Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

You roll a 66-sided die two times.\newlineWhat is the probability of rolling a number less than 44 and then rolling a 33?\newlineSimplify your answer and write it as a fraction or whole number.\newline_____

Full solution

Q. You roll a 66-sided die two times.\newlineWhat is the probability of rolling a number less than 44 and then rolling a 33?\newlineSimplify your answer and write it as a fraction or whole number.\newline_____
  1. Probability of Number < 44: The possible outcomes of rolling a 66-sided die are {1,2,3,4,5,6}\{1, 2, 3, 4, 5, 6\}. The probability of rolling a number less than 44 (which includes 11, 22, or 33) is P(Rolling a number<4)=Favorable outcomesTotal outcomes=36=12P(\text{Rolling a number} < 4) = \frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{3}{6} = \frac{1}{2}
  2. Probability of Rolling a 33: Next, we need to find the probability of rolling a 33. Since there is only one outcome that is a 33, the probability is P(Rolling a 3)=Favorable outcomesTotal outcomes=16P(\text{Rolling a 3}) = \frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{1}{6}
  3. Combined Probability of Events: Now, we need to find the combined probability of both events happening in sequence. This is found by multiplying the probabilities of each individual event. So, the probability of rolling a number less than 44 and then rolling a 33 is P(Rolling a number<4)×P(Rolling a 3)=12×16=112P(\text{Rolling a number} < 4) \times P(\text{Rolling a 3}) = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12}

More problems from Probability of independent and dependent events