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$Zoe owns a small business selling clothing. She knows that in the last week 41 customers paid cash, 54 customers used a debit card, and 44 customers used a credit card. Based on these results, express the probability that the next customer will pay with a debit card as a fraction in simplest form. Answer:$

Zoe owns a small business selling clothing. She knows that in the last week $41$ customers paid cash, $54$ customers used a debit card, and $44$ customers used a credit card. $\newline$ Based on these results, express the probability that the next customer will pay with a debit card as a fraction in simplest form. $\newline$ Answer:

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Probability of independent and dependent events

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Q. Zoe owns a small business selling clothing. She knows that in the last week

41

customers paid cash,

54

customers used a debit card, and

44

customers used a credit card.

\newline

Based on these results, express the probability that the next customer will pay with a debit card as a fraction in simplest form.

\newline

Answer:

Calculate total customers: Determine the total number of customers from last week. $\newline$ To find the total number of customers, we add the number of customers who paid with cash, debit card, and credit card. $\newline$ Total customers = $41$ (cash) + $54$ (debit card) + $44$ (credit card) $\newline$ Total customers = $139$
Find debit card probability: Express the probability that the next customer will pay with a debit card. The probability of an event is the number of favorable outcomes divided by the total number of outcomes. In this case, the favorable outcomes are the number of customers who used a debit card, and the total number of outcomes is the total number of customers. Probability (paying with debit card) = Number of customers who used a debit card $/$ Total number of customers Probability (paying with debit card) = $\frac{54}{139}$
Simplify fraction: Simplify the fraction to its simplest form. $\newline$ The numbers $54$ and $139$ have no common factors other than $1$ , so the fraction $\frac{54}{139}$ is already in its simplest form.

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