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You have 8080 grams of a radioactive kind of tellurium. How much will be left after 88 months if its half-life is 22 months?\newline____ grams

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Q. You have 8080 grams of a radioactive kind of tellurium. How much will be left after 88 months if its half-life is 22 months?\newline____ grams
  1. Identify Values: Identify the values of the initial amount aa, total time tt, and half-life period hh.\newlineInitial amount aa = 8080 grams\newlineTotal time tt = 88 months\newlineHalf-life period hh = 22 months
  2. Use Half-life Formula: Use the half-life formula to determine the remaining amount of the substance after a given time.\newlineThe formula is y=a×(1/2)(t/h)y = a \times (1/2)^{(t/h)}, where yy is the remaining amount after time tt, aa is the initial amount, and hh is the half-life period.\newlineSubstitute a=80a = 80, t=8t = 8, and h=2h = 2 into the formula to get y=80×(1/2)(8/2)y = 80 \times (1/2)^{(8/2)}.
  3. Simplify Exponent: Simplify the exponent in the formula.\newlineSimplify 8/28/2 to get 44.\newlineThe formula now is y=80×(1/2)4y = 80 \times (1/2)^4.
  4. Calculate Remaining Quantity: Calculate the remaining quantity of the radioactive substance.\newliney=80×(12)4y = 80 \times (\frac{1}{2})^4\newline=80×116= 80 \times \frac{1}{16}\newline=5= 5\newlineRemaining quantity of tellurium after 88 months: 55 grams

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