10
x
=
63
+
x
10x = 63 + x
10
x
=
63
+
x
Get tutor help
What is
4
a
−
13
=
8
+
2
a
4a - 13 = 8 + 2a
4
a
−
13
=
8
+
2
a
Get tutor help
Question
a
b
c
=
b
a
i
a
=
i
c
+
5
abc=baia=ic+5
ab
c
=
baia
=
i
c
+
5
\newline
A
=
b
−
c
A=b-c
A
=
b
−
c
\newline
B
=
14
B=14
B
=
14
\newline
C
=
b
+
a
C=b+a
C
=
b
+
a
\newline
Solve for
i
i
i
Get tutor help
15
15
15
-го января Сергей планирует взять кредит в банке
50
50
50
тыс. рублей на
5
5
5
месяцев. Условия его возврата таковы: -
1
1
1
-го числа каждого месяца долг возрастает на
2
2
2
\% по сравнению с концом предыдущего месяца; - со
2
2
2
-го по
14
14
14
-е число каждого месяца необходимо выплатить часть долга; -
15
15
15
-го числа каждого месяца долг должен быть на одну и ту же сумму меньше долга на
15
15
15
-ое число предыдущего месяца. Какую сумму (в рублях) вернет Сергей в банк за весь срок кредитования?
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x
2
−
10
x
=
4
y
2
−
25
x^2-10x=4y^2-25
x
2
−
10
x
=
4
y
2
−
25
Get tutor help
3
x
+
4
=
x
+
10
3x+4=x+10
3
x
+
4
=
x
+
10
Get tutor help
Question
\newline
Show Examples
\newline
After sitting out of a refrigerator for a while, a turkey at room temperature
(
7
0
∘
F
)
\left(70^{\circ} \mathrm{F}\right)
(
7
0
∘
F
)
is placed into an oven. The oven temperature is
32
5
∘
325^{\circ}
32
5
∘
F. Newton's Law of Heating explains that the temperature of the turkey will increase proportionally to the difference between the temperature of the turkey and the temperature of the oven, as given by the formula below:
\newline
T
=
T
a
+
(
T
0
−
T
a
)
e
−
k
t
T
a
=
the temperature surrounding the object
T
0
=
the initial temperature of the object
t
=
the time in hours
T
=
the temperature of the object after
t
hours
k
=
decay constant
\begin{array}{l} \qquad T=T_{a}+\left(T_{0}-T_{a}\right) e^{-k t} \\ T_{a}=\text { the temperature surrounding the object } \\ T_{0}=\text { the initial temperature of the object } \\ t=\text { the time in hours } \\ T=\text { the temperature of the object after } t \text { hours } \\ k=\text { decay constant } \end{array}
T
=
T
a
+
(
T
0
−
T
a
)
e
−
k
t
T
a
=
the temperature surrounding the object
T
0
=
the initial temperature of the object
t
=
the time in hours
T
=
the temperature of the object after
t
hours
k
=
decay constant
\newline
The turkey reaches the temperature of
11
6
∘
F
116^{\circ} \mathrm{F}
11
6
∘
F
after
2
−
5
2-5
2
−
5
hours. Using this information, find the value of
k
k
k
, to the nearest thousandth. Use the resulting equation to determine the Fahrenheit temperature of the turkey, to the nearest degree, after
5
5
5
.
5
5
5
hours.
\newline
Enter only the final temperature into the input box.
\newline
Answer Attemps z out of
2
2
2
\newline
T
=
57
T=57
T
=
57
\newline
Submit Answert
Get tutor help
1
1
1
.
4
4
4
Pre cal-Quadratic formula
\newline
7
7
7
. The profits of Mr. Unlucky's company can be represented by the equation
p
=
−
3
t
2
+
18
t
−
4
p=-3 t^{2}+18 t-4
p
=
−
3
t
2
+
18
t
−
4
, where
p
p
p
is the amount of profit in hundreds of thousands of dollars and
x
x
x
is the number of years of operation. He realizes his company is on the downturn and wishes to sell before he ends up in debt. [
6
6
6
pts]
\newline
a) When will Unlucky's business show the maximum profit?
\newline
P
=
−
3
t
2
+
18
t
−
4
P
+
4
−
27
=
−
3
(
t
2
−
6
t
)
P
+
4
=
−
3
t
2
+
18
t
P
−
23
=
−
3
(
t
2
−
6
t
P
+
4
=
−
3
(
t
2
−
6
t
)
→
−
6
−
7
−
3
→
i
P
=
−
3
(
t
−
3
)
2
+
23
unluchy’s boisne show the max’
vertex
=
(
3
)
23
)
Profit after
\begin{array}{ll} P=-3 t^{2}+18 t-4 & P+4-27=-3\left(t^{2}-6 t\right) \\ P+4=-3 t^{2}+18 t & P-23=-3\left(t^{2}-6 t\right. \\ P+4=-3\left(t^{2}-6 t\right) \rightarrow-6-7-3 \rightarrow i & P=-3(t-3)^{2}+23 \text { unluchy's boisne show the max' } \\ & \text { vertex }=(3) 23) \text { Profit after } \end{array}
P
=
−
3
t
2
+
18
t
−
4
P
+
4
=
−
3
t
2
+
18
t
P
+
4
=
−
3
(
t
2
−
6
t
)
→
−
6
−
7
−
3
→
i
P
+
4
−
27
=
−
3
(
t
2
−
6
t
)
P
−
23
=
−
3
(
t
2
−
6
t
P
=
−
3
(
t
−
3
)
2
+
23
unluchy’s boisne show the max’
vertex
=
(
3
)
23
)
Profit after
\newline
b) At what time will it be too late to sell his business? (When will he start losing money?)
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nat
\newline
res
\newline
He boxth
24
24
24
pupusas. Some were theese, and some mere pork.
\newline
He spent a tocal of
5136
5136
5136
.
00
00
00
.
\newline
Cheese pupusas cost
$
5.50
\$ 5.50
$5.50
each, and pork pupusas cost
56
56
56
.
00
00
00
acach.
\newline
How many of each variety did he buy?
\newline
Cheese Rupusas:
□
\square
□
I I
□
\square
□
] Patk Pupusar:
□
\square
□
-
Get tutor help
Test: Right Triangle Trigonometry
\newline
Name William Whalet Date
\qquad
\newline
Find the value of each trigonometric function. Round answers to the nearest hundredth if necessary.
\newline
1
1
1
.
\newline
sin
Z
=
\sin Z=
sin
Z
=
\newline
cos
Z
=
\cos Z=
cos
Z
=
\newline
tan
Z
=
\tan Z=
tan
Z
=
\newline
csc
Z
=
\csc Z=
csc
Z
=
\newline
sec
Z
=
\sec Z=
sec
Z
=
\newline
cot
Z
=
\cot Z=
cot
Z
=
\newline
2
2
2
.
\newline
sin
J
=
\sin J=
sin
J
=
\newline
csc
J
=
\csc J=
csc
J
=
\newline
cos
J
=
sec
J
=
\cos J=\quad \sec J=
cos
J
=
sec
J
=
\newline
sin
Z
=
\sin Z=
sin
Z
=
0
0
0
\newline
Solve for
sin
Z
=
\sin Z=
sin
Z
=
1
1
1
. Round to the nearest tenth if necessary.
\newline
3
3
3
.
\newline
6
6
6
.
\newline
4
4
4
.
\newline
5
5
5
.
\newline
8
8
8
.
Get tutor help
5
t
−
3
=
3
t
−
5
5 t-3=3 t-5
5
t
−
3
=
3
t
−
5
Get tutor help
8
8
8
of
50
50
50
\newline
Next
\newline
(
1
1
1
)
3502
3502
3502
\newline
An expression is shown that represents the change in Jake's cafeteria account balance after he bought some glant cookles that cost
x
x
x
each and he was given a credit.
\newline
−
2
3
(
12
x
−
6
)
=
[
+
⋯
+
−
…
]
-\frac{2}{3}(12 x-6)=\left[\begin{array}{c} +\cdots+ \\ -\ldots \end{array}\right]
−
3
2
(
12
x
−
6
)
=
[
+
⋯
+
−
…
]
\newline
Move a term into each blank to create an equivalent expression.
\newline
a
2
2
2
\newline
:
−
8
-8
−
8
\newline
:
−
8
x
-8 x
−
8
x
\newline
8
x
8 x
8
x
\newline
6
x
6 x
6
x
\newline
a
4
4
4
\newline
:
−
4
-4
−
4
\newline
:n
−
4
x
-4 x
−
4
x
\newline
Tems
\newline
1
1
1
Amacy
\newline
fix tamatecace
\newline
llog
\operatorname{llog}
llog
Get tutor help
5
5
5
.
3
3
3
Math XL
\newline
Find the solution to the system of equations
\newline
y
=
−
0.5
x
+
5
3
x
+
5
y
=
2
\begin{aligned} y & =-0.5 x+5 \\ 3 x+5 y & =2 \end{aligned}
y
3
x
+
5
y
=
−
0.5
x
+
5
=
2
\newline
The solution is
□
\square
□
Get tutor help
Eighth grade
\newline
GG.
8
8
8
Solve a system of equa
\newline
Solve using substitution.
\newline
x
+
y
=
16
−
8
x
+
9
y
=
8
\begin{array}{l} x+y=16 \\ -8 x+9 y=8 \end{array}
x
+
y
=
16
−
8
x
+
9
y
=
8
\newline
□
\square
□
□
\square
□
\newline
Submit
Get tutor help
nodes
=
=
=
no motion
\newline
tinodes = motion is
2
2
2
maximum
\newline
roblems:
\newline
Assume the frequency of the sound is
171
H
z
171 \mathrm{~Hz}
171
Hz
and the speed of sound is
342
m
/
s
342 \mathrm{~m} / \mathrm{s}
342
m
/
s
. If you are
5
m
5 \mathrm{~m}
5
m
from the right speaker and
11
11
11
meters from the left speaker, would you be a relatively loud or quiet spot? Explain and show your calculations.
\newline
f
=
171
H
z
v
=
342
m
/
s
\begin{array}{l} f=171 \mathrm{~Hz} \\ v=342 \mathrm{~m} / \mathrm{s} \end{array}
f
=
171
Hz
v
=
342
m
/
s
Get tutor help
For a high school dinner function for teachers and students, the math department bought
6
6
6
cases of juice and
1
1
1
case of bottled water for a total of
$
135
\$ 135
$135
. The science department bought
4
4
4
cases of juice and
2
2
2
cases of bottled water for a total of
$
110
\$ 110
$110
. How much did a case of juice cost?
\newline
Choose
1
1
1
answer:
\newline
(A)
$
12.50
\$ 12.50
$12.50
\newline
(B)
$
15.00
\$ 15.00
$15.00
\newline
(C)
$
20.00
\$ 20.00
$20.00
\newline
(D)
$
25.00
\$ 25.00
$25.00
Get tutor help
Question
M
s
\mathbf{M s}
Ms
\newline
O.
\newline
What tampers
\newline
suben thating.
\newline
z
\newline
16
+
4
\sqrt{16+4}
16
+
4
\newline
x
+
2
\sqrt{x+2}
x
+
2
\newline
地
\newline
can
\newline
tr
\newline
+
+
+
\newline
पa
\newline
8
8
8
\newline
riandat
\newline
θ
×
\theta \times
θ
×
\newline
M. Mury cienty
\newline
alantere
\newline
t.
\newline
What tamper
\newline
e
\newline
ד
53037
53037
53037
\newline
seonchen
\newline
LYu Mogasse
\newline
Question
/
/
/
/s
\newline
-
\newline
c.
\newline
T SusMit
\newline
n
n
n
\newline
nowterter
\newline
다가.
\newline
a
\newline
6
6
6
\newline
0
0
0
\newline
8
8
8
\newline
A convenience store has
20
20
20
bottles of water. Each dyy, a supplier delivers the same number of bottles to the stora. The store does fot sell any botiles of water for
5
5
5
days and now has
110
110
110
botwles.
\newline
What is the rate of change in the store's supply of bottled water each day?
\newline
□
\square
□
Get tutor help
4
x
−
8
=
8
x
+
7
4x-8=8x+7
4
x
−
8
=
8
x
+
7
Get tutor help
Solve.
\newline
2
sin
x
cos
x
=
sin
x
2 \sin x \cos x=\sin x
2
sin
x
cos
x
=
sin
x
Get tutor help
−
3
x
−
3
y
=
3
-3x - 3y = 3
−
3
x
−
3
y
=
3
\newline
y
=
−
5
x
−
17
y = -5x - 17
y
=
−
5
x
−
17
Get tutor help
y
=
−
3
x
+
4
y=-3x+4
y
=
−
3
x
+
4
\newline
y
=
3
x
−
2
y=3x-2
y
=
3
x
−
2
Get tutor help
solve
3
x
=
2
x
+
18
3x=2x+18
3
x
=
2
x
+
18
Get tutor help
Solve for
r
r
r
.
\newline
12
−
1
5
r
=
2
r
+
1
r
=
□
\begin{array}{l} 12-\frac{1}{5} r=2 r+1 \\ r=\square \end{array}
12
−
5
1
r
=
2
r
+
1
r
=
□
Get tutor help
10
x
=
8
x
+
6
10 x=8 x+6
10
x
=
8
x
+
6
Get tutor help
Y
=
4
x
Y=4x
Y
=
4
x
y
=
2
x
+
10
y=2x+10
y
=
2
x
+
10
Get tutor help
Sharon tried to solve an equation step by step.
\newline
9
=
−
3
(
e
−
2
)
9
=
−
3
e
+
6
Step 1
15
=
3
e
Step 2
5
=
e
Step 3
\begin{array}{rr} 9=-3(e-2) & \\ 9=-3 e+6 & \text { Step 1 } \\ 15=3 e & \text { Step 2 } \\ 5=e & \text { Step 3 } \end{array}
9
=
−
3
(
e
−
2
)
9
=
−
3
e
+
6
15
=
3
e
5
=
e
Step 1
Step 2
Step 3
\newline
Find Sharon's mistake.
\newline
Choose
1
1
1
answer:
\newline
(A) Step
1
1
1
\newline
(B) Step
2
2
2
\newline
(C) Step
3
3
3
\newline
(D) Sharon did not make a mistake.
Get tutor help
3
x
−
7
=
x
+
9
3 x-7=x+9
3
x
−
7
=
x
+
9
Get tutor help
Alexander used a discount coupon for
25
%
25 \%
25%
off at his favorite clothing store. He bought
5
5
5
pairs of shoes for
x
x
x
dollars each and
1
1
1
coat for
y
y
y
dollars. Which expression represents the total amount Alexander paid after the coupon was applied?
\newline
0.25
(
5
x
+
y
)
+
(
5
x
+
y
)
0.25(5 x+y)+(5 x+y)
0.25
(
5
x
+
y
)
+
(
5
x
+
y
)
\newline
25
(
5
x
+
y
)
25(5 x+y)
25
(
5
x
+
y
)
\newline
75
(
5
x
+
y
)
75(5 x+y)
75
(
5
x
+
y
)
\newline
(
5
x
+
y
)
−
0.25
(
5
x
+
y
)
(5 x+y)-0.25(5 x+y)
(
5
x
+
y
)
−
0.25
(
5
x
+
y
)
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4
x
−
8
+
8
=
8
+
8
x
4 x-8+8=8+\frac{8}{x}
4
x
−
8
+
8
=
8
+
x
8
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