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Zhang Lei spent $20.00\$20.00 during his last outing at the bowling alley. This included a one time shoe rental fee of $3.50\$3.50. He spent the rest of the money on bowling a number of games. If it took Zhang Lei 4545 minutes to bowl each game and he spent 22 hours and 1515 minutes bowling, how much did it cost per game.

Full solution

Q. Zhang Lei spent $20.00\$20.00 during his last outing at the bowling alley. This included a one time shoe rental fee of $3.50\$3.50. He spent the rest of the money on bowling a number of games. If it took Zhang Lei 4545 minutes to bowl each game and he spent 22 hours and 1515 minutes bowling, how much did it cost per game.
  1. Subtract shoe rental fee: First, subtract the shoe rental fee from the total amount spent to find out how much money was spent on the games alone.\newline$20.00$3.50=$16.50\$20.00 - \$3.50 = \$16.50 spent on games.
  2. Convert bowling time: Next, convert the total bowling time from hours and minutes to minutes. \newline22 hours and 1515 minutes is the same as 2×602 \times 60 minutes + 1515 minutes, which equals 135135 minutes.
  3. Divide total time: Now, divide the total time spent bowling by the time it takes to bowl one game to find out how many games he played. 135135 minutes ÷\div 4545 minutes per game = 33 games.
  4. Find cost per game: Finally, divide the total amount spent on games by the number of games to find the cost per game.$16.50÷3 games=$5.50 per game.\$16.50 \div 3 \text{ games} = \$5.50 \text{ per game}.