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Your answer should be in the form p(x)+kx1p(x)+\frac{k}{x-1} where pp is a polynomial and kk is an integer. x2+6x4x1\frac{x^2+6x-4}{x-1}

Full solution

Q. Your answer should be in the form p(x)+kx1p(x)+\frac{k}{x-1} where pp is a polynomial and kk is an integer. x2+6x4x1\frac{x^2+6x-4}{x-1}
  1. Perform Polynomial Long Division: Step 11: Perform polynomial long division on (x2+6x4)(x^2 + 6x - 4) by (x1)(x - 1). Divide the leading term of the numerator by the leading term of the denominator: x2/x=xx^2 / x = x. Multiply xx by (x1)(x - 1) to get x2xx^2 - x. Subtract (x2x)(x^2 - x) from (x2+6x4)(x^2 + 6x - 4) to get 7x47x - 4.
  2. Continue Division Process: Step 22: Continue the division process.\newlineDivide the leading term of the new expression 7x7x by xx to get 77.\newlineMultiply 77 by (x1)(x - 1) to get 7x77x - 7.\newlineSubtract (7x7)(7x - 7) from (7x4)(7x - 4) to get 33.
  3. Write Final Result: Step 33: Write the final result of the division.\newlineThe quotient from the division is x+7x + 7 and the remainder is 33.\newlineExpress the original expression as p(x)+kx1p(x) + \frac{k}{x-1} where p(x)=x+7p(x) = x + 7 and k=3k = 3.

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